Is int a 2 3 1,2 , 3,4 , 5,6 the correct assignment?

Here a[2][3] represents 2 rows and 3 columns, and when you assign the value, it is 3 rows and 2 columns, which means that your number of rows is out of bounds, so it is not possible, the number of rows can only be less than or equal to 2, and the number of columns can only be less than or equal to 3, I hope you can understand.

I think this is wrong, the landlord can take a look at the following **, you can find the problem, I hope it will help you.

#include

void main(), in fact, if you put this sentence in a global variable, the result will be the same.

for(int i=0;i<2;i++)

for(int j=0;j<3;j++)

printf("%d",a[i][j]);

d:\ error c2078: too many initializers

d:\ fatal error c1004: unexpected end of file found

There was an error executing .

1 error(s), 0 warning(s)

Wrong, because there are only 2 lines, but the value is given 3 lines.

No way? If I'm not mistaken, it should be 2 rows and 3 columns, and the value behind it is 3 rows and 2 columns, which should be wrong, and I used to take the 2nd level, I don't remember much, you think about it in this direction, I'm sorry.

The 0int type defaults to 0, and this initialization is equivalent to int a[3] = , , or int a[ ]3] = ,,}

The second-dimensional parameter is 3, but when assigning the value, all three have only one integer, and the other two default padding 0 is equivalent to int a[3][3]=,,}

So a[1][2] = 0;

2 This is a two-dimensional array, 2 in a[2][3] is the number of rows of the array, 3 is the number of columns int a[2][3]=,}; Equivalent to 1 0 0 2 3 0 Since the subscript in the array starts from 0, a[1][0] represents the 2 (1+1) rows in the array, and the 2. in the 1 (0+1) column.

int a[ ]3]=,,}

The second dimension parameter is 3, but when you assign the value, all three have only one integer, and the other two are filled with 0 by default

Equivalent to int a[3][3]=,,}

So a[1][2] = 0;

It's not random, it's 0

This initialization method is called "incomplete initialization" of the array, in the words of "C and Pointers".

int a[ ]3] We only know that the number of columns is 3, we don't know the number of rows, but there are only three values, which must be arranged sequentially, horizontally. It can only be arranged in this way, and the other fill in 0. There is also a[1][2], so fill in 0 for rows above 2

In the problem, a two-dimensional array a[3][2] is defined, and after initialization as, a pointer variable p is defined to point to a[1], which is the first address of the one-dimensional array.

Then, p plus 2 points to the first address of the one-dimensional array, and *(p+2) points to the value of the address, i.e., 1. Therefore, *(p+2) has a value of 1.

It should be noted that the expression "int+a[3][2]" in the title is the wrong Pizhou, and it should be "int a[3][2]" to be the correct syntax.

According to the title, the kernel pointer p points to a[1], which is the first element of the second line in the array, which is 4. (p+2) means that p moves 2 elements backwards, and the thick in the feast points to a[1][2], which is the element 3 behind Zhenzhen 4, so the value of (p+2) is 3.

a[1] points to the first element of the second row, which is 4. Therefore, p+2 will point to the three elements of the second row's ascending field, i.e. 3. Therefore, the value of *(p+2) is 3.

Summary. First of all, find the sequence, which is equal to 3, because the sequence of the array starts from 0, so 3 corresponds to the fourth number, which is 12 ha.

inta;, then a[6 2]=

Okay, wait a minute, I'll get back to you as soon as I'm done.

Good. a[6/2]=a[3]=12

How do you calculate it?

To the process. First of all, find the sequence, which is equal to 3, because the sequence of the array starts from 0, so 3 corresponds to the fourth number, which is 12 ha.

Each number in the array corresponds to the ordinal number 0 1 2 3 4 5

int a[4]; a[4]=5;Can it be assigned like this?

Hello dear and happy to answer for you. int a[4]; a[4]=5;In addition to assigning values to array elements one by one with assignment statements, the method of assigning values to arrays can also adopt the methods of initial assignment and dynamic assignment. The C language also has the following provisions for the initial assignment of arrays:

1) It is possible to assign an initial value to only some elements of lead wax. When the number of median values is less than the number of elements, only the previous elements are assigned. For example:

int a[10]=;It means that only 5 elements of a[0] a[4] are assigned a value of finch, and the last 5 elements are automatically assigned a value of 0. 2) You can only assign values to elements one by one, and you can't assign values to the entire array as a whole. For example, if you assign a value of 1 to all ten elements, you can only write it as:

int a[10]=;It cannot be written as: int a[10]=1; Multi-dimensional arrays are also the same way to assign values to arrays, in addition to using initialization assignments, using assignment statements to assign values to array elements can only be assigned one by one, the above is all the answers of the answerer, I hope to help you, I wish you a happy life

a[1][2] is the third element of the second group of numbers, which is 7

a[2][3] is the 4th element of the 3rd group of numbers, which is 8

What's wrong with being 15?

It represents two rows and three columns, and the following table all starts from 0, so a represents the second row and the third column.

The order is as follows: 1, 2, 3

Apparently visible The value is 6

Mathematics is not good, why don't you use easy language?