Elementary School Mathematics 6th Grade Application Questions will add points!

1. Treat the clock as a circle, according to the formula for calculating the circumference of the circle: c=2 r, the length of the minute hand is the radius of the circle, then the circumference of the circle is 2*, and then from 8 o'clock to 9 o'clock, it is one-twelfth of the circumference, and the answer can be obtained by dividing by 12.

2. According to the title, the length of the square is 6 decimeters, then the radius of the circle with the largest area that can be cut out in the square is 3 decimeters (you can draw it yourself, it is obvious), and the answer can be obtained according to the formula for calculating the area of the circle.

3. If it is enclosed in a circle, the circumference of the circle is 10cm, and its area can be calculated by using the circle area formula; If it is enclosed in a square, the circumference of the square is, and the length of the square is, and the area is calculated by the formula for calculating the area of the square, and finally the size of the two is compared.

1 This is the entire circumference of the circle, go from eight to nine, and divide it by 12.

The first question, multiply by 10, from 8 o'clock to 9 o'clock is 5 small squares, a total of 60 small squares, and then multiply by 5/60. The second question is to multiply the square 9 by 3 to get the square decimeter The third question is to divide the square by 4 to get the square is to calculate the circle, divide it by 20, 20 and divide it by 2 to get 10, and the square of 10 by 100 is multiplied to get 314Finally, the area of the circle is greater than the area of the square.

1. 2×2× 2.6 2=3 (radius) 3 3 area) 3

Circle: From the question: for the circumference of the circle, then get:

Radius Area Square Row: Area: ( So the area of the circle is greater than the area of the cube.

First question: The minute hand goes exactly once from 8 o'clock to 9 o'clock is the circumference of a circle, so multiply it by 2 times 10

That is, from 8 o'clock to 9 o'clock, the distance traveled by the fingertips of the minute hand is centimeters.

The second question: to cut a maximum circle radius should be 6 decimeters, which is the length of the sides of the square, so multiply by (6 divided by 2) multiplied by (6 divided by 2).

That is, square decimeters.

Answer: Xiaowen uses a square colored paper with a side length of 6 decimeters, cut the largest circle, please calculate the area of the circle is square decimeters.

The third question: if you enclose a circle, first find the radius as centimeters.

The area is in square centimeters.

If it is enclosed in a square, the side length is centimeters.

The area is in square centimeters.

Because 314 is larger, the area that surrounds a circle is large.

Is this a 6th grade question? The clock is a fan-shaped arc length, and the central angle = 360 12 = 15°

Arc length l=n r 180=15 10 180=150 180=5 6 Take as much as you want.

(1) Analysis: It takes 30 minutes to open an opening, and it only takes ten minutes to open two openings (the amount of ** passed is equivalent to 20 minutes to open an opening).

Why does it take 30 minutes to open one opening, and 20 minutes to open two openings (equivalent to 20 minutes for one opening)?

The reason for this is the addition of 20 minutes to other tourists. That is to say, it can be concluded that after opening an opening for 10 minutes, you can put it.

It's nice to have more visitors in 20 minutes. It's exactly a 1:2 situation.

So, in the case of opening an opening for 30 minutes, 15 minutes are responsible for increasing the population, and 15 minutes are negative.

600 people were responsible. So it takes 15 minutes for 600 people to check in, 600 15 = 40 (people) per minute, and the number of increases per minute is 600 30 = 20 (people).

2) I think C is wrong, if I want to represent the ray it should be ob, oa is more appropriate, starting from an endpoint.

Open one gate, the ticket inspection speed is 600 30 = 20 (person minutes) faster than the increase rate of tourists, open two gates, the ticket inspection speed is 600 10 = 60 (person minutes) faster than the increase speed of tourists Each ticket gate may pass 60-20 = 40 (people) per minute, and the number of tourists per minute increases by 40-20 = 20 (people).

c is wrong.

Each ticket gate can pass 210 visitors per minute.

The number of visitors in line increases by 10 per minute.

The erroneous statement is d

A opens an opening, the ticket gate speed is 600 30 = 20 (person minutes) faster than the increase rate of tourists Open two gates, assuming that 600 people enter in two, each ticket gate may pass 300 10 = 30 (person minutes) faster than the increase rate of tourists per minute

The number of tourists in line increases by 30-20 = 10 (people) per minute

Set x number of tourists per minute to increase by y people.

600 + 30y = 30x 600 + 10y = 2 * 10x solution x = 40 y = 20 to choose c

1. Two engineering teams build a section of road, engineering team A first repairs a total of three-eighths, and then the two teams cooperate, if engineering team B repairs four-ninths of the total project, then how much does engineering A repair the total project? How many points more than the B engineering team? (To process).

I have repaired a total of the total project.

1 4/9 5/9

It was repaired more than the B engineering team.

5/9 4/9 1/9

2. Xiao Ming deposited 27/5 of the money in the small bank of the class. If he gives Xiaohong seven tenths of the money, the two of them will have the same amount of money. How much money did Xiaohong save? How much money did the two of them have in total? (To solve this problem with the unknown x).

Solution: Set Xiaohong to save x yuan.

x 7/10 27/5 7/10

x 7/10 47/10

x 47/10 7/10

x 4 two people coexisted a total of 4 27/5 47/5 (yuan).

2 questions. Let's say Xiaohong saved x yuan.

x+7/10=27/5-7/10

x=4 two coexisting 27 5+4=yuan.

1. Set X boxes A and box B (10-x).

8x+3(10-x)=60

x=6 10-x=10-6=4

A6, B4.

2. There are 3x medium-sized cars, 8x small cars and 12x large cars

5*8x+10*3x+15*12x=7500x=30

Medium 3x = 3 * 30 = 90

Small 8x=8*30=240

Large 12x=12*30=360

3. Set the distance of walking to the unit x minutes, and the distance is 1 x-10= x = 30

4. Distance: uphill 36km*2 (2+3+4)=8km, flat slope 36km*3 9=12km

Downhill 36km*4 9=16km

Speed uphill 4km h

Time uphill 8 4=2h

Flat slope 2h 4*5=

Downhill 2h 4*6=3h2+

8=80.

80-60) (8-3) = 4 10-4 = 6 in box b.

A: A 6, B, 4.

2. Neutral x vehicles are dismantled.

8x/3×5+10x+4x×15=7500x=90

90 8 3 = 240 90 4 = 360 A 240 for small, 90 for medium, 360 for large.

3. If it is known that the distance of running is 3 times that of walking, the ratio of running time to walking time is 1:3

The walking time for half the distance is: 10 3 (3-1) = 15 minutes 15 2 = 30 minutes.

A: It takes 30 minutes to walk every day.

36 2 9 = 8 km.

8 4 = 2 hours.

4 15 4 = 15 hours.

A: It takes 15 hours.

1. Let ax, 8x+3(10-x)=60 x=6, so a=6, b=4

2. Set medium-sized car x, then large car 4x, small car 8 3x, 8 3 * x * 5 + 10x + 15 * 4x = 7500x = 30So 30 medium cars, 120 large cars, 803 small cars, 30 minutes.

4. Uphill road 8 km, flat road 12, downhill 16

Uphill time: 2 hours, flat road, downhill 3

The full walk takes 2+ hours.

:x b:y 8x+3y=60 x+y=10 x=6 y=4

2.Small car: x Medium car: y Large car: Z

5x+10y+15z=7500 x y=8 3 yz=1:4 x=24 y=9 z=36

3.Suppose the distance to the unit is x minutes, and the distance is 1 x-10= x = 30

4.Uphill 36 (2+3+4) 2=8 Flat 36 (2+3+4) 3=12 Downhill 36 (2+3+4) 4=16

Total time (8 4) 4 (4+5+6) = hours.

1, a has (60-3*10) (8-3)=6, b has 4; 2. The ratio of small cars and medium-sized cars to large cars is 8:3:12; So 7500 (5*8+10*3+15*12)=30; Therefore, small cars, medium-sized cars and large cars are 30*8=240, 30*3=90, 30*12=360

3. The time to take half of the road is a unit, then there is, The time to walk half of the road is 10 (2-1-1 3)=15The journey takes 30 minutes.

4. The distance ratio is 2:3:4, the full name is 36 kilometers, you can know that the uphill, flat road and downhill are 8, 12, 16 kilometers long, so the uphill time is 2 hours, and then the time ratio is 4:

5:6.Know the time and 3 hours for flat and downhill roads, for a total of hours.

1. Three-quarters minus two-fifths, multiplied by six-sevenths.

Multiply by seven-eighths squared.

3. Surface area 4,

As far as percentage problems are concerned, the basic ones are generally divided into three categories:

1. Find how many percent a number is another number (including finding how many percent more [or less] one number is than another);

Divide one number by another, divide by more [or less] quantity by another number (i.e., the amount being compared).

2. Find out what percentage of a number is (including how many percent more than a number is [or less]);

Multiply a number by a percent, (multiply a number by a percent, add the number, or subtract a number by a percent).

3. If you know how many percent of a number is, find this number (including how many percent you know is more [or less] than a number, find this number).

This is the second type of inverse problem.

That's all for the basics, of course, some questions will be combined with other knowledge to become comprehensive questions, so that's another matter.

1 January plan: 256-16=2.4 million yuan, excess rate: 16 240) 100% 2 A work efficiency: 1 15 Therefore, B is 1 12-1 15 = 1 60

After 4 days of cooperation (1 15 + 1 60) 4=1 3 left 1-1 3=2 3

A needs: 2 3 1 15 = 10 days.

3 Set x yuan per flower, so 250 yuan on the first day.

250x-200x=360

50x=360

x=Liu Xiangyang Panpan.

The first question is wrong, and I wrote it in such detail, so I need extra points.

1 Answer: 16 (256-16)=

2 Answer: 10 days.

3 Answer: 1800 yuan.