y lg sinx cosx Is sinx cosx odd or even.

Define the domain: (sinx-cosx) (sinx+cosx)>0sinx-cosx)*(sinx+cosx)>0sin x-cos x>0

cos²x-sin²x<0

cos2x<0

2+2kπ<2x<3π/2+2kπ

4+k defines the domain: ( 4+k , 3 4+k )k=0, ( 4, 3 4).

k=-1, (3π/4, -/4)

When k=0 and k=-1, the composition of the definition domain is symmetrical with respect to the origin.

Again satisfying f(x)=-f(x) (upstairs has been written) the image is as follows: also about origin symmetry.

So y=lg(sinx-cosx) (sinx+cosx) is an odd function.

Note that y=(sinx-cosx) (sinx+cosx) is non-odd and non-even.

Let f(x)=lg[(sinx-cosx) (sinx+cosx)], then f(-x)=lg[[sin(-x)-cos(-x)] [sin(-x)+cos(-x)]].

lg[(-sinx-cosx) (-sinx+cosx)]lg[(sinx+cosx) (sinx-cosx)]-lg[(sinx-cosx) (sinx+cosx)]-f(x) so f(x) is an odd function.

If you don't understand, you can ask.

Super easy question, so complicated!

x=2, y=0;

When x=-2, y is meaningless.

It's not odd! The title is y=lg[(sinx-cosx) (sinx+cosx)].

The odd function The numerator and denominator are divided by the cosine to get the tangent.

Summary. y=(xsinx) (1+cosx) parity is an even function. The specific process will be sent by the teacher**.

y=(xsinx) (1+cosx) to find parity.

y=(xsinx) (1+cosx) parity is an even function. The specific process will be sent by the teacher**.

First of all, the true/false question type is a function question. Second, observation. Then, use the definition to prove it. Finally, the identity deformation is obtained.

y=cos(x-7 2)=cos(x-7 2+4 )=cos(x+ 2)=cos(-x- 2)=-cos( -x- 2)=-cos( jujube 2-x)=-sinx; ∵sin(-x)=-sinx;y is an odd function, if there is a stool in this question, what auspicious vertical does not understand, you can ask, if you are satisfied, remember that if there are other questions, this question will be sent after another click.

Root number 2 * sin(x-4) +1

f(-x)= root number Swim Oak Rent2 * sin(-x- 4) +1 is not equal to f(x).

It is neither an odd function nor an even function.

If you really can't do it, just bring a few numbers or draw a picture with a geometric drawing board like Zheng.

Odd functions. Here's how, please refer to:

y＝-sinxcosx

sin2x/2

So this function is odd.

For reference, please smile.

Method 1: f(x) =sinx)(cosx)f(-x) =sin(-x) *cos(-x) =sinx * cosx = f(x), odd function.

Method 2: f(x) =sinx)(cosx) =f(-x) = = =f(x), odd function.

y=sinxcosx

Root number 2SIN (x-4).

f(-x)=

Root number 2SIN (x-4).

Not equal. f(x)

It is neither an odd nor an even function.

It's really not good, just bring a few numbers to the town or use a geometric drawing board to draw a picture.

f（-x）=sin(-x)-cos(-x)+1-sinx-cosx+1

f（x）≠-f（x）

Therefore, this function is non-odd and non-even.

If you approve of the jujube line quietly mine, please be in time.

In the top right corner of me, click [Answer] to bring along.

If you have any questions, you can continue to ask, thank you.