Mechanics.. Inclined plane.. Maximum, the force on the inclined plane

The so-called ultra-troublesome traditional method is to do mechanical analysis. This method is actually not particularly cumbersome. There's a long equation for that.

If you don't like it, go ahead and do it. You see, what I write is complicated, but it's actually just a momentary thought, and I'm a little afraid of saying it clearly.

The object rises under the action of the force, and this is to do work. The ** of the work is entirely provided by f, so the less the power, the smaller the f.

According to the law of conservation of energy, the work done causes a certain amount of energy to rise in an object. Since the object is at a constant velocity, the kinetic energy does not change, then, it is possible that the heat is generated due to friction and is converted into heat energy), or the gravitational potential energy.

Since the increase in gravitational potential energy is obtained by overcoming gravity, the gravitational force of an object does not change, so its power depends only on the rising velocity. In this question, the object rises at a constant speed, which means that the object is in a state of force equilibrium, and what is the speed, whichever is the answer, does not affect the answer.

Well, obviously, the less friction, the less heat is generated, and the lower the power. The least frictional method is that f cancels out in the direction of the perpendicular bevel and g again. But since the inclined plane does not interact with the object in this way, the equilibrium of forces is done only by f and g.

F and g are equal in size and opposite in direction. The angle between the bevel and f is 90 degrees - si ta

The most labor-saving thing to do is to make the component of the perpendicular slope of f equal to the gravitational force in that direction (i.e., frictionless force), with fsina=mgcos@, fcosa=mgsin@ to do the division i.e. tan a=cot @

a=90 degrees-@

Two forces, one gravity and one support, do not produce other forces because people are relatively stationary on the inclined ladder.

People: gravity, the elastic force of the oblique to the person, the friction of the oblique to the person.

1) Perform force analysis on the ball (orthogonal decomposition along the vertical and horizontal directions) by gravity, tensile force, and support force.

Vertical Plane Equilibrium The horizontal plane has a resultant force to the left to provide acceleration, and the column equation can be removed.

2) The same decomposition is carried out with a pressure of 0 that means the inclined plane does not give support to the ball.

Then the vertical plane equilibrium The horizontal plane is completely provided by the tension of the rope, and the resultant force to the left = ma column equation can be relieved.

On the top floor, there is also a large tension of the rope when it leaves the inclined plane, and the vertical component has met the gravity of the ball, and the horizontal component provides the acceleration of the common exercise with the inclined plane.