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Common human genetic diseases:
Often: syndactyly, polydactyly, achondroplasia.
Often: albinism, congenital deafness, phenylketonuria, sickle anemia.
X shows: with vitamin D rickets, some familial chronic nephritis.
X-hidden: red-green color blindness, hemophilia, progressive muscular dystrophy.
Y: hirsutism of the external auditory canal.
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Albinism is often hidden.
Rickets is x-shown.
Red-green color blindness is x-hidden.
Some of the questions will prompt you, but the main ones are these 3.
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Albinism Rickets is autosome, while color blindness is recessive on the X chromosome.
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1. All X chromosome dominant inheritance: anti-vitamin D, rickets, etc.
X-chromosome recessive inheritance: human red-green color blindness, hemophilia.
Y-chromosome inheritance: human hairy ear phenomenon (hirsutism of the external auditory canal) autosomal dominant inheritance: syndactyly, polydactyly, achondroplasia autosomal recessive inheritance:
Phenylketonuria, albinism, congenital deafness, sickle cell anemia, polygenic genetic diseases: cleft lip, anencephaly, essential hypertension, juvenile diabetes chromosomal abnormalities, genetic diseases: trisomy 21, meow syndrome, gonadal dysplasia, etc.
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With X recessive disease: red light color blindness in humans, hemophilia.
With X-dominant disease: antivitamin D rickets, hereditary chronic nephritis.
Autosomal dominant: syndactyly, polydactyly, achondroplasia.
Autosomal recessive: phenylketonuria, albinism, congenital deafness, sickle cell anemia.
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Red-green color blindness.
Blood type: red eyes and white eyes.
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This refers to the genetic determination of a genetic disorder.
Creating something out of nothing is hidden] means that neither parent has the disease, but the child is sick. This indicates that the disease is recessive. Both parents are heterozygous and carry the disease.
Therefore, there is a 1 in 4 chance that a child will be recessively homozygous for the disease (ignoring the presence of the gene on the sex chromosomes).
There is no dominant middle birth] means that both parents suffer from this genetic disease, but children do not suffer from this disease. Indicates that the disease is dominantly inherited. Both parents are heterozygous.
Therefore, there is a 1 in 4 chance that a child will be recessively homozygous and not develop the disease. (Again, ignoring the chromosomes of the disease-causing gene).
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For example, it is possible for AA to have AA offspring, which is different from the phenotype of both parents, that is, "out of nothing", then A is a recessive gene.
There is no such thing as "there is no such thing......
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If horns are dominant and hornless are recessive, the genes of horned cattle are AA or AAThe genes of several pairs of horned cattle were aa, aa, and aaGenotypes AA and AA are horned offspring, and AA is hornless offspring.
If hornless is dominant and horned is recessive, then the genotypes of several pairs of horned cattle are all AA, and the genotypes of the offspring cattle are all AA and are horned.
So, there is a conclusion on the topic.
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There is a cross between two homozygous parents with a pair of relative traits, and their F1 exhibits exactly the same dominant trait as the dominant parent, and this dominant performance is called complete dominance.
After the hybridization of homozygous parents with relative traits, F1 showed an intermediate type. If a pair of alleles with a dominant recessive relationship interact with each other to produce an intermediate trait in between, i.e., the phenotype of heterozygous (aa) is lighter than that of homozygous (aa), for example, safflower (aa) is not completely dominant to white flower (aa), then the phenotype of (aa) is pink flower, which is incomplete dominance.
Incomplete dominance is also called semi-dominance.
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As shown in the figure, the female parents should be two heterozygous, so the ratio of AA to AA is 1:2, the male is AA, the probability of the child of these two people suffering from the disease controlled by A is 1 6, and H is inherited with sex, and the probability of disease is 1 2, so the probability of not suffering from both diseases is the product of the probability of not suffering from both diseases.
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