5 points bounty!! Speed to solve math problems in junior high school! Thank you very much!

Solution: First draw an image of y=-2x+1 on the coordinate paper (this will be!?Then find the point (-4,2).

On the image y=-2x+1, find the points that intersect the x-axis and the y-axis, mark them, and use them later. Then find the point when y=-2x+1 is -4, then calculate the distance between this point and the point (-4,2), and then subtract the distance just mentioned from the abscissa of the point where y=-2x+1 intersects with the x-axis, and then get the coordinates of the intersection point a between the function image and the x-axis. Then, according to my instructions, the coordinates of the intersection point b with the y-axis are obtained in the same way.

I won't talk about the answer, you don't have to think about the answer. Hehe. Slowly think about what I said, and then you will calculate the area of A0B at once!

Very simple! It's all about thinking. I wish you success in your studies.

1) Set the equation first. y=kx+b, because it is parallel to the straight line y=-2x+1, so its slope k=-2, and because the straight line passes through the point (-4,2), so substitute the point into the equation, getting: 2=-4k+b, k=-2, so, b=-6, the analytic formula of the function is y=-2x-6

2) The intersection point with the x-axis, i.e., y=0, can be substituted into the equation to obtain x=-3, so the coordinates of a are (-3,0), and the same is true for the coordinates of b (0,-6).

3) The AOB is a right-angled triangle, and its area is equal to half of the product of two right-angled sides. s=1/2

x3x6=9

1) k=-2 from parallel: let the function equation be y=-2x+b; Replace the point (generation equation to get b=-6

then y=-2x-6

2) From (1): x=0, y=-6;When y=0, x=-3, then a(,b(0..)-6)

3) From (2) s=(1 2)*6*3=9

It seems that the mathematics of the year, the last thing is the function, wait and see. Ha ha..

1.2n+1 to the 2nd power minus 2n-1 to the 2nd power is equal to 8 times n.

2.2006 divided by 4 quotient 501 remainder 2, so 2 to the power of 2006 can be written as 16 to the power of 501 times 2 to the 2nd power, 16 any positive integer to the power of the single digit is 6, so that the 501st power of 16 is 6, and the 2nd power of 2 is equal to 4, so the single digit of 2 to the 2006 power is the single digit of the product of 4 and 6 4.

Question 1: (x 2)-(y 2) = (x + y) * (x - y).

Question 2: 2006 4=501......2

That is, the single digit of 2 to the power of 2006 is 4

1:2*(2n+2) n is the smaller number.

2: Regularity: 2 4 8 6 cycle Answer: 4

Like the answer of the happy ant, the answer of the happy ant is right.

Solution: The triangle ADB and the triangle CEA congruence can be deduced, and de=ce db can be obtained

That's an interesting question.

I'm probably writing it.,The main thing about this kind of question is the idea.,You probably look at the idea I wrote.,And then push it yourself.,I don't know how to ask me again.。。。

Arrive at the same time.

The distance traveled by car A: AD+DE+EC+CF

The distance traveled by car B: BE+ED+DC+CG

where de=ec=cd

acb=∠ecd=60

ACD = ECB ECA = 60 and BC = AC EC = CD

Triangle BCE Triangle ACD

ad=eb cbe= cad and cb=ac eca= bca=60 triangle bcf triangle acg

CG=CF In summary: AD+DE+EC+CF=BE+ED+DC+CG, so the two cars arrive at the designated station at the same time.

At the same time, the departure distance of A is AD+DE+EC+CF, and the departure distance of B is BE+ED+DC+CF, where DE+EC=ED+DC

ABC and CED are both equilateral triangles, the angle ACD = angle BCE, AC=BC, CD=CE, so the triangle ACD is all equal to BCD, AC=BE, according to the congruent equiangular EBC= angle DAC, the angle ACG = angle ACB=60 degrees, BC=AC, so the triangle BCF is all equal to ACG, so CF=CG, so it arrives at the same time.

(1) t=12-6t (0 is less than or equal to t less than or equal to 2), when t=0, t=2, when t=0, t=12, the function image can be obtained by connecting the two points. The intersection point with the x-axis is (2,0) and the intersection point with the y-axis is (0,12).

2) After 2 hours it drops to 0 and after hours it drops to -9. I'm also a sophomore in junior high school, o( o

After the start-on cooling, the room temperature drops by 6°C per hour, that is, the uniform rate drops t=12-6t

The diagram is too easy to draw (so I won't draw it specifically): t=0, t=12 t=2, t=0 two points are connected to draw a straight line, or any two points that meet the above formula are connected to draw a straight line.

Find the location of t=-9 in the above figure, and check how much t is equal to, you can see that t= at this time

t=0 t=12 t=2,t=0 two points are connected to draw a straight line.

Find the location t=-9 in the image above t=

t=20+(-6*1x)

Let the height be x, and since absolute zero, the range of t is 20-

t=20-6h

How do I write a value range? There is no maximum or minimum temperature.