Mathematics in the second year of junior high school, mathematics in the second year of junior high

The angular bisector is equal to the distance to the 2 sides.

The angular bisector is equal to the distance to the 2 sides.

The angular bisector is equal to the distance to the 2 sides.

The angular bisector is equal to the distance to the 2 sides.

The angular bisector is equal to the distance to the 2 sides.

1. Two small squares with a side length of 1 can be cut and put together to obtain a large square [draw a figure]. If the side length of a large square is a, can a be a positive number? [ Yes ], the reason is [ a*a=2 ].

Could a be a fraction? [ not ] reason; 【

2.Give examples of different types of irrational numbers that you know; 【

3.Knowing that a and b are two consecutive integers, and a 7 b, then a+b = [ 5 ].

4.With a 48m long fence, a green field is enclosed in the open space, and there are two design schemes; One is a square site, the other is a circular site, which scheme is selected, and the enclosed site is larger? Why do you want to explain?

5.If x+2=2, then the arithmetic square root of 2x+5 [ ] is written.

6.Knowing y= 5-x + x-5+2, find the value of x y.

7.Find the values of the following formulas.

All write down the process ha}

8.Knowing that the square root of 2a-1 is 3 and the square root of 3a+b-1 is 4, find the square root of a+2b?

5.The absolute value x+y-2+ x-y+4=0 is known to determine whether x+y has a square root or not. Try to explain.

Too many questions show that you are lazy.

questions is very.

Give examples of different types of irrational numbers that you know; 【 Root No. 2 ( (.)

Yes, because the translation of the graph is determined by the direction and distance of the translation; The rotation of the graph is determined by the center of rotation and the angle of rotation; Map.

This data is ** on the map, and the final result is subject to the latest data on the map.

Knowing that y1=2x+4 and point p is on l1, then -2+4=m, m=2

L2 passes through two points and is p(-1,2),a(-3.).,0), let the expression of l2 be y2=kx+b, then -k+b=2, -3k+b=0, and the solution is k=1, b=3, that is, the expression of l2 is y2=x+3

Solution: 1: 3 3x 2x 18

x＞－3x≥－2

3x－ax＝6

6＋2a＝6

A 62: I can also buy x dictionaries.

65×20＋40x≤2000

40x≤700

x x is a positive integer.

x 17 means you can buy up to 17 dictionaries.

3： ①x/3＋2x≤0

Xiao Ming's weight Xiao Gang's weight.

1. Solution: 3-3x<2x+9 x>-6 5 is the smallest integer by x=-1 substituting to obtain a=9

65x20=700 700 divided by 3x+2x less than or equal to 0

Xiao Ming's body is greater than or equal to Xiao Gang.

Question 1:

Remove the parentheses and move the items to get: 3-18<3x+2x

i.e. 5x>-15 so we get x>-3

Question 2: If you can buy up to x copies, you can list inequalities:

65*20+40x<=2000

i.e. 40x<=700.

x< = 70 4 and 70 4 = so up to 17 copies.

Question 3: [1].

x/3+2x<=0

2] Let Xiao Ming's weight be x and Xiao Gang's weight be y, then it can be expressed as x>=y

1.From the solution of the inequality to obtain x=-2, bring in the equation, get a=63(1) Less than or equal to.

2) Greater than or equal to.

I did it myself, and I can't be blamed for my mistakes. Check it out for yourself.

δabc is an isosceles right triangle with a ratio of 1:1:2 to the three sides of an isosceles right triangle.

After A is Ah L in H, then Ah=C to AB distance = 2 2, HP1=HP2= (AP 2-AH2)= 6 2, and Δach is also an isosceles right triangle, CH=Ah= 2 2, Cp1=(6- 2) 2, Cp2=(6+ 2) 2, and ΔCP1E, ΔCP2D are also isosceles right triangles, P1E=CP1 2=(3-1) 2, P2D=CP2 2=(3+1) 2.

Elect d.