Chemistry asks for the quantity and concentration of a substance

The trivalent aluminum ions in VML of Al2(SO4)3 are A 27mol, SO42- is A 18mol, and the SO42- in V 4ml solution is A 72mol, and the amount of the substance diluted to 4 VML SO42- is a (288*V) mol mL, or 125A 36V mol L

dAnalysis.

A: It must be completely dissolved.

b: Standard atmospheric pressure is not stated.

C: The volume after mixing concentrated hydrochloric acid and water together is not 10 liters because of the different densities.

The amount concentration of the substance = the molar mass of the substance and the total volume of the mixed solution.

Then d is the amount of 10gnaoh of the substance divided by volume.

Amount of aluminium substance: a 27

Amount of sulfate substance: 3a (27*2).

The amount of sulfate after taking a quarter: 3a (27*2*4)The concentration of sulfate: (3a (27*2*4)) 4Simplification is a 18

The final answer on the fourth floor is unit conversion; Mol ML*1000ml L becomes mol L

a/(27*2)]*3/（4*4v）

Simplification: A (288*v) unit mol ml

The last step upstairs is a fool's errand.

Solution: The gas generated is.

H2 The amount of the allergenic substance of H2 is prudent.

n(h2)=v/

2na+2h2o=2naoh+h2↑

x yx=2×

y=2 The amount of the substance of the metal sodium that has not been oxidized is.

x=so its mass is.

m(na)=nm=

The mass of sodium oxide is.

The amount of GNA2O substance is:

n(na2o)=

molna2o+h2o=2naoh

generated. The amount of substance of NAOH is.

The amount of substance that is concealed in the mol width to the resulting solution is.

n(naoh)=

The amount of the substance of y+NaOH concentration c(NaOH)=

n(naoh)/v=

Solution ideas: 1. When the oxidized metal sodium is put into water, the reaction between sodium and water will produce gas, and the reaction between sodium oxide and water will produce no gas. So there are two reaction equations involved, 2, the amount of gas that is converted into matter under standard conditions.

3. Calculate the mass of sodium according to the gas.

4. The total mass of sodium oxide and sodium and the mass of sodium obtained in the migration step are conserved by the elements to obtain the concentration of the substance in the solution.

This question mainly tests the equation of the reaction between sodium and sodium oxide and water, the conversion relationship between the quantity and volume of a substance under standard conditions, the calculation of the accompanying mass of a certain element in a mixture, and the calculation formula of the quantity concentration of a substance.

The amount of the substance of the vl gas is.

The mass of v mol gas is.

The quality of the mv solution is.

100+mv/

The volume of the solution is.

100+mv/

The solution is the amount of the substance, and the concentration is.

c=1000 (v choose b.)

1.3:2:1 Because the concentration of OH- ions in the NaOH solution is, H+ is ionized in the three acids.

The sub-concentration should also be. And because the concentration is the same, the volume is inversely proportional to the stoichiometric number, so, 3:2:1.

3.Mass percentage: ammonia mass: 560l The mass of the resulting solution = = 1000g (1L of water) + 425g = = 1425g, so the mass percentage concentration = = 425g 1425g * 100% = = approx.).

The amount and concentration of the substance: 560L ammonia = 25mol under standard conditions, the volume of the solution = = 1425g, and the amount concentration of the substance = = 25mol is also approximate).

To neutralize the same volume of NaOH solution, a volume ratio of hydrochloric acid, sulfuric acid, and phosphoric acid solution is required to be 6:3:2

Mix 500ml of 4mol L H2SO4 with 800ml of 2mol L H2SO4 solution, and the total volume of the mixture is, then the concentration of the amount of substances in this mixture is: (

The amount of substances in ammonia solution is 560

The mass of ammonia is 25x17 = 425 grams.

So the mass percentage concentration of the ammonia solution is.

The volume of ammonia solution is: (425+1000).

So the concentration of the amount of the substance is 25

3.Mass percentage concentrations are; The amount of concentration of the substance.

The amount of the total sulfuric acid substance is unchanged.

v=200

n=c*v=

The mass of copper sulphate m = n * m =

Use a tray balance to weigh copper sulfate and follow the general solution configuration steps to do it.

Please refer to...

The quality of copper sulfate is 500ml

4/40/1=

Take out 10ml, then the amount and concentration of the substance will not change.

4gnaoh combined with mol (40gnaoh is 1mol), dissolved in 10ml of water, the amount concentration of the substance is, diluted to 1l, the amount concentration of the substance is, 10ml is removed, the amount concentration of the substance remains unchanged.