1 If the average velocity in t1 t2 t1 v1 and the average v v2 in t2, find the average v for the whol

Updated on physical education 2024-04-04
7 answers
  1. Anonymous users2024-02-07

    Solution: 1. According to the velocity formula v=s t, s=vt, then the displacement of the first process is s1=v1t1

    The displacement of the second process is s2=v2t2

    The total displacement is s=s1+s2=v1t1+v2t2=t(v1+v2) and the total time is 2t

    The average speed of the whole process v=t(v1+v2) 2t=(v1+v2) 22, according to the velocity formula v=s t, t=s v, then the time of the first process is t1=x1 v1

    The time of the second process is t2=x2 v2

    The total displacement is s=x1+x2=2x

    The total time is t=t1+t2=x1 v1+x2 v2=x v1+x v2=x(v1+v2) v1v2

    The average speed of the whole journey is v=2x t=2v1v2 (v1+v2).

  2. Anonymous users2024-02-06

    1) Displacement in T1 x1 = V1T1, Displacement in T2 X2 = V2T2 Average V Full Process = Total Displacement Total Time = (V1T1 + V2T2) (T1 + T2)2) Time in X1 = X1 V1, Time in X2 = X2 V2 Average V Full Process = Total Displacement Total Time = (X1+X2) (X1 V1+X2 V2) = V1V2 (X1+X2) (V2X1+V1X2).

  3. Anonymous users2024-02-05

    Average velocity: refers to the ratio of the displacement of the object's motion to the time taken in a certain period of time, it is a vector and directional.

    In other words, it represents the average speed of an object in the time interval t.

    s t = average velocity.

    v0+vt) 2 = average velocity, v0 is the initial velocity, vt end velocity.

  4. Anonymous users2024-02-04

    The two periods before and after are equal in time, and the average speed.

    Yes (v1+v2) 2, there is no disadvantage in the front and back sections of the road hall, and the average speed is 2v1v2 (v1+v2)

  5. Anonymous users2024-02-03

    The whole process of linear motion of the object is 2s, and the average velocity v1 in the first half of the journey is the movement time t1=s v1; , the average velocity of the second half v2 movement time t2=s v2

    Total time t=t1+t2=s v1+s v2 average speed of the whole process.

    v=2s/t=2s/(s/v1+s/v2)=2/(1/v1+1/v2)=2v1v2/(v1+v2)

  6. Anonymous users2024-02-02

    The left numerator and denominator are multiplied by s t1t2 at the same time

  7. Anonymous users2024-02-01

    Solution: Let the whole process time be t, then the displacement of the object half of the time is s1=v1*t 2, and the displacement of the second half of the time is s2=v2*t 2, so the whole displacement should be s=s1+s2=(v1+v2)*t 2.

    According to the average speed of the p.a. potato.

    The defining average speed of the whole course should be .

    v=s/t(v1+v2)/2.

    If it helps you, please give a good review, thank you, I wish you a pleasant ride.

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