There are 19 5 grams of a mixture of methanol and ethanol, which reacts with a sufficient amount of

n1+n2）÷2=

32g per mol N1 + 46g per mol N2 = the amount of methanol in the substance n1 =

The amount of ethanol in the substance n2=

So the mass fraction of methanol is 32g per mol

The mass fraction of ethanol is 1-41%=59%.

Please understand it in a timely manner!! Good luck!

Supplementary cross method: according to hydrogen is, because the ratio of the amount of the two alcohols to the amount of hydrogen is 2 to 1, so the total amount of alcohol is , so the average molar mass of the mixed alcohol is per mol, so.

Hope!! Good luck!

Directly set methanol xg ethanol yg

2ch3oh---h2

x x/32

2ch3choh---h2

y y/46

x+y=x 32+y 46=2* Just solve xy.

n1+n2=

32n1+46n2=

The amount of methanol is n1 =

The amount of ethanol in the substance n2=

A certain amount of ethanol and benzene mixture reacts with a sufficient amount of sodium metal to produce hydrogen gas (under standard conditions), that is, to generate hydrogen moles. Benzene does not react with sodium metal, ethanol reacts with sodium metal to form hydrogen.

2c2h5oh + 2na——2c2h5ona + h2；So there is 1 mole of ethanol in the mixture.

C2H5OH + 3O2 - 2CO2 + 3H2O ethanol combustion produces 3 moles of water, burning this mixture can produce 108 grams of water, that is, 108 18 = 6 moles, so benzene combustion also produces 3 moles of water.

2C6H6 + 15O2 - 12CO2 + 6H2O According to the ratio of the coefficients on both sides of the chemical equation, the amount of benzene obtained is 1 mole and the mass is 78 grams.

Hydrogen is produced, so 22g, hydroxyl is, so methanol and ethanol are in the sail altogether, methanol molar mass is 32, ethanol is 46, let the amount of methanol substance be x, and the amount of hail alcohol is y, so.

The equation x+y=,32x+46y=22 can be obtained, and the simultaneous solution yields x=,y=, so the mass of methanol is, and the mass fraction is.

Let the amount of methanol liquid slow mass x, ethanol y, and molar mass of hydrogen = mol, i.e., according to equation 1 2 (x + y) =

According to the mass of 32x+46y=22, the bipolar x=, or punch y=, the mass of the armor buried alcohol is, and the mass fraction is.

Let the amount of methanol substance be trapped and cracked as x

The amount of ethanol substance is y

1: x+y=(Ruler surplus.)

2:32x+46y=22

Lianli solution. y=

x=then the mass fraction of methanol is.

H2 contains ethanol xmol and propanol ymol

2C2H5OH + 2Na---2C2H5ONA + H2 (gas).

2 1x x/2

2C3H7OH + 2Na--- 2C3H7ONA + H2 (gas).

2 1y y/2

x/2 + y/2 =

46x + 60y =

==> x + y= ===> 60x + 60y =9===> 14x=

x=y=ethanol in both mixtures is propanol.

So the amount of the substance ethanol:propanol = 2:1

Good luck with your studies

This problem can be solved with equations:

Let the mass of ethanol be x and propanol be y

Then x+y=

x/46+y/60=

After solving the mass, the ratio of the quantity of the substance can be obtained.

Both are 2mol alcohol and 2molna reaction, the generation of 1mol H2 is assumed to be H2 formed by ethanol reaction, then the mass of ethanol is assumed to be H2 produced by propanol reaction, then the mass of propanol is g, the mass ratio is :1, then the ratio of substances is 2 46:1 60=60:23

Monool general formula: cnh2n + 1oh (n 1, n is a positive integer) n element alcohol general formula: cmh2m + 2-n (oh) n (m> = n) First of all, you solve the idea in hydrogen production, and secondly, the title refers to this circle, and the reaction with a sufficient amount of Na explains, the alcohol is all reflected to complete, then you can solve it with the cross method according to the reaction formula of alcohol and Na (don't consider Na, because the title says, there is enough amount, so the complete reaction is alcohol.

I can tell you that, and then it's up to you to do it yourself.

2roh+2na===2rona+h2

The amount of hydrogen substance generated n(h2)=

The amount of this alcohol hydroxyl substance n(-OH)0=

Therefore, the mass of 1mol of hydroxyl alcohol is so that it can be seen that it is a polyol, and then you can solve it according to the reaction equation of polysol and sodium, and you can correct it. Good luck.. If you don't understand, I'll tell you next time.

The amount of hydrogen standard mu branch condition) is , which is obtained by replacing hydroxyl hydrogen with na, so the amount of hydroxyl substance in organic matter is.

Methanol CH3OH, molar mass: 32, hydroxyl base: 1ethanol C2H5OH, molar mass:

46, hydroxyl base: 1 ethyl dichun alcohol CH2OH-CH2OH, mol Xun Senmin mass: 62, hydroxyl base:

2 Glycerol CH2OH-CHOH-CH2OH, molar mass: 92, hydroxyl number: 3 From the above calculation data, it can be seen that the organic matter is glycerol.

2ch2(oh)ch(oh)ch2(oh)+6na===2[ch2(o)ch(o)ch2(o)]na3+3h2↑

x = pyriglycerol to produce hydrogen. is picking up the celery and the title is given; Match. Therefore, the correct answer is glycerol.

Let ethanol permeate xg propanol yg

Conservation of quality and quantity.

46x+60y=

Hydrogen is generated by the 1mol alcohol involved in the reaction of the clump. x=

Analysis: Let the saturated monool be CNH(2N+1)-OH then there is:

2 cnh(2n+1)-oh --1h2 --2(n+1)h2o

2 2(n+1)1836 solution: n=3 so the molecular formula of this alcohol is: C3H8O

The amount of substance that decomposes hydrogen gas is: 2= mol Let the saturated monool be CNH(2N+1)OH

Then let the amount of the substance of the alcohol be x mol

2 cnh（2n+1)oh + 2na = 2 cnh（2n+1)na + h2↑

x---mol

then 2 x = 1

Get x= mol

So the amount of the substance of the alcohol is.

The same amount of this alcohol is burned in the air to produce 36 grams of water.

The amount of 36 grams of water substance 36 18 = 2 mol The number of h atoms in water is: 4 mol

Whereas, the hydrogen in the water is all derived from alcohol, so the CNH(2N+1)OH of mol contains 4 mol H atoms, so * 2N+1+1 )= 4

It is obtained that n=3 so the molecular formula of this alcohol is: C3H7OH i.e. Propanol.

Alcohol reacts with sodium to produce sodium alk with hydrogen.

2roh+2na====2rona+h2

The amount of hydrogen substance generated n(h2)=

The amount of alcohol hydroxyl group in this alcohol is n(-OH) =

So the alcohol containing 1mol of alcohol hydroxyl group has a mass of .

Assuming that the alcohol is a saturated monoalcohol, then the general formula should be CNH2N+2O74=12N+2N+2+16

The solution is n=4, so the molecular formula is C4H10O

Every 2 OH reacts with 2 Na to produce 1 H2, so every 1 mol of OH will produce H2

Secondly, the problem is that the total mixture cannot be generated, and it is more reliable to tentatively say that it is hydrogen.

There is a total of OH, 1 OH per molecule of ethanol, 2 OH for ethylene glycol, and 3 OH for glycerol

In total, there are 2 per molecule on average.

Therefore, it is required that the ratio of ethanol and glycerol must be 1:1, and the amount of ethylene glycol is arbitrary.

Of the four options, only d is not satisfied.