C program, which prawn can point down

The characteristic of shaping is to discard the number after the decimal point, no matter how big or small, even if it is. The same goes for 9.

Therefore, when using floating-point operations and division operations, you should use floating-point or double-precision floating-point operations.

There are quite a few such questions in the Level 2C exam.

To put it simply, this loop statement is weighted and assigned.

for(i=1;i<=n;i++)

item=x2/x1;

sum+=item;

x=x1+x2;

x1=x2;

x2=x;n=2, the first round of cycle:

i=1 item=x2/x1=

sum=item+sum=2+0=

x=x1+x2=

x1=x2=

x2=x=Second Cycle:

i=2 item=x2/x1=

sum=item+sum=

x=x1+x2=

x1=x2=

x2=x=This is where the problem can be seen.

If it's an integer, it becomes.

item=x2/x1=

sum=item+sum=

x=x1+x2=5

x1=x2=3

x2=x=5

and 3, the problem lies in the decimal places generated by the division operation.

Therefore, use floating-point instead of integer.

item=x2/x1

The result of the division here is:

floating-point = (cast type conversion) (integer integer).

Suppose x2 = 3 and x1 = 2

item=x2 x1=instead of.

Because the result of x2 x1 is an integer, the result is taken as 1

It is then converted to floating-point type.

So i,n can be defined as integers.

Nothing else

If the integer number in the C C++ language involves division operations, the result after the decimal point will be omitted (this is determined by the characteristics of its data type), so it is generally not used when it comes to division. Unless it is really realistic (e.g. when counting people, there is no decimal, it can be used).

That one is related to your output format.

sss is the function that calls the first argument.

And so it is.

x=funa(9,3)=12

x+=funb(8,3)=5

x=12+5=17

Therefore, choosing C is the simplest application of function pointers, as long as you understand function pointers, this problem is not difficult.

The answer is c, after the first call to funa x = 12, the second funb returns 5 and 12 + 5 = 17