Central Celestial Density? The density formula of a celestial body

Central object density = 0. Because the stars and galaxies are distributed on the surface of a small spherical universe. Since the diameter of the small universe is 100 times or 1,000 times the thickness of the surface of the small universe、-- the density of the center of the small universe = 0.

Even if the celestial body is an infinite universe, then the gap between the infinitely many small universes is a hundred or a thousand times the diameter of the small universe、-- so that the center of the celestial body has to fall above the gap of the small universe. And the interstitial density = 0, so the central object density = 0

The formula for the motion of a celestial body can be divided into two lines, the first line orbiting the central celestial body is a satellite-like formula:

gmm r 2=mv 2 r=m 2r=m(2 t) 2r, where m is the mass of the central celestial body, m is the mass of the surrounding celestial body, g - gravitational constant, and r is the radius of the orbit around the celestial body. If the radius r of the planet and the gravitational acceleration g of the planet's surface are given in the question, the ** substitution should be used. It is sometimes combined with the density formula to find the density of the central object.

Different celestial bodies have different densities. In particular, some celestial bodies have extremely high densities, such as neutron stars, etc., so they are extremely powerful.

How do you calculate the density of a central object? Written with rewards.

How do you calculate the density of a central object?

v=4 3r What does it mean, how did you get it??? Urgently, there are 2 rewards. Anonymous users

The ship has a circular orbit near the surface of a planet, so the orbital radius of the ship = the radius of the planet. Let it be r, the velocity is v, the mass of the central object is m, the mass of the spacecraft is m, and the period is t

gmm r*r=mv 2 r=m4 2r t 2 so m=4 2r 3 gt 2

and volume v=(4 3) r 3

So =m v=3 gt 2

Note: This question can be memorized as a formula, and it will be convenient to do multiple-choice fill-in-the-blank questions in the future, hehe......Note the word "near the surface", so the orbital radius of the ship = the radius of the planet.

The formula for the density of sensitive pins for a celestial body: gmm r 2 = mv 2 r. Astronomical objects, also known as stars, refer to objects in space, and more broadly they are all individuals in the universe.

The accumulation of celestial bodies, thus forming bridges, has become the object of study of various astronomical states. Celestial bodies are the real existence of space matter in the universe, and they are also the general name for various astral bodies and interstellar matter.

Density is a measure of the mass within a particular volume, density is equal to the mass of an object divided by the volume, which can be expressed by symbols, the International System of Units and the Chinese legal unit of measurement.

, the unit of density is kilograms of silver and meters3

The formula for the central natural mass cultivation amount is m=v 2r g, and the density formula is =m v. Celestial bodies refer to objects in space, and more broadly they are all individuals in the universe.

The agglomeration of celestial bodies forms the object of study of various astronomical states. Celestial bodies are the real existence of space matter in the universe, and they are also the general name for various astral bodies and interstellar matter. Artificial satellites launched by humans and operated in space.

Spacecraft, space laboratories, and interplanetary probes are called man-made objects.

The density of a celestial body can be calculated by the density formula:

m v where m is the mass of the celestial body and v is the volume of the celestial body. In this formula, it can be seen that the density is related to the mass and volume of the celestial body, so by measuring the mass and volume of the celestial body, its density can be calculated.

It is important to note that the density of a celestial body is different from the source spike density of the material on its surface, because the material on the surface of the celestial body is usually gas or dust, which is less dense, while the material inside the celestial body is denser. Therefore, the density of a celestial body is a more accurate physical quantity than the density of surface matter.

The banquet is not <>

The density formula for a celestial body is =m v=m (4 r 3).

The mass of the Earth and other celestial bodies is very large, and Newton's discovery of the law of gravitation made it possible to calculate the mass of celestial bodies.

Suppose that the mass of a celestial body is m, and there is a planet (or satellite) with mass m moving in a circle around the celestial body, the circumferential radius is r, and the period is t, since the gravitational force is the centripetal force of the star moving in a circle, there is gmm r2=4 2rm t2, from which m=4 2r (gt2) is obtained, if t and r are measured, the mass m of the celestial body can be calculated.

The density of a celestial body can be found by using the law of gravitation to determine the mass m and the radius r or diameter d of the object. i.e. =m v=m (4 r 3).

Basic celestial density formula.

m = v sphere volume formula v = 3 4x r

So m=3 4x r

4m/3πρr³

m is the mass, is the density, r is the radius, is the pi (no nonsense.

The formula for the motion of celestial bodies can be divided into two lines, the first line orbiting the central celestial body is a satellite-like formula:

gmm/r²

mv r=m r=ma=m(2 t) r, where m is the mass of the central celestial body, m is the mass of the surrounding celestial body, g - gravitational constant, and r is the radius of the orbit around the celestial body. If the radius r of the planet and the gravitational acceleration g of the planet's surface are given in the Ku's problem, the ** substitution should be used. It is sometimes combined with the density formula to find the density of the central object.

The second line is usually when an object placed at the equator rotates with the Earth: the gravitational force experienced by an object is approximately equal to gravity.

gmm r = mg, the gravitational acceleration of the planet's surface g=gm r, the gravitational acceleration at a certain height above the ground.

g‘=gm/(r+h)²。where h is the height of the object above the ground. If combined with the density formula, the density can also be found.

Therefore, knowing the gravitational force, you can find the mass of the celestial body you need to do it from the above equation, and then obtain the density of the celestial body according to the volume of the celestial body (which should be known).

Let the mass of the celestial body be m, the surface gravitational acceleration be a, and the radius be r.

Suppose there is an object on the surface with a mass of m

The law of gravitation is (gmm) r ) = mg, gm) = (gr ), m = 4 3 r times the density, so (4 3 gr times the density) r = g

Therefore, the density is (3g) (4 rg).