Two candles of different thickness and the same length, see the supplement Good additional 100 fortu

When the length is the same, the coarse candle burns 4 to 3 times longer than the thin candle.

When the length of a long candle is 2 times that of a thin candle, the burn time is 4 3 2 = 8 3 times that of a thin candle.

The difference in burning time between the two candles remains the same, which is 4-3 = 1 hour.

The remainder of the thin candle can be burned: 1 (8 3-1) = hours.

Burning time: hours = 2 hours and 24 minutes.

Lighting time: 4:00-2:24=1:36

It was lit at the same time at 1:36 p.m.

Let the length be x, then their hourly burning rate is respectively.

x 3 and x 4, set the elapsed time t hour to 4 o'clock.

So. 2(x-tx/3)=x-tx/4

Solution t=12 5

That's t = 2 hours and 24 minutes.

So the original time was 1:36.

Analysis: Think of the total length of the candle as 1, the burning rate of a thin candle is 1 3, and the burning rate of a coarse candle is 1 4.

Solution: Suppose that the remaining part of one candle is twice as long as the remaining part of the other candle when it burns for x hours.

1-1/3x）×2=1-1/4x

2-2/3x=1-1/4x

x=12/5

Push forward 2 hours and 24 minutes from 4 p.m.

A: Two candles should be lit at 1:36 p.m.

2(1-1/3x)=(1-1/4x)

x=t=so candles should be lit at 2:06 p.m. (at the same time).

Two and six o'clock.

Let the time be x1-4 x divided by 1-3 x=2 to calculate the required hours, that is, two hours and 24 minutes, and subtract 4:30 minutes to calculate it.

Set the power outage for x hours, and the length of the thick candle is y

The thin candle has 2y(1-x) 1 left

The coarse candle is left with y(3-x) 3

2y(1-x)=y(3-x)

x = 3 5 so the power went out for 3 5 hours, i.e. 36 minutes.

Wrong is 2 3. Belch.. Then don't show off if you don't have a level.

It's 40 minutes.

There's an option for this question...

It can be done with elimination.

My answer is 40 minutes.

Reason: This problem can be simplified and abstracted into the solution of the chase and encounter problem: let the length of the thin candle be 1 and the length of the coarse candle is.

v coarse, 2v fine, 2v coarse, s coarse, v, fine s, coarse, s, 4, respectively, the speed is 1 hour and hour, that is, 40 minutes.

The consumption rate of fine is 4 times that of coarse.

2-4x=1-x x=1/3

1 3 *2= 2 3 hours.

Let the length of the coarse candle be h, then the length of the thin candle is 2h, then the length of the thin candle burning per hour is 2h, and the length of the coarse candle burning per hour is h 2, and the power outage has been stopped for x hours, then the equation is obtained: h-hx 2=2h-2hx

Solution x = 2 for 3 h.

If the original length of the coarse candle is a and the remaining length is x, then the time of the thin candle is (2a-x) 2a *1

Time for long candles (a-x) a *2

Because the duration is equal, (a-x) a *2 = (2a-x) 2a *1

4a-4x = 2a -x

x=2a/3

So duration = (2a-x) 2a *1 = 2 3 hours.

The two candles are of different thicknesses and lengths, with the longer one burning for four hours and the shorter one burning for six hours. Light them at the same time, and after three hours, the remaining length of the two candles is equal, and the ratio of the shorter to the longer candle length is.

Is this the problem, does it have anything to do with physics, elementary school math?

Untie; Let the short length be x and the long length be y, then the short burning speed is x 6 and the long speed is y 4

Then according to the remaining length is equal after 3 hours of combustion, the equation can be listed:

x-x/6*3=y-y/4*3

x*1/2=y*1/4

x/2=y/4

x：y=1/4：1/2=1：2

A: The ratio of the length of the shorter to the longer candle is 1:2

I advise the heavenly prince to be vigorous and reduce talents without sticking to one pattern. 93, Guan Ju.

Let the length of the thin candle be two, then the length of the coarse candle is one, and let x hours have passed according to the title, if the length is the same, the thin candle is four times faster than the coarse candle 2-x=1-quarters x

x = four-thirds.

Let the length of the energy burn 3 small lifting time be x, the length of 5 hours is y, and after two hours the equal length, one is left x 3, the other is left 3y 5, there is x hitting the rock 3=3y noisy 5, there is: z y=9 5