Hurry!!! How to calculate this math problem!

C=1, a(x+2) 2+bx+2+c, a(x+2) 2+bx+2+c-a=2, a(x+2) 2+bx-c=2x, a=1 2, b=-1, f(x)=1 2(x 2)-x+1, you can solve the inequality when you find m, or f(x)=1 2(x 2)-x+1 to get f'(x) = x-1, let f'(x)=2 is x=3, and then f(3)=1 2*(3 2)-3+1>=2*3+m.

Bring x=0 in.

then f(2)-f(0)=0

f(2)=f(0)=1

f(2)=1 x=2 f(4)-1=4 f(4)=3Because it is a quadratic function, the axis of symmetry is x=1, and the quadratic function formula can be written.

f(x)=a(x-1) 2-b brings x=0, x=2 into the above equation.

a-b=1 9a-b=3

then 8a=2 a=1 4 b=-3 4

f(x)=1/4(x-1)^2+3/4

Bring y=2x+m into f(x)=1 4(x-1) 2+3 4, then 2x+m=1 4(x-1) 2+3 4

Collated into m=???of the formula.

6.x=2y, x+40=, x=120, y=60. Bag A contains 120 kg of rice, and bag B contains 60 kg of rice.

7.x+y=14,2(15-y)=3[15-x-(15-y)], and the solution is x=5, y=9. Barrel A sold for 5 kilograms, and barrel B sold for 9 kilograms.

8. 4*7+4(。At least about 72 cm of packing rope is required.

9. 6000/80=75；80/6000=。1 kg of salt takes 75 kg of seawater; Kilograms of salt can be dried per kilogram of seawater.

10.Suppose the velocity of Xiao Wang is x, the velocity of Xiao Li is y, and the velocity of Xiao Zhang is z, then there is.

8/15x=(1-1/3)ab，8/15y=(1-2/5)ab，8/15z=(1-4/9)ab

x:y:z=2/3:3/5:5/9=30:27:25

Xiao Wang is the fastest, Xiao Li is second, and Xiao Zhang is the slowest.

6. Set B bag of rice as x

x+40)* x=60

A: 120 kg B: 60 kg.

Since the remaining bucket B is exactly 3 times that of bucket A, let bucket A be xx+3x=16 x=4 bucket B:12

Because the oil of barrel B is doubled from the remaining more barrel A to a part of barrel B, so barrel B is originally 12 2 = 6, and barrel A: 4 + 6 = 10

So barrel A sold: 15-10=5 Barrel B sold: 15-6=9

6. There are 120 kilograms of rice in the first bag, and 60 kilograms in one bag.

7. Barrel A was sold for 5 kilograms, and barrel B was sold for 9 kilograms.

Fill in the blank 1The equation for which the difference between 5 and x is 2 times greater than x is ((5-x)3=2x+1).

2.A workshop received x parts, planned to process 120 pieces per day, completed on schedule and actually processed 40 more pieces per day, and the result was completed 6 days ahead of schedule. The column equation is ( x 120 = x (120 + 40) + 6 ).

3.For a project, A alone does m days to complete, B can be completed 3 days later than A, and A, B cooperation can only be completed in (1 [1 m+1 (m+3)] days.

4.Xiaohong's mother deposited a bonus in the bank for a fixed period of one year, according to the bank's profit rate: the annual interest rate of regular savings for one year is 20%, and the interest tax is 20%.

After calculation, Xiaohong's mother can get 108 yuan of after-tax interest after one year, then the bonus deposited by Xiaohong's mother is ( x*(1+) yuan.

5.It is known that -32x=174 is found )

Answer the question (write down the process).

1.If xy -2x y + 3x y is the difference between x y -2x y minus another polynomial, find the other polynomial.

xy²-2x²y²+3x²y-(x²y²-2x²y)

xy²-2x²y²+3x²y-x²y²+2x²y

xy²-3x²y²+5x²y

Solution: by the meaning of the title:

For (x-2a) (x-a 2-1) <=0, there are: x1=2a, x2=a 2+1; （1）

For x 2-3 (a + 1) x + 2 (3a + 1) " = 0, there are: x1 = 3a + 1, x2 = 2; （2）

Then for Eq. (1), when a belongs to r, x2 is greater than or equal to x1, and then only the value of a needs to be discussed for (2).

If the hand is stupid a=1 3, the original formula is equal to 0 to be true, but for (x-2a)(x-a 2-1)<=0, Li Shu needs a=1, and, according to the title, there should be a=1 3, therefore, it is not true;

If the servant a>1 3, then.

x1>x2, meet the topic, should have.

2<=2a<3a+1,23a+1<=2a<2,3a+1< a 2+1<=2, the solution A is in the defined domain, and the two equations are unconditionally satisfied at the same time, and in summary, the value range of a is 1

After the encounter, the velocity ratio = 5x80%: 6x 50% = 4:3

Car A traveled 6 11 miles when it reached place B.

The time after the meeting of car B went 6 11 x 3 4 = 18 44 = 9 22

Remaining 5 11 - 9 22 = 1 22ab The distance between the two places = 20 x 22 = 440 kmIf you have any questions, you can ask them; Helpful, please adopt. Good luck with your studies.

Set the distance to 11s. The speed is 5V and 6V, respectively.

When they meet, row A is 5 seconds, and row B is 6 seconds.

The time taken by A to B is equal to the time it takes for B to reach 20 kilometers away from A: 6s (5V*6S 4V=(5S-20) 3V, 18S=20S-80, S=40. The whole journey = 40 * 11 = 440 kilometers.

AB The two places are 440 kilometers apart.

After meeting, the speed ratio of car A and car B is 4:3

Solution: Let A and B be X kilometers apart.

1/2x：4=（1/2x-40）：3.

Solution: x=320

Answer: Slightly.

AB distance is 440 km. Given the unknowns, calculated based on the proportions and known relationships.

I'm going to cry out.,I've been doing it for so long.,Finally made it.。。。 But the method is annoying.

Draw your own wheel and make up the trapezoids into a big triangle.

Do you set the upper bottom = x, the bottom of the lower bucket code = x + 2, and you can't calculate it by using the high = 7 equation?

So I'm using a similar triangle.

Principle: Upper bottom Bottom lower bottom = (height of triangle - 7) 7

Equation (50-x) 2 ( 50-x ) 2+7)=x (x+2) ends up with x=1 because the middle line = (top + bottom) 2=x+1=2

Solution: (1) 3 5 3 = 9 5 or 1 and 4 5 or Answer: B is 5.

2) Unclear title.

I guess what you're asking is if A and B sum of two numbers, if so, take a look at the solution.

A: B: A: The number A is 14, and the number B is.

The ratio of number A to number B is 5:3, if number A is 3, what is number B? The number B is.

If A and B are two numbers, what is the number of A? What is the number B? Is it the sum of the two numbers of A and B, or?

Solution: by the meaning of the title:

For (x-2a) (x-a 2-1) <=0, there are: x1=2a, x2=a 2+1; （1）

For x 2-3 (a + 1) x + 2 (3a + 1) " = 0, there are: x1 = 3a + 1, x2 = 2; （2）

Rule. For equation (1), when a belongs to r, x2 is greater than or equal to x1, and then only the value of a needs to be discussed for (2).

If a=1 3, the original formula is equal to 0 is true, but for (x-2a)(x-a 2-1)<=0, a=1 is required, and, according to the title, there should be a=1 3, therefore, it is not true;

If a>1 3, then.

x1>x2, meet the topic, should have.

2<=2a<3a+1,213a+1<=2a<2,3a+1a In the defined domain, the two formulas are unconditionally satisfied at the same time, and in summary, the value range of a is 1