Mathematics, nine on, proof, calculations about trapezoids

Updated on educate 2024-04-08
10 answers
  1. Anonymous users2024-02-07

    Passing the point D is made of DG, and the vertical BC is crossed with G. Then the triangle BEF is similar to the triangle chain ascending GDC and gc=4-1=3=dg=ab=2eb. So EB = 3/2. Then from the Pythagorean shed scattered old slag digging theory, EF = 3/2 of the number 2

  2. Anonymous users2024-02-06

    Pythagorean theorem.

    1.If the leak is ab on the side, the height will always be bc

    Then the triangle area is 10x10 2=10

    2.Take BC as one side. Then be=15, bc=10, using the Pythagorean theorem to obtain ce=root number 125Only socks, i.e., 5 roots, 5 three-finger liquids, with an area of 10x5, 5 roots, 5 2 = 25, 5 roots, 5 <>

  3. Anonymous users2024-02-05

    Because ABC is an isosceles ladder sedan deformed, angle b = angle trembling c, as df ab, then the closed angle c = angle dfc, ab = df = cd = 6, ad = bf = 5, cf = bc-bf = bc-ad = 3

    So the circumference of the triangle is 6+6+3=15

  4. Anonymous users2024-02-04

    As AE DC, the angle c=70°, so the angle AEB=70°

    In AEB, the angle b=55°, so the angle EAB=55°, equiangular to the equiside, AE=BE=5

    So dc=ae=5

  5. Anonymous users2024-02-03

    In the isosceles coarse reed trapezoidal ABCD, bending delay a= d, c = bad bc

    Rock belt c + d = 180

    then c+ a=180

  6. Anonymous users2024-02-02

    Because AD is parallel to BC angle ACB = angle DAC

    And the angle b = the angle AED, so the triangle ABC is similar to the ADE.

    And because of the pretense ab=3 bc=4, so ac=5

    By the source of the lack of Chang in the similar AD than AC and hail de than AB equal. de=

  7. Anonymous users2024-02-01

    ∠b=90º

    ac= (ab +bc )=3 +4 wreckage) = 5 abc area = ab bc 2=3 4 2=6 trapezoidal area = (ad+bc) ab 2=(2+4) 3 2=9 adc area = trapezoidal area - abc area = 9-6=3de acde ac 2=3

    i.e.: de 5 2 = 3

    de=6/5

    ac*de=ad*ab means that the area of the triangle with the same base is equal.

  8. Anonymous users2024-01-31

    The area of the ADC can be based on AC, and DE can be the height on the edge of AC; You can also use AD as the bottom, and AB is the height on the side of AD.

  9. Anonymous users2024-01-30

    1 2ac*de=1 2ad*ab are all areas of a triangular acd, so ac*de=ad*ab

  10. Anonymous users2024-01-29

    <> do and bury de bc to hand over bc to e

    de=ab=ad=be=1

    ec = cd -de = 3 -1 = 2 2 trapezoidal ABCD full area.

    1+1+2 2 *1 2=1+ first 2

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