A math problem, I urgently need the answer, please know quickly, thank you for your cooperation

x=y+

z = the above two equations are substituted into the third formula, and the following is obtained

3y=so, y=

Substituting y= into the top two formulas, we get:

x=4z=8

x-y＝ （1）

y+z＝ （2）

x+z＝x+x+x （3）

From (3) we get z=2x (4), and by substituting (4) into (2), we get 2x+y= (5).1) + (5), got.

3x=12 i.e. x=4

Substituting x=4 into (1) gives y=

Substituting x=4 into (4) gives z=8

So x=4, y=, z=8

x=4 y= z=8

x = substitution x + z = 3x

Obtain y=substitution of the relevant terms to obtain x=4, z=8

From x+z x+x+x, we get z 2x

So y+z is y+2x

Get x from x-y

Substituting x into y+2x gives 3y+

y=z=8

The addition of 1 and 2 gives x+z=12=x+x+x, so y=,z=8

I won't draw a picture.

1, 2, the sum is certain.

xy=603,w=xy-2y=60-2y=60-120 x to w maximum, that is, 60-120 x maximum, that is, 120 x minimum, that is, x maximum.

then w=48 is the largest when x=10.

1 All 1. Because the height is shortened by 2 centimeters, the surface area is reduced by square centimeters, so the bottom circumference of the cylinder is: divided by 2 = centimeters, so the height of the original cylinder is centimeters, and the radius of the bottom surface is 1 centimeter, so the volume of the original cylinder is: cubic centimeters.

2。Cone; 6 cm; 10 cm.

3。Isosceles triangle; 2 square decimeters.

1.Let the original height be h cm, and the circumference is the same as the original height is also h cmh*h-(h-2)*h=

H=Original ground radius=

Original volume = 1*1**

2.Cone 6 10

3.Triangle 2

Let the vertical distance from F to AD be H.

Because F is the midpoint, the height of the parallelogram ABCD is 2h.

Because: s(adf)=ad*h2=5

Then: s(abcd)=ad*2h=5*2*2=20, so s(aef)=s(abcd)-s(adf)-s(abe)-s(efc)=8

Hope it helps

Let the height on the side ad of the parallelogram be h.

Then the area of ACD is 1 2*ad*(h 2)=ad*h 4=5, then the area of the parallelogram is ad*h=20

The AEF area sought is 20-3-4-5=8

So the area sought is 8 square centimeters.

Let the height of F to Ad be H, then the height of the parallelogram ABCD is 2H

Because, the area of the triangle ADF AD*H2=5 i.e. AD*H=10 The area of the parallelogram ABCD AD*2H=20The area of the triangle AEF The area of the parallelogram ABCD - the area of the triangle ADF - the area of the triangle ABE - the area of the triangle ECF = 20-5-4-3=8

Solution: A is perpendicular to BC

Because f is the cd midpoint.

then sadf=ad*1 2am 2=5

then ad*am=20

So the parallelogram ABCD area is 20

The area of the triangle AEF is 20-5-4-3=8

8 square centimeters. Let the height of the parallelogram be h, and let ad=a, then the area of the triangle adf is expressed as: (a*h2) 2=5.

This translates to: a*h=20. The parallelogram area is the total area minus the blank part 12, which is 8

The area of the solved AEF is 4 square centimeters.

Let the DF side length a and the parallelogram height be h

s△afd=½ah=4

s parallelogram abcd=2ah=16

s aef = s parallelogram abcd-s efc-s afd-s aeb = 16-3-4-5 = 4

Set big horse x, medium horse y, pony z

x+y+z=100

2x+y+ can know y=100-3x

z = 2x because y 0

So x 33

This is discussed according to x.

There can be 34 bells of reasonable answers, which are:

0 large horses, 100 medium horses, 0 small horses.

1 large horse, 97 medium horses and 2 small horses.

There are 2 large horses, 94 medium horses and 4 small horses.

There are 33 large horses, 1 medium horse and 66 small horses.

Let the cultural achievement be noisy x

x Shen round group ) wide orange

x=388