How do you trim a chemical reaction with the conservation of charge method?

Can the charge conservation be balanced?

To be honest I haven't heard of it... At most, the conservation of charge is only a method used to test whether an ion reaction formula is matched correctly, if it is a reaction, the molecular formula is written without ions, and the left and right electrical properties are 0 How to "conservation of charge".

The method of balancing equations is generally balanced by the conservation of elements and the conservation of electron transfer.

Does it refer to the conservation of electron transfer?

Example 1: K2Cr2O7 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

2cr: +6+3, get 6e-

s: +4+6, lose 2e-

The least common multiple of 6 and 2 is 6,6 6=1,6 2=3

So: 2cr:+6+3,000,000 to get 6e-1

S: +4+6, lose 2e- 3

1k2cr2o7 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then, according to the law of conservation of mass, the residual coefficient is balanced.

1k2cr2o7 + 3so2 + 1h2so4 = 1cr2(so4)3 + 1k2so4 + 1h2o

Example 2: If it is: K2CRO4 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

cr: +6+3, get 3e-

S: +4+6, lose 2e- 3

The least common multiple of 3 and 2 is 6,6 3=2,6 2=3

So: cr:+6+3, you get 3e- 2

S: +4+6, lose 2e- 3

2k2cro4 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then, according to the law of conservation of mass, the residual coefficient is balanced.

2k2cro4 + 3so2 + 2h2so4 = 1cr2(so4)3 + 2k2so4 + 2h2o

Conservation of charge: In the electrolyte solution, the total number of negative charges carried by anions is equal to the total number of positive charges carried by cations, and the solution is not electrically conducted. [Example 1] A mixture of sodium chloride, magnesium chloride and magnesium sulfate, if sodium ions are, magnesium ions.

Example 1: K2Cr2O7 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

2cr: +6+3, get 6e-

s: +4+6, lose 2e-

The multiples of the most sail dust of 6 and 2 are 6, 6 6 = 1, 6 2 = 3

So: 2cr:+6+3,000,000 to get 6e-1

S: +4+6, lose 2e- 3

1k2cr2o7 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then, according to the law of conservation of mass, the residual coefficient is balanced.

1k2cr2o7 + 3so2 + 1h2so4 = 1cr2(so4)3 + 1k2so4 + 1h2o

Example 2: If it is: K2CRO4 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

cr: +6+3, get 3e-

S: +4+6, lose 2e- 3

The least common multiple of 3 and 2 is 6,6 3=2,6 2=3

So: cr:+6+3, you get 3e- 2

S: +4+6, lose 2e- 3

2k2cro4 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then according to the law of conservation of mass, the balance number residual coefficient.

2k2cro4 + 3so2 + 2h2so4 = 1cr2(so4)3 + 2k2so4 + 2h2o

Find the least common multiple according to the same number of electrons gained and lost.

Example: KMnO4 ==K2mNO4 +MNO2 + O2Mn Electrons: +7---6 1

o Lost electrons: -2---0 2*2=4 So the least common multiple of lost electrons is 4So it's okay to prefix KMNO4 with 2.

Conservation of charge is to check whether the total amount of positive and negative charges on the left and right sides of the equation is equal after leveling the chemical equation; For example:

Trim of Na2O2+CO2--Na2CO3+O2;

The oxygen in Na2O2 can be regarded as two -1 valence oxygen, in the reaction, one of the two oxygen in a molecule of Na2O2 loses an electron, and the other gets an electron to become 0 valence, that is, it is equivalent to producing an oxygen atom, so two molecules of Na2O2 produce 1 molecule O2.

So the equation for balancing is: 2Na2O2+2CO2=2Na2CO3+O2

First, find out the elements with valence change, mark the valency, then take the least common multiple of the two changes and mark them before their respective chemical formulas, and finally make the number of atoms on both sides of the equal sign equal.

Find out the elements that change in valency and take their least common multiple.

This is just one example.

Example 1: K2Cr2O7 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

2cr: +6+3, get 6e-

s: +4+6, lose 2e-

The least common multiple of 6 and 2 is 6,6 6=1,6 2=3

So: 2cr:+6+3,000,000 to get 6e-1

S: +4+6, lose 2e- 3

1k2cr2o7 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then, according to the law of conservation of mass, the residual coefficient is balanced.

1k2cr2o7 + 3so2 + 1h2so4 = 1cr2(so4)3 + 1k2so4 + 1h2o

Example 2: If it is: K2CRO4 + SO2 + H2SO4 — CR2(SO4)3 + K2SO4 + H2O

cr: +6+3, get 3e-

S: +4+6, lose 2e- 3

The least common multiple of 3 and 2 is 6,6 3=2,6 2=3

So: cr:+6+3, you get 3e- 2

S: +4+6, lose 2e- 3

2k2cro4 + 3so2 + h2so4 — 1cr2(so4)3 + k2so4 + h2o

Then, according to the law of conservation of mass, the residual coefficient is balanced.

2k2cro4 + 3so2 + 2h2so4 = 1cr2(so4)3 + 2k2so4 + 2h2o

Chemical Equation Balancing: The equation of chemical reactions strictly adheres to the law of conservation of mass.

The trimming of the redox reaction equation is mainly on the substances with valency changes, and when these substances are balanced, then according to the conservation of elements, the balancing of substances without valence increases.

There are three substances with valency changes in this reaction: Na2O2, Na2CO3 and O2Na2O2 oxygen elements are -1 valence, one is reduced to -2 valence in Na2CO3, and one is 0 valence in O2, so the two oxygen atoms of O2 are obtained by increasing valence, so naturally there should be two oxygen atoms with reduced valency, that is, 1Molo2 will be generated at the same time as 2mol of Na2CO3, so the ratio of the amount of Na2CO3 and O2 is 2:1.

This reaction is essentially like this:

Na2O2+CO2-Na2CO3+1 2O2 adjusted.

2Na2O2+2CO2-2Na2CO3+O2 supplement: Because a CO2 molecule and an O-2 combine to form a CO3 2-, that is, CO3 2-, only one oxygen in it is a product of reduced valency, so the generation of 1Molo2 will generate 2mol of Na2CO3 at the same time.

The valency on the left and right sides of the chemical formula is the same.

To use a simple analogy: hydrogen ion + hydroxide ion = water.

The hydrogen ion valency on the left side of this chemical formula is +1

The hydroxide ion valency is -1

The two add up to zero.

Water (H2O) on the right is a chemical.

The valency is zero.

This is called conservation of charge!

When you make a chemical formula.

It is necessary to satisfy the conservation of valence.

Also meet the conservation of each element! Detailed enough!!