Reward for a high level of chemical substance concentration question

You are right. 1 BA (NO3)2 contains 1 cation (BA2+) and 2 anions (NO3-), and the total number of anions and cations is 3

Then 2*ba(NO3)2 should contain 3* anions and cations.

I guess that's what you calculated, I think that's it, there should be no problem.

Believe in yourself, you are right.

Because the solution contains barium nitrate, the cation is barium ion, and the anion is nitrate, because the solution is electrically neutral, therefore, each anion and cation cancel each other, and each cation and each anion cancels out, so the total number of ions in the solution is.

I don't know if you understand that.

It can also be understood in this way: there is a sum phase canceling out in the solution, so it is.

You are right.

1) First of all, to help you understand, write the ionization equation ba(no3)2=ionization=ba2+ +2no3-

2) Calculate the amount of barium nitrate in a barium nitrate solution with a volume of 2 l.

n ba（no3）2=cv=

As can be seen from the ionization equation, a molecule of barium nitrate produces 3 ions.

So barium nitrate, ionized; Number of ions =

So the total number of anions and cations is.

Set the volume of the bottle, and the mixed gas of HCL and N2 is 1mol, where HCl is X mol and N2 is Y mol

x+y=1, we get x=, y=

Nitrogen is poorly soluble in water, so HCl is soluble in water, and the concentration of the amount of substances in the solution can be obtained 1, which is the answer B.

There is also a solution to the standard condition of the gas, there is x mol dissolved in water, there is mol of water mixed with it, the volume of the solution l, the concentration of the amount of the substance of the solution x, this problem does not need to calculate the specific gas content, hehe, the analysis is clear, so that the efficiency can be improved.

Because nitrogen is insoluble in water, HCl dissolves, so the dissolved gas is replenished by water, and the nitrogen does not overflow the bottle and does not dissolve away. In there, hehe.

Well. You should know that there is a method called the cross method.

Crossing, that is, the ratio of the amount of HCl to N2 substance.

28 cross, which is the relative molecular mass of HCl, and 28 is the relative molecular mass of N2) has a ratio of 4:1

Hcl 4mol, N2 1mol

HCl is highly soluble in water, so what remains is N2, indicating that there is 4* water in the tube.

In this way, the amount concentration of the substance is 4mol

There should be a lot of counseling books on it, and it is recommended that you go and buy counseling books.

Because the original solution is saturated, after evaporating the solvent, the crystals will be precipitated, and after returning to the original temperature, the evaporated solution is still a saturated solution, so the concentration of the substance is still the same as when it was saturated.

When the water evaporates, KCL precipitates. The temperature is constant, the solubility of KCl is constant, so the concentration of the saturated solution is also constant.

All of the above is very correct, for the sake of understanding, it is suggested that the precipitated KCl is not counted in the solution.

Add to 20ml, the white precipitate no longer increases, indicating that the sulfuric acid is completely reacted, and when added to 60ml, the pH value of the solution is exactly equal to 7, indicating that the H+ is completely reacted, then the 40ml added later is to neutralize hydrochloric acid.

ba(oh)2———h2so4———baso41mol 1mol 233

c1· mba(oh)2———2hcl

1mol 2mol

c2·40ml

Solution: m c1 c2

The amount of a substance of barium sulphate is , and its mass is.

The amount of the sulfuric acid substance and the amount of the barium sulfate substance are equal to. Therefore, its concentration is from the consumption of 60ml of barium hydroxide, and the H ions contained in the solution are 60* hydrogen ions ionized by hydrochloric acid, that is, the concentration of hydrochloric acid is.

The amount of substance in solution Ba(OH)2 is.

The amount of Ba2+ substance is.

223g/mol*

2.The amount of substance obtained from 1 of the SO4 root is provided by sulfuric acid and H+ is 60 ml of Ba(OH)2 solution contained.

When added to 60ml, the pH of the solution is exactly equal to 7 i.e. H+ is provided by hydrochloric acid.

So sulfuric acid has hydrochloric acid.

The concentration of the amount of the substance is MLO L

Probably right!

88 (88-88)=8 8 The mass of the original solution is 811 8 8=888g The concentration of the amount of the substance of the original solution is 8111 888 88% 88 881=