Cut a square with a side length of 3 cm in a rectangular piece of paper 12 cm long and 5 cm wide.

<> as shown in the figure, problem 1: the remaining area is equal to the area of the rectangle minus the area of the square, the area of the rectangle = length * width = 12*5=60 the area of the square = the square of the longer = 3*3 = 9So the area of the remaining part is 60-9=51

Question 2: <> 8.

The remaining part of the area: 12 * 5 - 3 * 3 = 51 square centimeters.

At most, it can be cut like this: 2 wide pendulums, 4 long pendulums, a total of 8 pendulums.

The remaining area is equal to the area of the rectangle minus the area of the square, the area of the rectangle = length * width = 12*5=60 the area of the square = the square of the longer = 3*3=9, so the area of the remaining part is 60-9=51.

The Law of Division:

From the high position of the dividend, first look at how many digits there are in the divisor, then try to divide the first few digits of the dividend with the divisor, and if it is smaller than the divisor, try to divide by one more digit.

Divide to the digit of the dividend, write the quotient on that digit.

The dividend expands (shrinks) n times, and the divisor does not change, and the quotient expands (shrinks) n times accordingly.

The divisor expands (shrinks) n times, and the dividend remains unchanged, and the quotient shrinks (expands) n times accordingly.

The dividend, divided by two divisors consecutively, is equal to the product of the two divisors. Sometimes simple operations can be performed depending on the nature of division. For example: 300 25 4 = 300 (25 4) divided by a number = the reciprocal of this number.

The remaining part of the area: 12 * 5 - 3 * 3 = 51 square centimeters.

At most, cut like this: 2 wide pendulums, 4 long pendulums, a total of 8 pendulums, and draw their own pictures.

The circumference of the remaining paper is: 80 cm. Analysis: The perimeter of the remaining paper, while reducing the two line segments, also adds two equal line segments.

Square circumference = side length 4

20 4 = 80 (cm).

The length of the perimeter is therefore equal to the sum of all sides of the figure

The circumference of the square:

c=4a。Formula description: a is the side length.

Example: If the side length of a square is 3cm, then the circumference c=4x2x2x3=12cm.

The circumference of a rectangle is (13+5) 2=36 (cm).

The circumference of the remaining figure is 20 4 = 80 (cm).

The circumference of the cut rectangle is 36 cm.

The remaining circumference is 80 cm.

Please see the ** I sent for the detailed calculation process.

As shown in the figure below, in a square paper reef scenic spot with a side length of 20cm, a rectangle with a length of 13cm and a width of 5cm is 13+13+5+5.

You all answered incorrectly (13+5)*2=36, 20*4=80, 80-36=44, got it?

Hello: 15 2 = 7....1

7x2=14 (pcs).

We'll be happy to answer for you.

Up to 12 small squares with an edge length of 2 cm can be cut.

You should first see how many 2 centimeters are in the length and width of the rectangle, and then multiply the number of small squares. However, it should be noted that when the length and width of the rectangle are not all multiples of the length of the sides of the square, you cannot use the "area of the rectangle and the area of the square" to find the number of cuts, because the figure cannot be densely paved.

Solution: 12 2=6

2 6 = 12 (pcs).

The nature and determination of the rectangleQuality. The two diagonal lines are equal.

The two diagonals are bisected with each other.

The two sets of opposite sides are parallel to each other.

The two sets of opposite sides are equal.

All four corners are right angles.

There are 2 axes of symmetry.

There are 4 bars in the square).

Decide. There is a parallelogram with right angles.

is rectangular. A parallelogram with equal diagonal lines is a rectangle.

A parallelogram with adjacent sides perpendicular to each other is a rectangle.

A quadrilateral with three corners that are right angles is a rectangle.

Quadrilaterals with equal diagonals and bisected from each other are rectangulars.

How many small squares with two centimeters on sides can be fried on a rectangular piece of cardboard 12 cm long and 5 cm wide? You can start with a length of 12 centimeters, then draw 6 segments, each of which is 2 centimeters long. A width of 5 cm can be divided into two sections, each segment is two centimeters long, and the remaining one centimeter is not needed.

Then you can subtract two 6 small squares, which is 12 squares.

A rectangular piece of cardboard 12 cm long and 5 cm wide can be cut up to 24 small squares with an edge length of two cm.

Because the side length of the square is 2 cm, this rectangle can accommodate 12 2 = 6 on the length and 5 2 = on the width of the whole number is 2. So a total of 6 2 = 12 squares can be cut.

According to the inscription column, it is calculated as follows:

12 2 = 6 lines.

5 2 = 2 columns. 1 cm.

6 2 = 12 pcs.

A: You can cut up to 12 small squares with an edge length of 2 cm.

The area of rectangular cardboard is 60 square centimeters, the area of small squares is 4 square centimeters, 60 4 = 15 So, up to 15 small squares can be cut.

A rectangular piece of cardboard 12 cm long and 5 cm wide. If you cut a small square with an edge length of 2cm, you can only cut 12 pieces.

The length can be placed 6 pcs.

The width can be placed by 2.

So you can put a total of 12 of them.

6x2=12

The long can be cut 12 2 = 6, and the width can be cut 5 2 = 2 more than 1 cm, so a total of 6 2 = 12 pieces.

12, the width is 5 can be cut up to two rows, the length is 12, each row can be cut 6, a total of 12.

It should be possible to cut 12 pieces, with six lengths and two widths.

The long side is 12 2 = 6, and the wide side is 5 2 = 2 and 1. The number of numbers is equal to 6*2=12.

Up to 12 small squares with an edge length of 2 cm can be cut.

15 3 = 5 strips.

7 3 = 2 ......1 cm.

5 2 10 pcs.

Up to 10 small squares with a side length of 3 cm can be cut.

15x7＝1053x3＝9

You can cut about 11 small squares.

Summary. With the help of a corner, the length and width coincide with the length of the square side.

In a square of paper with a side length of 15 cm, cut a rectangle 5 cm long and 2 cm wide, and the circumference of the remaining paper is how many centimeters.

With the help of a corner, the length and width coincide with the length of the square side.

The remaining circumference is.

15x2 ten (15a5 5) (15a2 2) 60 (cm).

A: The circumference is 60 cm.

2 4 = 8 eggplant companions.

Answer: It can be cut into 8 squares with a side length of 3 centimeters.

Summary. Kissing and expanding: Application questions can be divided into general application questions and typical application questions.

Application problems with more than two operations that do not have a specific solution rule are called general application problems. The application problems that have special quantitative relationships in the questions and can be solved with specific steps and methods are called typical application problems. The conditions and questions of the application questions form the structure of the application questions.

On a rectangular piece of paper 21 cm long and 9 cm wide, a square with a trimmed edge length of 2 cm can be cut at most.

Dear, I'm glad to answer your <>

On a rectangular piece of paper 21 cm long and 9 cm wide, a square with a cut edge length of 2 cm is cut up to 47 yo, 21 times 9 divided by 2 times 2 = , a square is a positive number. The reputation of the limbs is so bad that it can only cut 47 more in the most historical state. <>

Kissing and expanding: Application questions can be divided into general application questions and typical application questions. The application problem of more than two steps of the return masking operation without a specific solution rule is called a general application problem.

There is a special relationship between numbers and omissions, and the application problem can be solved with specific steps and methods, which is called a typical application problem. The conditions and questions of the application questions form the structure of the application questions.

Dear, I'm glad to answer for you [big file with saffron], on a rectangular piece of paper with a length of 21 cm and a width of 9 cm, cut a square with a length of 2 cm at most 47 yo, 21 times 9 divided by 2 divided by 2 =, a square is a positive number. So you can only burn up to 47 scissors. <>

Subject to this).

Kiss. I'm still writing math problems so late! ~