6th grade practical problems, math masters, please come in, online, etc

1. Solution: Because A: B = 3:4, so A = 3 4 B; And because B: C = 5:7, C = 7 5B.

According to the topic: A + B + C = C + 21000, that is: 3 4 B + B = 21000, B = 12000, C = 7 5 B = 16800, total sales = C + 21000 = 16800 + 21000 = 37800 (yuan).

2. Solution: Let the total number of parts be x, according to the problem to get 25%x+90=40%x, and solve x=600 (pieces).

3. Solution: taxable = 86500 * 14% - 3120 = 8990 (yuan).

1: Last week's ratio was 15:20:28

78,380* yuan.

The third question is like this, if you don't understand the meaning of the question.

1. Let A, B, and C be ABC respectively

a:b=3:4

b:c=5:7

a+b+c-c=21000

Therefore, a=9000 b=12000 c=168002 set parts x.

x=600Is there a problem with the semantics of the third question?

1. Set the sales volume of store A to be 3x, then store B is 4x, store C is 28x 5, and the solution is 3x + 4x + 28x 5-28x 5 = 21000 x = 3000, so 3x + 4x + 28x 5 = 63 * 3000 5 = 378002, and there are x parts for the set.

Then 40%x-25%x=90 gives x=600

Produce a batch of parts, complete his 25 on the first day, and complete his 40 on the second day, if the first day is 90 less than the second day, how many parts are in this batch? 40%-25%=15% 90 divided by 15%=600

Divide by (40% minus 5/11) = original trees 2, (divide by a few percent of the time shortened.)

Divide by 2 = 90 90 + 10 = 100 (100-80) divided by 100 = a few percent less than Class A.

1/1 = 80% of the remaining The next day is 1/8 of the total 270 divided by (1-1/2 1-1/8) = how many sets of 6,

1. Set up x trees in total.

40％x＋50÷﹙x＋50﹚＝5／11

x 500 trees.

A: Originally, there were 500 trees.

2. ( is " " instead of " ".

A: The time is shortened approx.

3. 20% of two more copies of A than B: 20% 2=40% 100% of A B is 100%-40%=60% of A

Then A: B = 100%: 60% = 5:3

Answer: The ratio of A to B is 5:3

2 = 90 copies B: 90-10 = 80 copies A: 90 + 10 = 100 copies.

It turned out that Class B was 20% less than Class A.

5. Set the second day and the third day to make x sets.

270＋x﹚÷2＝80％x

135+50%x-50%x=80%x-50%xx＝650

A: A total of 650 sets were made on the second and third days.

6. (Same as Question 1) Set up x trees in common.

40％x＋50÷﹙x＋50﹚＝5／11

x 500 trees.

A: Originally, there were 500 trees.

7. Set up armor repair XM

25％x÷20％＋x＝108

x 48 meters.

108-48=60m

A: Team A repairs 48 meters, Team B repairs 60 meters.

8. Analysis: Suppose all 20 questions are done correctly: 20 5 = 100 points.

If you make a mistake, you will lose 5 + 3 = 8 points.

Do not do 5 points minus.

The column formula is as follows: (20 5-69) (5+3)=3131=2 8+5 3

A: She didn't do 3 questions.

9. Solution: If there are x rabbits, then there are 11 + x chickens.

4x＋（11+x）×2＝94

4x+22+2x=94

x=1211+12=22.

A: There are 22 chickens and 12 rabbits.

10. If there are x chickens, then there are 100-x rabbits.

100-x）*4=2*x+28

400-4x=2x+28

6x=372

x=62100-62=38 (only).

A: There are 62 chickens and 38 rabbits.

1.Set up a total of x trees.

40％x＋50÷﹙x＋50﹚＝5／11

x 500 trees There were originally 500 trees.

2.The time is shortened.

5.Set the second day and the third day to do a total of x sets.

270＋x﹚÷2＝80％x

x 650 sets.

6.Done. 7.Let the armor be x

25％x÷20％＋x＝108

x 48m Team A 48m, Team B 60m.

Give it to you again if needed.

1 has 2（

3.Let A be x, B be y, x-20%x=y+20%x

Simplification yields y=60%x

The ratio of A to B is 10:6 =5:3

4.Let A be x, then B is (x-20).

x+(x-20）=180

x=100, B is 80

Less (100-80) 100=20%.

5.Let the total be x

270 + 20% * (x-270) + 50% x = xx = 720, do 720-270 = 450 sets on the second and third days.

Of the eleven branches and five, 5 are ashamed trees and the other 6 are other trees, = 60% of 6040% of 110 = 6/10 of other trees = 66/110 difference = 50.

50 divided by 6 times 100

Divide by (13 seconds.)

It's all simple!!

There is no sub-gang to do a problem, 1) set the original locust tree x, and the total number of original trees is one.

Then: (x+50) (

x=200, the original total number of trees is 500.

10.Set rabbit x and chicken y. x+y=100,,,4x-2y=28,,,x=38,,,y=62 9.Same as above, y-x=11,,,4x+2y=94,,,x=12,,,y=23

Divide by (11 5-40%) = 500 (trees).

2.(13 seconds 9 - 12 seconds 88) divided by 13 seconds 9

3.(1+20%)*2= divided by 2= :1=7:54

Length and width are. 16 (1, 3, 8) 10 (dm).

To make such a pair of tanks, at least iron sheets.

10 10 (10 16 10 16) 2] 2 1480 (square decimeter).

Solution: length = width = 16 * (1-3 8) = 16 * 5 8 = 10 decimeters.

Because there is no cover, s=10*10+10*16*4=100+640=740

2s = 740 * 2 = 1480 square decimeters.

The first solution should be to increase the base area by multiplying by 2=

Solve the second problem by dividing 6= is the base area and then use 16* =

This question is ok; It's here.

1. Square centimeters.

2. The square * square centimeter.

1。It should be an increase of two base areas Multiply] 2=

2 divide by 6= is the base area and then use 16* =

Question 1: s (increase) = square centimeters).

Question 2: a(radius) = centimeters).

s = square centimeters).

square centimeters).

square centimeters) 16* = square centimeters).

These two questions are okay, just be proficient, and you can easily solve them with more heads