A tractor, on the first day plowed 1 3 more than 50 square meters of this field

Let the area of this land be x

Ploughed on the first day : x 3+50

Ploughed on the second day : x-(x 3+50)] 2+30 with total area x-ploughed on the first day - ploughed on the first day = remaining (310) In summary: x-[x 3+50]-=310

Find x=1095

If the area of the land is x, then 1 3x+50 was ploughed on the first day, and 1 2+30 was plowed on the second day, so.

x-(1/3x+50+1/2x+30)=3101/6x-80=310

x=2340

or (310+30+50) (1-1 3-1 2)=(390) (1 6)=2340

Set up a total of x square meters of land.

x-（1/3x+50）-（1/2x+30）=310

x=3240

Let the area of this land be x

From the meaning of the title. 1 3x+50+1 2x+30+310=x solution: x=2340

So the area of this land is 2340 square meters.

Let the area of this land be x

1/3x+1/2x+50+30=x-3105/6x-x=-310-80

1/6x=-390

1/6x=390

x=2340

Count the rest yourself!!

1 Question 4 out of 9 2 Question 2 and 1 Quarter 3 is 9 out of 13 for large tractors and 4 out of 13 for small tractors.

A tractor ploughed 9,000 square meters in three hours, and it would take another 12 hours to plough the land. This piece of land has more than one brother and a total of more than one square meter?

45,000 square meters.

The land ploughed on the first day = a 3+2

The land ploughed the next day = [a-(a 3+2)] 2

The remaining = a- (ploughed on the first day + ploughed on the second day) after two days, and the specific algebraic arithmetic should be able to calculate it yourself!

The tractor wants to plough x acres, and on the first day it ploughs one-fourth, i.e. (1 4)x acres, then x-(1 4)x = (3 4)x acres.