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Anonymous users2024-02-07x^2-1=x^2-1^2=（x+1）（x-1）a^3-9a
a（a^2-9）
a（a+3）（a-3）
3m（2x-y）^2-3mn^2
3m[(2x-y)^2-n^2]
3m(2x-y+n)(2x-y-n) extracts the common factor first, and then decomposes it.
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Anonymous users2024-02-061、(x+1)(x-1)
2. a(a 2-9)=a(a+3)(a-3)m[(2x-y) 2-n 2]=3m(2x-y+n)(2x-y-n) These three problems all use the squared difference formula, you should remember: a 2-b 2=(a+b)(a-b).
In addition, if you see that two items have the same factors, you should bring them up.
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Anonymous users2024-02-05One day, I was walking home and I stumbled upon a toy spring, and I was so happy! It's cylindrical, and there's a smiley face on it, and when you pull it off, it's gone, and it's a little black dot, and it's orange-red and very cute. Don't copy it.
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Anonymous users2024-02-04The length of this rectangle is 1 2 of the circumference of the circle, i.e. 2 r 2=, so r = 2 cm, area = r = square centimeter.
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Anonymous users2024-02-03.It is not scientific to analyze with perimeter, although the result may be the same. It should be analyzed in terms of area, where the radius r is equal to the width of the rectangle and the area is equal.
r=2, so.
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Anonymous users2024-02-02The length of the rectangle is measured in centimeters.
The radius of the circle is about centimeters.
The area of the circle is approximately s = square centimeters.
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Anonymous users2024-02-01This is actually the derivation of the area of a circle.
The length of the rectangle is only half the circumference of the circle.
So 2* r=2s=
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Anonymous users2024-01-31Several results involving the side heart are not correct.
In a triangle, there are four circles tangent to the three sides, the center of one of which is called the inner center (the intersection of the bisector of the inner angle), and the center of the other three circles is called the side center (the intersection of the bisector of the two expatriate corners and the bisector of the other inner angle).
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Anonymous users2024-01-30It is not correct to refer to a few knotted bi source fruits in the side heart. In a triangle, there are four circles tangent to all three sides, the center of one of which is called the inner (the intersection of the inner angle bisector), and the center of the remaining three circles is called the side center (the intersection of the outer angle bisector of the two dust cavities and the inner angle bisector of the other faction).
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Anonymous users2024-01-29If the inner part of the triangle coincides with the secondary center, it proves that the triangle is a regular triangle.
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Anonymous users2024-01-28It's just 5 points, one by one.
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