Mathematics Algebra Values Please answer in detail, thank you 15 22 1 27

The first year of junior high school, it's so far away, I don't know if it's right:

ax2003-bx2001-cx1999+6=x(2003a-2001b-1999c)+6

Substitute x=-5.

Then: -5 (2003a-2001b-1999c) + 6 = -25 (2003a-2001b-1999c) = -82003a-2001b-1999c=

When x=5, AX2003- BX2001- CX1999+6=X(2003A-2001B-1999C)+6=5(2003A-2001B-1999C)+6=5*

Using the theorem of odd functions, we can find that the value of x=5 is 14

1.If the algebraic formula a + 2/1a makes sense, then a should be taken as (a is not equal to -1).

2.If the value of algebraic equation 2 (square of x) + 3x + 7 is 12, then algebraic equation 4 (square of x) + 6x + 10 = (20).

Not equal to -1

It's not equal to 1, and the others are not counted.

Mistaken? Study hard and don't be opportunistic! It's a very simple question.

Replace part 1 of the requirement with abc

Original formula = a (ab+a+abc)+b (bc+b+abc)+c (ac+c+abc)=1 (b+1+bc)+1 (c+1+ac)+c (ac+c+1)=abc (b+abc+bc)+1 (c+1+ac)+c (ac+c+abc)=ac (c+1+ac)+1 (c+1+ac)+c (ac+c+abc)=(ac+1+c) (c+1+ac)=1

You don't have a complete topicDefinitely. x+2

y+1)】=0Then since (x+2) 2 is greater than or equal to o, and the absolute value of (y+1) is also greater than or equal to o, and the sum of two numbers greater than or equal to o is o, then both must be oThen there is an absolute value of (x+2y+1)]=o, so x=-2, y=-1, and then substitute it into the later calculation.

Because (x+2) 2 + [absolute value of (y+1)] = 0Then since (x+2) 2 is greater than or equal to 0, the absolute value of [(y+1)] is also greater than or equal to 0, so there is (x+2) 2=0, [absolute value of (y+1)] = o, so x=-2, y=-1, and because 5xy 2-=4xy 2=4*(-2)*(1) 2=-8

1.When a+b 2a-b = 5, take the last 2a-b a+b = 1/5

So 2 parts of a + b (2 a-b) plus 3 parts of 2 a - b (a + b).

2 5 + 3 1/5

10 and 3/5

2.If the value of x+2y+5 is 7

So x+2y = 2

3x+6y²+4

3(x+2y²)+4

103.Known: a=2b c=5a

So c = 5 2b = 10b

So a-4b+c 6a+2b-c

2b-4b+6/10b 2b+2b-10b=4b/8b

14 out of 2Let x = a of 2 = b of 3 = c of 4 parts

then a=2x, b=3x, c=4x

So 3a-b+c is a+2b-c

6x-3x+2x+6x-4x

4x out of 7x

4 out of 7

(2a-b) (a+b)=5 gives a=-2b, and the original formula =2*5+(-2b-b) (-5b)=59 5

x+2y+5=7, i.e. x+2y=2, the original formula = 3*(x+2y)+4=10

a-4b+6a+2b-c=(12b+2b-10b) (2b-4b+10b)=1 2

2/2 a = 3 out of b = 4 out of c i.e. b = 3 2a, c = 2a, original formula = (a + 3a - 2a) (

Because 12+22+32+...n2 = 1 6n (n + 1) (shirt draft chong 2n + 1) so 22 + 42 + 62 + .2n)2=1 Jingfan 6*(2n)(2n+1)(2*(2n)+1)=1 3*n(2n+1)(4n+1).

And because 2n=50

So or annihilation is n=25

Bring in 22+42+62+...502=1/3*n(2n+1)(4n+1)=25*17*101=42925

If AP is connected, then the area of the triangle ABC = the sum of the area of the triangle ABP and the triangle APC = 1 2*AB*PD+1 2*AC*PE=2*(PD+PE)=6

So pd+pe=3

Mathematics Algebraic Formulas Please answer in detail, thank you! (9 23:10:53)

Bounty Points: 0 - 14 days and 23 hours until the end of the question.

1。No matter what value x takes, the value of the algebraic formula -3x 2+mx+nx 2-x+3 is always 3, try to find the value of m,n.

2。Knowing that x 2-x-1 = 0, find the value of the algebraic formula -x 3+2x 2+2011.

3。Knowing a=2x 2+3xy+2x-1, b=x 2+xy+3x-2, and the value of a-2b has nothing to do with x, find the value of y.

4。Let a represent a two-digit number, b represents a three-digit number, put a to the left of b to form a five-digit x, and put b to the left of a a five-digit y, and ask 9 is divisible x-y?Please explain why.

Analysis: Put A to the left of B, B is a 3-digit number, which is equivalent to enlarging A by a factor of 1000.

Answer: Get the result 1000 a+b

1.The value of -3x 2+mx+nx 2-x+3 is always 3, and -3x 2+mx+nx 2-x+3

-3+n)x^2+(m-1)x+3

3 So x 2, x has a coefficient of 0

i.e. n-3=0

m-1=0, so m=1, n=3

Cubic + 2x square + 2011

x squared - x-1) (-x + 1) + 2012 = 2012

2x^2+3xy+2x-1-2x^2-2xy-6x+4=xy-4x+3

x(y-4)+3

The value is independent of x.

So the coefficient of x is equal to 0

So y-4=0

y=4 is, of course, a multiple of 9.

Is there a reward?

I'm hurting you.