If x 1 x 3 1 find x squared x x squared 1

1) Because x+1 x=3, (x+1 x) 2=3 2=9

And because (x+1 x) 2=x 2+1 (x 2)+2*x*1 x=x 2+1 (x 2)+2=9

So x 2 + 1 (x 2) = 9 - 2 = 7

2) Because x 2 + 1 (x 2) = 7

So (x 2 + 1 (x 2)) 2 = x to the power of 4 + 1 x to the power of 4 + 2 = 49

So x to the power of 4 + 1 x to the power of 4 = 47 (the idea is the same as the first question, that is, the result of the first question is a known condition).

3) (x-1 x) 2=x 2+1 (x 2)-2*x*1 x=7(:(1))-2=5

1) x+1 x=3, squared on both sides, get: x 2 + 1 x 2 + 2 = 9, the answer to the shift: 7

2) x 2 + 1 x 2 = 7, squared on both sides, get x 4 + 1 x 4 + 2 = 49, the answer to shift terms: 47

3）（x-1/x）^2 = x^2 + 1/x^2 - 2 = 7 - 2 = 5

Hope you understand.

x+1 x=3, (x+1 x) squared = 9, we can get, x's square + x's square 1+2=9, so x's square + x's squared 1=7

In the same way, x to the power of 4 + 1 x to the power of 4 = 47, and (x-1 x) squared = x squared + x squared 1-2 = 5

The result of this polynomial is x=1, here, we first turn the left side into x 2+2x+1-4=x 2-1, and move the terms to merge the same kind of terms to get 2x=2, so x=1. The main step in solving this question is to turn the left.

The solution consists of x 2-4x+1=0

i.e. x 2 + 1 = 4x

Divide the two sides by x to get x+1 x=4

squared x 2+1 x 2+2=16

i.e. x 2 + 1 x 2 = 14,8, x -4x+1 = 0x-4 + x one-part = 0

x+x/1 = 4

x+x/1) = 16

x + x 1 per square = 14, look! ,0,

x+1/x=4

x+1/x）^2=4^2

x 2+1 cavity calendar x 2+2=16

x^2+1/x^2=14

It is the search of the Yiwu Hall of the square of Fu Xian.

(3x squared) - 7x squared [x squared - x (4x squared + 1)] + x squared) where x = 1/2.

3x^6-7x³(x³-4x³-x)+x^4=3x^6+21x^6+7x^4+x^4

24x^6+8x^4

8x²(3x^4+x²)

2) 6xy [x's squared (5x+3)-3x's squared (-4y)], where x=2 and y=one-third.

6xy(5x³+3x²+12x²y)

x x squared - x + 1 = 1 3, take the reciprocal on both sides to get :

x²-x+1)/x=3

x+1/x-1=3

x+1/x=4

Both sides are squared:

x²+1/x²+2=16

x²+1/x²=14

x x to the fourth power + x +1

The numerator and denominator are divided by x to get :

Original = 1 (x +1 x +1).

This question examines the perfect flat way of a particular formula.

x + 1 x) squared = x squared + 1 x squared + 2 (x - 1 x) squared = x squared + 1 x squared - 2 Compare the two formulas, do you see the problem?

x + 1 x) squared = (x - 1 x) squared + 4 will be done below, right?

Multiply x on both sides

x square + 1 = 4x

ps: The following "squared" is used for 2 generations.

Shift item x2-4x+1=0

To perfectly square the formula, add 3 on both sides

x2-4x+4=3

x-2) = 3