Speed, to the process! Be sure to have process speed!

1.First, the force analysis of the object is carried out: the object is subjected to its own gravitational force and frictional force and also has a pulling force.

So the gravity is broken down into the component mgsin that is perpendicular to the inclined plane and the pressure mgcos

Because the object moves upwards at a constant speed: f- mgsin -umgcos = 0 so f = mgsin + umgcos

2.Because f'Horizontally to the right So put f'Take the pressure f that is orthogonally decomposed into pairs of inclined planes'sin and the upward tensile force f along the inclined plane'sinθ

Then analyze and solve the force according to the method just now.

Your second question, I showed that the question is incomplete.

2) If an external force f is applied horizontally to the right on an object', to make the object along the slope of the constant velocity only show here If you want me to help you do it, can you send me the question? Thank you).

1. The downward component of gravity along the inclined plane is mgsin, the pressure on the inclined plane is mgcos, and the friction force on the inclined plane is mg cos.

So f=mgsin +mg cos

2. The component of the horizontal force f along the inclined plane is fcos, and the pressure on the inclined plane is fsin, and the friction force is (mgcos + fsin) to be constant so fcos -mgsin = (mgcos + fsin) so f=mg(1+tg) (1-tg).

1 f=mgcos +mgsin is the downward component of the inclined face plus the frictional force.

2 The magnitude of the frictional force of the object is equal to the resultant force of the downward force of the inclined side and the force f' of the horizontal direction.

Use synthetic bar yourself.

1）f=mgsinθ+μmgcosθ

2) f *cos = mgsin + mgcos + f *sin so. f = (mgsin + mgcos) (cos -sin ) Note: Both equations are equilibrium forces in the direction of the inclined plane.

In the principle of two-force equilibrium, f is a range value.

The maximum value is f = mgsin + mgcos

The minimum value f=mgsin - mgcos

f is moving upwards at a uniform speed in this range.

The second question is incomplete.

Let's take the computer as the math.