How to solve complex redox reaction trimming?

Updated on science 2024-04-05
5 answers
  1. Anonymous users2024-02-07

    1 First used: find out the valency change, the number of electron transfers, find the least common multiple.

    2 Just set one of them to 1 (preferably a compound with only one element on one side)3 It's really out of the question, write the letter coefficient for each chemical loss, and buy a copy of this book for the system of equations.

    The first chapter is devoted to redox reactions, which is very good.

  2. Anonymous users2024-02-06

    The principle of trimming for redox reactions.

    1) Principle of conservation of electrons: the total number of electrons lost by the reducing agent in the reaction is equal to the total number of electrons obtained by the oxidant.

    2) Principle of conservation of charge: if it is an ionic reaction, the total number of positive and negative charges carried by ions before and after the reaction is equal.

    3) Principle of conservation of mass: the number of atoms of each element before and after the reaction is equal.

    Trim steps: 1) A mark: indicate the valency of the elements whose valency has changed before and after the reaction.

    2) Second-class: By finding the least common multiple, the total value of valence rise and fall is equal.

    3) Three determinations: determine the stoichiometric number of oxidant and reducing agent.

    Stoichiometric number of oxidant (reducing agent) = least common multiple of the price reduction (liter) The total number of oxidant (reducing agent) price reductions (liters) in 1mol.

    4) Siping: Balance the stoichiometric numbers of other substances by observation method.

    5) Five checks: check whether the mass is conserved with charge and electrons respectively.

  3. Anonymous users2024-02-05

    ag3aso4+zn+h2so4---ag+znso4+ash3+h2o

    The best way to do this is to:

    Let the ag3aso4 coefficient be 1, then ag is 3, ash3 is 1, so if water is not considered, h2so4 is, znso4 is, zn is, the excess oxygen atom is 4, and an additional 8 HYDROGEN IS NEEDED, SO ADD 4 H2SO4, 4 ZN, 4 ZNSO4

    It is divided into integers, namely: 2AG3ASO4+11ZN+11H2SO4 - 6AG+11ZNSO4+2ASH3+8H2O

  4. Anonymous users2024-02-04

    The trimming of all redox reactions can be considered according to the characteristics and nature of redox: the total number of valence rises and falls is equal, and the total number of electron gains and losses is equal.

    Steps: Mark the price, change the column, rise and fall, etc., and observe the flat.

    Therefore, the key to the timing of the match is to correctly mark the valency of the elements, and it is easier to use some trimming techniques. ag3

    aso4zn+h2so

    4---ag+znso

    4+ash3+h

    2o.Middle. It can be seen that it is AG that has a decrease in valency

    In 3ASO4, the reduced valency of AG and AS in the whole substance is =3*(+1-0)+1*[+5-(-3)]=11, the valency of the whole substance is increased by Zn, and the increase of the valence of the whole substance is =2.

    Lifting, etc.: ag

    The coefficient of 3ASO4 is 2 and the coefficient of ZN is 11.

    The rest are balanced according to the conservation of mass, the conservation of charge (ionic reaction).

    For: 2ag3aso

    4+11zn+11h2so

    4=6ag+11znso

    4+2ash

    3+8h2o

  5. Anonymous users2024-02-03

    To be honest, what I generally see is common, and those coefficients have long been remembered, so it won't be as difficult as the trimming of the redox topic, I usually answer the questions online, I don't bother to calculate, I often use the ** chemical reaction trimming software above, this is very good, if there are some too difficult, it can't be made by using conventional methods, you can also use this ......

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