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N2 + O2 (energized) ***** = 2NO

2no+o2====2no2

3no2+h20==no+2hno3

3no2+h20==no+2hno3

NH4Cl + NaOH (concentrated) ***** = heated NH3 + NaCl + H2ON3 + HCl = == NH4Cl (solid particles) 4NH3 + 5O2 ==== (catalyst) 4NO+6H208HNO3 (dilute) +3Cu*****3Cu (NO3)2+2NO+4H2O

HNO3+NH3·H2O NH4NO3+H2O10 can also be this 4ZN 12HNO3 (extremely rare) 4ZN(NO3)2 NH4NO3 3H2O

1 N2 + O2 = (discharge) = 2NO

2 2no+ 02=2no2

34 3no2+h20=2hno3+no

5 4Hno3 = (heat or light) = 4NO2 + 02 + 2H20 or concentrated nitric acid reacts with reducing agent.

6 NH4Cl = (heated) = HCl + NH38 4NH3 + 502 = (catalyst, heated) = 4NO+6H207 NH3 + HCl = NH4Cl

9 4Hno3 (dilute) + Fe = Fe (No3) 3 + No + 2H2010 Hno3 + NH3 = NH4NO3

under discharge conditions).

Normally, you can).

4no2+2h2o+o2=4hno3

Light) microthermal) to test the presence of ammonia NH4Cl= HCl + NH3 (heat) Heat, catalyst).

Diluted) 3Cu = 3Cu (NO3) 2 + 2 No + 4H2O (heating) That's it, I found that the chemical formula was really tiring after playing

n2+o2=2no

2no+o2=no2

no2+n=no

no2+h2o=hno3

Hno3 No2 passes into H2SO4

I don't know about the back.

HNO3+2H2SO4=NO2+2HSO4+H3OH3BO3+6H2SO4=B(SO4)4+2HSO4+3H3O7I2+HIO3+8H2SO4=5I3+8HSO4+3H3O did not add "-+, add it yourself, this is a competition question, right?

1. Heating of (CH3)3C-OH and concentrated H2SO4: (CH3)3C-OH --concentrated sulfuric acid, -CH3)2C=CH2 + H2O

The product after the reaction reacts with BR2 and CCL4: (CH3)2C = CH2 + BR2 --CH3)2CBrCH2BR

2. CH2=CH-CH=CH2 + BR2 --certain conditions-->CH2BRch=CHch2BR

ch2brch=chch2br + 2naoh --ch2ohch=chch2oh + 2nabr

ch2ohch=chch2oh + hcl --ch2ohch2chclch2oh

CH2OHCH2CHClCH2OH -- concentrated sulfuric acid, -CH2=CHCcl=CH2 + 2H2O

nch2=chccl=ch2 --certain condition-->ch2-ch=ccl-ch2-]n-

ch2ohch2chclch2oh + 2O2 --certain conditions-->hooc-ch2chclcooh + 2H2O

Hooc-CH2CHClCOOH + 3NaOH - alcohol solution, -NaoOC-CH=CH-CoONA + NaCl + 3H2O

naooc-ch=ch-coona + 2h+ -hooc-ch=ch-cooh + 2na+

Hooc-CH=CH-COOH + 2CH3OH -- concentrated sulfuric acid, -CH3OOC-CH=CH-Cooch3 + 2H2O

1: (CH3)3COH tert-butanol and concentrated H2SO4 are heated to eliminate and react to form 2-methylpropene, and Br2-dibromo2-methylpropane is added.

It's really too much.,The landlord won't be able to write it all.,Refer to a few that really can't talk about it.。

It's easy, but it's really too much to write.

Mn in KMno4 decreases from +7 to +2, and S rises from -2 to 0 in H2S, and the number of gained and lost electrons is equal.

So the coefficient kmno4:h2s=2:5

The other coefficients are then trimmed. Pick D

The answer is that the price of two mns in D is reduced by a total of 10, so there should be five sulfurs oxidized.

d, the gains and losses of electrons should be conserved

d is chosen because the gain and loss electrons are not conserved.

Magnesium and hydrochloric acid, mg + 2HCl

mgcl2h2↑

Magnesium and sulfuric acid, MGH2SO4

mgso4h2↑

Zinc and hydrochloric acid, Zn2HCl

zncl2h2↑

Zinc and sulfuric acid, ZNH2SO4

znso4h2↑

Iron and hydrochloric acid, Sifeng.

fe2hcl

fecl2h2↑

Iron and sulfuric acid, FeH2SO4

feso4h2↑

Iron oxide and hydrochloric acid, Fe2O3 + 6HCl = = 2FeCl3 + 3H2O iron oxide and sulfuric acid, Fe2O3 + 3H2SO4 = = Fe2 (SO4) 3 + 3H2O

Sodium hydroxide and carbon dioxide, 2NaohCO2

na2co3

H2O calcium hydroxide and carbon dioxide, CO2

ca(oh)2

caco3↓+

H20 raw stone celery lure lime slaked lime, Caoh2O

ca(oh)2

Caustic soda absorbs sulfur oxide.

2naohso3

na2so4h2o

Hey, rush aside...

mg+2hcl=mgcl2+h2↑

mg+h2so4=mgso4+h2↑

zn+2hcl=zncl2+h2↑

zn+h2so4=znso4+h2↑

fe+2hcl=fecl2+h2↑

fe+h2so4=feso4=h2↑

fe2o3+6hcl=2fecl3+3h2ofe2o3+3h2so4=fe2(so4)3+3h2o2naoh+co2=na2co3+h2o

naoh+co2=nahco3

Ca(OH)2+CO2=CAC3+H2OCA(OH)2+2CO2=CA(HCO3)2CAC3=CAO+CO2 (heated state shed).

2naoh+so3=na2so4+h2o

If you want to learn chemistry well, you can take a good look at these equations and find some rules from them.

A small amount of carbon dioxide 2NaOH+CO2=Na2CO3+H2O is introduced into the sodium hydroxide solution

A small amount of sulfur dioxide is introduced into the sodium hydroxide solution 2NaOH+SO2=Na2SO3+H2O

A small amount of sulfur dioxide Ca(OH)2+SO2=CaSO3+H2O is introduced into the calcium hydroxide solution

2naoh+co2=na2co3+h2o

A small amount of sulfur dioxide is introduced into the sodium hydroxide solution 2NaOH+SO2=Na2SO3+H2O

A small amount of sulfur dioxide Ca(OH)2+SO2=CaSO3+H2O is introduced into the calcium hydroxide solution

Excessive production of bicarbonate Know.