Math problems must be given to me by 2:50 p.m., plus 200 points if the answer is sent to me on time!

Ding gets second Xiaoqiang guesses: C is the first, B is the second, A is the third, and Ding is the fourth.

A cannot be the second, the third;

B cannot be second;

C cannot be the first, the second;

Xiaoli guessed: B got first, Ding got second, C got third, and A got fourth.

A cannot be the fourth;

B cannot be the first;

C cannot be the third;

Therefore, A has the first place.

Ding got second. B gets third.

C got fourth.

A is first, B is second, C is third, and D is fourth, because this is their order.

A:4B:1

C: 3: D: 2

Absolutely! It's a matter of logical reasoning! I learned!

A, B, C, D.

Xiaoqiang conjecture: 3rd, 2nd, 1st, 4th

Xiaoli conjectures: 4th, 1st, 3rd, 2nd

Correct Answer: 1st 3rd 4th 2nd

Looking at the relationship above, since only Ding 2 is right, according to A is not 3 or 4, so A can only be 1

C is not the first, nor the third, nor the second, so it can only be the 4th, and the B can only be the third

Satisfied? Huh,

Oma, Oa

A is the first, D is the second, B is the third, and C is the fourth.

Reason: Xiaoqiang guessed that A is the third and Xiaoli guessed that A is four, all A can only be the first and second, and now Ding is the second, so A is the first;

In the same way, C is not the first, not the third, and D is the second, so C is the fourth, and the remaining B is the third.

A, D, B, C: It's too pediatric! ~

Hypothetical method. Because only Ding has a second pair.

So. A is not 3 4

B is not 2 1

C is not 1 3

So. A is either 1 or 2

B is 3 or 4 and C is 2 or 4

As Ding is 2.

C is 4 and B is 3

A is 1, so A1, B3, C4, D2

Classmate, you have time to type in these song titles, it is better to use them to do a few questions, how about the children now, alas.

Nothing to do? Isn't there a three-day off?

How can you do it quickly?

141-2*44=53 - this means that 44 cars have 53 more wheels than 44 bicycles.

There is one more wheel for every additional tricycle, one less car than twice as many as a tricycle, and 2 more wheels for every car.

So first consider the one less car, then add a car, and the extra at this time is 53+2=55

At this time, the car is twice the number of tricycles, and the number of extra wheels is (2*2+1)=5 times the number of tricycles.

So the number of tricycles is 55 5 = 11, then the number of cars is 2 * 11-1 = 21, so bicycles = 44 - 21 - 11 = 12.

44-=12 (total formula).

Add a car, a total of 45 cars, with 145 wheels, then the car is twice as large as the tricycle, and the number of tricycles at this time is regarded as unit 1

If you look at all the cars at this time as bicycles, there should be 45 5 90 wheels, which is 145 90 55 different from the actual 145 wheels.

The 55 wheels are caused by one extra wheel for each tricycle and two more wheels for each car.

The number of extra wheels of a tricycle is exactly equal to the number of tricycles, and the number of extra wheels of a car is equal to twice the number of cars, that is, four times the number of tricycles.

Thus the number of tricycles is 55 (1 4) 11, the number of cars is 11 2 22, and the number of bicycles is 45 11 22 12.

Since one car was added in the consideration of the above problem, the number of cars is 22 1 21.

Because there are 141 wheels, a maximum of 35 cars, a maximum of 47 tricycles, a maximum of 70 bicycles, and a car is 1 less than twice that of a tricycle, then, the tricycle that meets the theme is: (141+4) (4*2+3)=13....2, i.e. 13 tricycles, 2*13-1=25 cars.

If there are 25 sedans and 13 tricycles, then there are 6 bicycles, but there are 141 wheels (151) that do not meet the wheels. According to a total of 141 wheels, the tricycle should be singular, after calculation, the maximum car is 21, the tricycle is 11, the bicycle is: (141-4*21-3*11) 2=12, and, 21+11+12=44 meets the conditions.

Give it points... Tired!

1.Use the simple method to calculate (recursive equation calculation) the following questions, and get extra points for correct answers, and the bottom is 5 points. (Use [+] for the plus sign, use [ ] for the minus sign and use [x] for the multiplication sign) Use [ ] for the division sign and use [=] for the equal sign) {If the symbol can't be spelled out, you can use "copy" of}

125x72 99x26 45x99+45

2.Add the appropriate operator symbol and parentheses between the numbers to the left of the equal sign below to make the equation hold.

Operator symbol: [+x] [ parentheses: ().

3.Work something out.

1）.How many seats does a theater have in 25 rows, with 38 seats in the first row, and 2 more seats in each row than in the front row?

25 2=(38+38+48) 25 2=1550 (pcs).

A: There are a total of 1,550 seats.

2）.138 teachers and students went to participate in theatrical performances, the bus can seat 40 people, the rent is 160 yuan, and the passenger car can sit 18 people, the rent is 90 yuan. How many car rental options can you write about? Which plan is the best deal?

1. Four large cars, 160 4 = 640 (yuan).

Two or three large cars and one small car need 160 3 + 90 = 570 (yuan).

3. Two large cars and four small cars need 160 2 + 90 4 = 680 (yuan).

Fourth, a large car, six small cars, need 160 + 90 6 = 700 (yuan).

Five or eight cars, need 90 8 = 720 (yuan).

Therefore, three large cars and one small car are the most cost-effective.

3）.In the rope skipping competition, the students of Class 4 (3) have achieved good results, if you use 600 yuan to buy a prize, please help them design a plan to buy the prize and write down the reason.

Hero fountain pen: 45 yuan Eternal fountain pen: 32 yuan l First place: 4

Two-color ballpoint pen: 5 yuan Ordinary ballpoint pen: 4 yuan l Second place: 5

Pencil case: 16 yuan Mechanical pencil sharpener: 12 yuan l Third place: 7

School bag: 8 yuan Pencil: yuan l Encouragement Award: 10

Eraser: Yuan Notebook: 3 Yuan L

This question is very tangled, you arrange it yourself... Don't do it...

Feeling: 1st Hero Fountain Pen.

2nd place Eternal Life Fountain Pen.

3rd place pencil case.

1 encouragement scholarship bag, 2 notebooks, 1 eraser.

4.Find patterns.

The odd digits are: 1 2 3 4

The even digits are: 2 4 8 16

5.Fill in the appropriate number in and the operator symbol in .

199x13= 200×13 – 1×13

20+8）x12=20×12 +8×12

106x26－26x6=（106-6）×26

1. The absolute value is not less than 0

x+1=0,2y-6=0

x=-1,y=3

2. The absolute value is not less than 0

3x-2=0,y-2=0

x=,y=2

6x-y=6*

3、∵a∵|a|=20,|b|=9

a=-20,b=±9

1、|x+1|+|2y-6|=0

So x+1=0 2y-6=0

So x=-1 y=3

2、|3x-2|+|y-2|=0

So 3x-2=0 y-2=0

So x=2 3 y=2

3、|a|=20 |b|=9

Because a, a=-20 b=9

or a = -20 b = -9

Absolute value of x+1 + absolute value of 2y-6 = 0 x= y= to have a process.

Because the number in the absolute value is 0, and the two numbers of 0 are added to 0, then both numbers are 0, so x+1=0 2y-6=0

So x=-1 y=3

The absolute value of 3x-2 + the absolute value of y-2 = 0 Find the value of 6x-y.

Since the number in the absolute value is 0, and the two numbers of 0 are added to 0, then both numbers are 0 3x-2=0 y-2=0

x=2/3 y=2

6x-y=6×2/3-2=4-2=2

Knowing that the absolute value of a is 20, the absolute value of b is 9, and a is less than b, find the value of a, b The absolute value of a is known to be 20, the absolute value of b is 9, and a is less than b, so a 0 b

So a=-20

b=9 may be a simpler step, but time is not enough, if you don't understand, continue to ask me.

If the absolute values add up to zero, then the number in the absolute value is equal to zero.

1，x+1=0 x=-1 2y-6=0 y=32,3x-2=0 x=2/3 y-2=0 y=2a

1 As the question, so x+1=0 2y-6=0 so x=-1 y=3

2 As in the first question, so x=2/3 y=2 so 6x-y=2

3 Because a< b, so a=-20 b=-9 or 9< p>