A few math questions, 50 points, to have a clear process

After deducting 18 ballpoint pens, there are 160 pens left, divided by 10 boxes, so there are 16 pens in each box, and each box of pencils is more than three times that of pens, which is 16 * 3 + 1 = 49;

2. Assuming that the unit price of a pencil is x, the unit price of a fountain pen is 12x, and the unit price of a ballpoint pen is 4x. So 2*12x+6*4x+18*x=33, you can get x=, so the unit price of pencil is yuan, the unit price of ballpoint pen is 2 yuan, and the unit price of fountain pen is 6 yuan.

3. If the number of small tabloids that can be placed on the small display board is x, the large display board is 4x. Therefore, 5*4x+8*x=56, you can get x=2, that is, you can put 2 tabloids on the small display board, and 8 copies can be placed on the large display board.

10 boxes of pens and 18 boxes of pencils, a total of 178 pens, each box of pencils is more than 3 times the number of pens in each box, how many pencils and pens are in each box?

Fountain pens (178-18) (10+18 3) 1025 pcs. Pencils 178-25 = 153.

The title is not clear, the numbers are problematic.

At the beginning of the school year, my mother bought 2 fountain pens, 6 ballpoint pens and 18 pencils for Xiao Ming, a total of 33 yuan, and the price of a fountain pen and 3 ballpoint pens is the same. It's the same price as 12 pencils. How much is the unit price?

Ballpoint pen 33 (6 + 3 2 + 18 12 3) 2 yuan. Fountain pen 2 3 = 6 yuan.

Pencil 6 12 = yuan.

Year 6 students produced 56 environmental tabloids to be displayed on 5 large boards and 8 small boards The number of tabloids on each board is 4 times that of small boards, and how many tabloids can be placed on each large board and small board?

Small display board 56 (8+5 4).

2 servings. Large display board 2 4 = 8 copies.

1 49 pencils and 16 fountain pens.

Number of pens per box = (178-18) 10 = 16

Number of pencils per box = 16 * 3 + 1 = 49

2 pencil yuan, fountain pen 6 yuan, ballpoint pen 2 yuan.

The unit price of pencil, fountain pen and ballpoint pen is x, y, z2y + 6z + 18x = 33 respectively

y=3z=12x

Just solve it.

3 Large display boards can hold 8 tabloids and small display boards can hold 2 tabloids.

Set up a large display board and a small display board to put x and y tabloids respectively.

5x+8y=56

x=4y.

If you still have questions, you can continue to ask, I hope it can help you, and I wish you progress in your studies!

Question 1: Solution, set up x pencils per box and y pens per box.

10y+18=178

x-3y=1

The solution is {x=49

y=16 Question 2: Solve the pen x, the ballpoint pen y, and the pencil z.

2x+6y+18z=33

x-3y=0

x-12z=0

Solution: {x=6

y=2z=Question 3: Solve the problem that x copies of tabloids can be placed on the large display board, and y copies of tabloids can be placed on the small display board.

5x+8y=56

x-4y=0

The solution yields {x=8y=2

If each box of pens has x, then each box of pencils has 3x+1, according to the title:

18+10x=178

10x=160

x=16, so the pencil is 16*3+1=49 boxes of pens and 16 pens.

Let each pen be $ x then each ballpoint pen is $1 3x and each pencil is $1 12 x according to the title

2x+6*1 3x+18*1 12x=33x=6, so 6 yuan per pen, 2 yuan per ballpoint pen, and 2 yuan per pencil.

Set up a small display board to put x blocks, then a large display board can put 4x according to the theme:

5*4x+8x=56

28x=56

x=2, so you can put 2 on the small display board, and 8 on the big board.

Pencils per box = 16 * 3 + 1 = 49 pcs.

pens per box = (178-18) 10 = 16 pens.

Pencil = 33 (18 + 2 * 12 + 6 3 * 12) = 33 62 yuan fountain pen = 33 62 * 12 = 198 31 yuan ballpoint pen = 66 31 yuan.

Display board = 56 (8+4*5)*=2 tabloids.

Large display board = 2 * 4 = 8 tabloids.

It consists of 10 boxes of pens and 18 ballpoint pens, a total of 178 pieces.

10 boxes of pens for 178-18 = 160 pens.

So each box of pens is 160 10 = 16.

It is obtained by 3 times more pencils per box than the number of pens in each box.

Each box of pencils is 16x3+1=49 pieces.

Note: The 18 ballpoint pens don't seem to have much to do with the question, is it wrong?

Ballpoint pen 33 (6 + 3 2 + 18 12 3) 2 yuan. Fountain pen 2 3 = 6 yuan.

Pencil 6 12 = yuan.

Small display board 56 (8+5 4).

2 servings. Large display board 2 4 = 8 copies.

178-18 = 160 pcs, 160 10 = 16 pcs, 16 * 3 + 1 = 49 pencils per box, 49 pens each, 16 pcs.

Set up in a small display board to put x copies of tabloids. From the title: 8x+20x=56 so x=2

Answer; Each large and small display board can be placed on 8 and 2 respectively

At first, I wanted to use the counter-proof method to do the first question, but then I found a logical loophole, there is a negative proposition that the sum of all parts of the circular arrangement is greater than 0, that is, there is no circular arrangement and the sum of all parts is greater than 0, that is to say, all.

:(65/6)= 21%(x-5)=7*9

4*(6/65)=x*(1/ x-5=7*9/21%

x=4*(6/65)* x-5=300

x=12/5 x=305 x=2

2.Square du

体zhi cuboid cube.

3.Preceding. DAO version of the latter item ratio weight.

Solution: Suppose the number of people who scored 3 goals is A, and the number of people who scored 4 goals is B, then;

It can be seen from "the average number of goals scored by people who score 3 or more goals".

3a 4b 5 2 , simplified to : a b 6;

It can be seen from "the average number of goals scored by people who score 4 or fewer goals":

0 1 1 2 2 7 3a 4b, simplified to : a 3b 18;

Synthesis, two formulas, solution: a 9, b 3;

So, the number of people who scored 3 goals and 4 goals were 9 and 3 respectively.

Set up x people who score 3 goals and y people who score 4 goals.

3x+4y+5*2)/(x+y+2)=

6x+8y+20=7x+7y+14 ->y-x=-6(1*2+2*7+3x+4y)/(1+2+7+x+y)=32+6x+8y=50+5x+5y ->x+3y=18+：4y=12

y=3x=9

1. Set the original x grain, x-2 5x-4=41 x-2 5x=45 3 5x=45 x=75,

2 ，30x=20 x=20/30=2/33,4n+2 2/5=4 4n=4-14/5 4n=80/20-56/20 4n=6/5 n=3/10

4. Let each piece be x yuan, 3x+25=40 3x=15 x=515=3b b=5

Landlord elementary school student?

1: Let there be a total of x, according to the meaning of the question: x multiplied by 3/5 minus 4 equals 41 to get x=65

2: x = 2/3

3: n = 2/5

4: Let each x-yuan have: 3x+25=10 multiplied by 4 to get x=55:b=5

Absolutely.

1.There are a total of x sugars.

3/5x=41+4

x=45*(3/5)

x = 75 and 2/5 equals 12/5

Divide both sides of the equation by 4 at the same time

n+3/5=1

n=2/54.Set the value of the cash coupon x

3x+25=4*10

3x=15x=15b=5

1. Set up the original candy x grains.

According to the inscription, the equation is:

3/5)*x-4=41

Solution x=752, x=2 3

3、n=2/5

4. The value of each cash coupon is X yuan.

According to the question of the equation, the following is obtained

3*x+25=10*4

The solution is x=55 and b=5

1.Set the original candy x pieces. 3/5 x = 41 + 4x = 75

2。x = 2/3.

3。x = 2/5

4。Let the value of a cash coupon be x.

3x+25=10x4x=

1.6x=450 gives x=752 x=2/3

3.2 and 5 points 2 is equal to 4n+ 4n= to get n=43x+25=4 multiplied by 10 3x=40-25=15x=5

5. 15=3b b=5

1.Let it be that there are x grains.

x*3/5-4=41 x=75

2. x=2/3

4.Set a chapter of cash coupons for $x.

3*x+25=4*10x=

1.Equipped with x grains. 3|5x-4=41 launch x=752 x=2|3

3. n=2|5

4.Set value x 3x+25=40 launch x=55 b=5

1,75

2.Three-two.

3, two-fifths.

Solution x=5

Question 1 3 5x—4=41 x=75

Question 2 x=2 3

Question 3 n=2 5

Question 4: 3x+25=10*4 x=65 3, and question 5: b=5

This question is so "difficult", ah......to solve the ......

A certain engineering team repaired a road, repaired 38 meters on the first day, repaired 42 meters on the second day, and repaired 1/56th of the total length of the road on the second day than on the first day, how many meters is the total length of this road?

224 meters. A and B are 300 kilometers apart, the fast train and the slow train start from A and B respectively, and after 3 hours the two cars meet, the speed of the slow train is 2/3 of that of the fast train, and how many kilometers does the fast train travel per hour?

300 3 100 km.

100 (1+2 3)=60 km.

Wait a minute, I'm doing it.

1.(42-38)*56=224 is the total length of the highway 2If the fast train travels 3x per hour, then the slow train travels 2x per hour, so there is (2x 3x)*3=300

Get x=20That is, the express train travels 60 kilometers per hour3According to the title, A completes 20 1 per day, and B completes 30 1 per day

Then the cooperation of A and B can be completed every day (20 1 30 1) = 12 1 and according to the meaning of the topic, B can be set to call up n days, then the following equation holds n 20=1Thus solving n=15

3.Let a chair be m, then there is a table m12 and the equation can be obtained as follows.

5m = 3 (m 12) can get m equal to 18 then a set of tables and chairs ** will also come out, m m 12 = 48

Personally, I don't need to say more about typing on my phone, the landlord should understand what I mean.

Solution: The second day was more repaired than the first day:

42 - 38 = 4 (meters).

The full length of the road:

80 3 (m).

Solution: If the speed of the fast train is x kilometers per hour, then the speed of the slow train is 2 3 x kilometers per hour 3 (x + 2 3x) = 300

x+2/3x=100

5/3x=100

x=60A: The express train travels 60 kilometers per hour.

42-38 = 4m, 4 (1 56) = 224m, the total length of 224m is set to be fast speed x, then the slow speed is (2 3) x, 3x + 3 * (2 3) x = 300, x = 60 km h.

If the total amount of work is 1,18-1 (1 20 + 1 30) = 6 (days) and the unit price of the table is x, then the unit price of the chair is (3 5) x, x-12 = (3 5) x, x = 30, then (3 5) x = 18, 18 + 30 = 48 (yuan).

25*20*40*40 divided by 10000

80 square meters.

On a scale of 1:40, the foundation of a house is 25 cm long and 20 cm wide, and the actual area of this foundation is (80) square meters.