There are 200 chickens and rabbits, and the chickens have 160 more feet than rabbits. How many chick

I'll offer a clever approach here:

If you are lucky enough to see an unusual situation: all the chickens in the cage are standing on one foot, and all the rabbits are standing on two feet. At this time, the foot touching the ground is only half of the 200 feet, that is, 100.

And the number 100 is equivalent to the result of a chicken counting once and a rabbit counting twice. Originally, there were only 200 animals, but because the rabbits were counted twice, it became 100, and the difference between the 200 and the 160 more chickens than rabbits was 200-160=40. So the number of chickens is 200-40=160.

160 chickens, 40 rabbits, and 200-x rabbits can be found if there are x chickens.

If there are x chickens, the rabbit is 200-x.

2x-4(200-x)=160

x = 160 chickens and 40 rabbits.

I haven't taught binary equations yet.

Then use one dollar at a time.

Solution: There are x chickens and 200-x rabbits.

According to the equation of the question column: 2x-4(200-x)=160, x=160 is calculated

160 chickens, 40 rabbits.

If there are x rabbits, then there are 200-x chickens.

So with 2*(200-x)-4*x=160, you get 160 chickens and 40 rabbits.

Chickens = 160; rabbits = 40;

Because there are 160 more chickens than rabbit legs. Description 2 times the number of rabbits in the wild tolerant chickens. 80 more than rabbits;

Let the rabbit be xRule.

2x+x+80=200---x=40

2*x+80=160 for chickens

Suppose they are all chickens, there are 200 2 400 chicken feet, and there are 0 rabbit feet, and there are 400 more chickens than rabbit feet, and there are actually only 160 more chickens, and the difference between the two is 400-160 240, and after each chicken is replaced by a rabbit, the difference between the two is 4+2 6 240 6 40, that is, the number of rabbits is 200-40 160.

The fake banquet is buried with 150 chickens, 50 rabbits, the number of chicken legs is 300, the number of rabbit legs is 200, the number of chicken legs is 100 more, the number of chicken legs is 160 more than the rabbit pants banquet, that is, there are 60 more chicken legs, chicken legs plus 2 rabbit legs Hu Xiangyin minus 4, a total of 6, so 60 divided by 6 is 10, so the chicken is 150 + 10 = 160, rabbit 50-10 = 40

Suppose there are x chickens and 200-x rabbits, then there is:

Number of chicken's feet: 2x Lianghu

Number of Qin Ling feet of rabbits: 4 (200-x).

The column equation is as follows:

2x-4(200-x)=160

2x-800+4x=160

6x=960

x=160 so there are 160 chickens and 40 rabbits.

How can you calculate without equations? Eat one and count one?

Suppose the chicken 150, the rabbit 50, the number of chicken legs is 300, the number of rabbit legs is 200, the number of chicken legs is 100 more, according to the requirements of the number of chicken legs than the rabbit 160, that is, the chicken legs are more than 60, the chicken legs plus 2 rabbit legs minus 4, the total number is 6, so 60 divided by 6 is 10, so the chicken is 150 + 10 = 160, rabbit 50-10 = 40

Assuming there are x chickens and 200-x rabbits, there are:

Number of chicken's feet: 2x

Number of feet of rabbit: 4 (200-x).

The column equation is as follows:

2x-4(200-x)=160

2x-800+4x=160

6x=960

x=160 so there are 160 chickens and 40 rabbits.

If the number of chickens is x, then the number of rabbits is 200-x.

It can be obtained according to the title.

2x-4（200-x）=160

2x-800+4x=160

6x=960

x=160200-160=40.

A: The number of chickens is 160 and the number of rabbits is 40.

Chickens and rabbits in the same cage is one of the famous interesting topics in ancient China, which is recorded in the "Sun Tzu Sutra". The problem of chickens and rabbits in the same cage is a common question type in the Mathematics Olympiad in primary schools. Many elementary school arithmetic problems can be transformed into this type of problem, or they can be solved in the typical way of solving it"Hypothetical method"to solve.

Therefore, it is necessary to learn its solutions and ideas. It is usually easier to understand by using the equation method or the hypothetical method.

It is known that the total number of heads and the number of chicken legs are more than those of free legs, ask how many chickens and rabbits there are.

Number of chickens = (4 times the total number of heads + number of feet apart) 6

Number of rabbits = total number of heads - number of chickens = total number of heads - (4 times the total number of heads + number of different feet) 6 = (2 times the total number of heads - number of different feet) 6

Number of chicken feet = 2 times the number of chickens.

Number of rabbits = total number of heads - number of chickens.

Number of rabbit feet = 4 times the number of rabbits = 4 times (total number of heads - number of chickens) = 4 times the total number of heads - 4 times the number of chickens.

The number of feet = the number of chicken feet - the number of rabbit feet = 2 times the number of chickens - (4 times the total number of chickens - 4 times the number of chickens) = 6 times the number of chickens - 4 times the total number of heads.

6 times the number of chickens = 4 times the total number of heads + the number of different feet.

Number of chickens = (4 times the total number of heads + number of feet apart) 6

Number of rabbits = total number of heads - number of chickens = total number of heads - (4 times the total number of heads + number of different feet) 6 = (2 times the total number of heads - number of different feet) 6

Suppose the number of rabbits in it is x

Then the number of chickens is the total number of heads - x

The number of feet = the number of chicken feet - the number of rabbit feet = 2 (total number of heads - x) - 4x = 2 times the total number of heads - 6x

6x = 2 times the total number of heads - the number of feet in difference.

x = (2 times the total number of heads - the number of feet in difference) 6

Let's say the number of chickens in it is x

Then the number of rabbits is the total number of heads - x

The number of feet = the number of chicken feet - the number of rabbit feet = 2x-4 times (the total number of heads - x) = 6x - 4 times the total number of heads.

6x = 4 times the total number of heads + the number of different feet.

x = (4 times the total number of heads + the number of different legs) 6

Solution: Set x chickens and 200-x rabbits.

2x-（200-x）×4=160

2x-800+4x=160

6x=960

x=160200-160=40.

A: There are 160 chickens and 40 rabbits.

There are 160 chickens and rabbits and 40 rabbits.

Solution: There are x chickens and y rabbits.

Then x y 200

2x－4y＝160②

by Synoid x=160

y=40

Suppose the chicken 150, the rabbit 50, the number of chicken legs is 300, the number of rabbit legs is 200, the number of chicken legs is 100 more, according to the requirements of the number of chicken legs than the rabbit 160, that is, the chicken legs are more than 60, the chicken legs plus 2 rabbit legs minus 4, the total number is 6, so 60 divided by 6 is 10, so the chicken is 150 + 10 = 160, rabbit 50-10 = 40

Solution: Suppose it's all chickens.

There are 200 2 400 chicken feet and 0 rabbit feet.

There are 400 more chickens than rabbits.

In fact, there are only 160 more.

The difference between the two is 400-160 240 chickens, and after each chicken is replaced by rabbits, the difference between the two is 4+2 6 birds.

240 6 40, that is, the number of rabbits.

The number of chickens is 200-40 160.

Let's say it's all chickens.

200 chicken feet 2 400 pcs, rabbit feet 0 pcs.

There are 400 more chickens than rabbit feet.

There are actually 160 more.

The difference between the two is 240, and after the chickens are replaced by rabbits, the difference between the two is 6.

240 6 40, that is, the number of rabbits.

The number of chickens is 200-40 160.

Assuming there are x chickens and 200-x rabbits, there are:

Number of chicken's feet: 2x

Number of feet of rabbit: 4 (200-x).

The column equation is as follows:

2x-4(200-x)=160

2x-800+4x=160

6x=960

x=160 so there are 160 chickens and 40 rabbits.

The extra 160 chicken feet are 80 chickens, and another 120 are chicken rabbits, where the rabbit feet are twice as large as the chicken feet, i.e. 80 chicken legs and 40 legs. Answer: 160 chickens, 40 rabbits.

Solution: If there are x chickens, then rabbits have ((200-x), according to the title:

2x-4(200-x)=160

Solve this equation to get:

x=160200-x=40

A: There are 160 chickens and 40 rabbits.

There are 200 chickens and rabbits, 160 more chickens than rabbits, 80 chickens and 120 rabbits.

Rabbit: (200x2-160) (4-2).

120 (only).

Chickens: 200-120 = 80 (pcs).

If they are all chickens, there are 200*2=400 feet.

then there are more chickens (400-160) 2=120.

So chickens have 120 + (200-120) 2 = 160 and rabbits have 200-160 = 40.