How do you convert a binary equation into a unitary equation?

A binary equation should have two formulas, (e.g. x y 5 and 5x 2y 16), then one of the equations is used to form an unknown element, and the other side is represented by an identity deformation of the other element (e.g. from x y 5 to x 5 y).

And then subpode this deformed equation into another equation that doesn't change, for example, x 5 y to 5x 2y 16.

5＊（5－y）＋2y＝16〕

Then the equation becomes a univariate equation.

For example, the above equation becomes 25, 5y, 2y, 163y, 9y, 3).

In the end, just find x and you're good to go.

Bringing in the elimination method: x+y=n 2x+2y=m can be seen to be x=m-y brought in to obtain n-y+2y=m (is a constant).

You can use addition, subtraction, and elimination: one of the equations has x+(-ny, and the other is x+(-my, which can be eliminated with 1-2 or 2-1 (which is constant).

Constants: Rational numbers such as fixed numerical values that do not change.

Thank you, please give points.

Take one of the unknowns and express it as a formula with another unknown, and then bring in another equation.

Binary Linear Equations.

There should be two formulas, (e.g. x y 5 and 5x 2y 16), then use one of the formulas to form an unknown element, and the other side is represented by the other element through the identity deformation, (e.g. from x y 5 to x 5 y).

And then the deformed equation is subtyped into another equation that does not change, for example, x 5 y to 5x 2y 16.

5＊（5－y）＋2y＝16〕

Then the equation becomes a univariate equation.

Finish. For example, the limb empty bibi formula above becomes 25 5y 2y 163y 9y 3).

In the end, just find x and you're good to go.

Match a quadratic equation of one element.

and then use the direct leveling method to solve the method.

1) Use the matching method.

Steps to solve a quadratic equation:

Reducing the original equation to a general form;

Both sides of the equation are divided by quadratic coefficients.

Make the quadratic term coefficient 1 and put the constant term.

Move to the right of the equation;

Both sides of the equation are widened at the same time to square half of the coefficient of the previous term;

The left side is matched into a perfectly flat way, and the right side is cautiously teased and envied into a constant;

Further, the solution of the equation is obtained by the direct open-level method, and if the right side is a non-negative number, then the equation has two real roots.

If the right side is a negative number, then the equation has a pair of conjugate imaginary roots.

2) The theoretical basis of the matching method is the perfect square formula.

Example of a matching method for solving a quadratic equation:

1. Unary equation: ax+b=0 (a, b is constant, and a≠0).

2. Binary linear equation: x=(-b (b -4ac)) 2a.

3. Unary quadratic equation: ax+bx+c=0(a≠0). where ax is called the quadratic term, and a is the quadratic coefficient; bx is called the primary term, and b is the coefficient of the primary term; c is called the sedan car as a constant term.

4. Ternary linear equation: ax+by+cz=d.

5. Linear equations:

1) The general formula: ax+by+c=0 (0 when a and b are different in hail) applies to all straight lines.

Straight line l1: a1x+b1y+c1=0

Straight line l2: a2x+b2y+c2=0

When two lines are parallel: a1 a2=b1 b2≠c1 c2

When two straight lines are perpendicular: a1a2+b1b2=0

When two straight lines coincide: a1 a2=b1 b2=c1 c2

When two straight lines intersect: a1 a2≠ b1 b2

2) Point oblique: Knowing that there is a point on the line (x0, y0), and the slope k of the line exists, then the line can be expressed as y-y0=k(x-x0). When k does not exist, a straight line can be represented as x=x0

3) Intercept type: If the straight line intersects with the x-axis at (a, 0) and the y-axis at (0, b), then the straight line can be expressed as: x a+y b=1. Therefore, it does not apply to straight lines perpendicular to any coordinate axis and straight lines that cross the origin.

1. Unary linear equation: ax+b=0 (a, b is a constant pants, and a≠0) 2. Binary linear equation: x=(-b (b -4ac)) 2a.

3. Unary Erhu Zhengci equation: ax+bx+c=0(a≠0). where ax is called the quadratic term, and a is the quadratic coefficient; bx is called the primary term movement, and b is the primary term coefficient; c is called a constant term.

4. Ternary linear equation: ax+by+cz=d.

15 x 2 steps to solve the equation:

1. Move 15 to the right of the equal sign.

x＝2－15

2. Calculate the subtraction.

x 133, remove the negative sign of x.

The x 13 unary equation is the simplest equation, and it is relatively simple to solve the equation and the equation.

An equation must be an equation, but an equation is not necessarily an equation.

Basis for solving the equation:

Shift term: Move some terms in the equation from one side of the equation to the other with the previous symbol, and add and subtract, subtract and add, multiply and divide, and divide by multiplication.

Steps to solve the equation:

Method 1: 1. Calculate first; 2.Convert – Calculate – Result.

Method 2: 2. Calculate from front to back, and you can calculate directly when there is only one number left.

Expansion information:By solving the equation, you can avoid the difficulty of reverse thinking, and directly list the equation containing the quantity you want to solve. Equations have a variety of forms, such as a one-dimensional one-dimensional equation, a binary one-dimensional space-space equation, a one-element quadratic equation, etc., and can also form a system of equations to solve multiple unknowns.

In mathematics, an equation is a statement that contains an equation that splits one or more variables. Solving the equation involves determining which values of the variable make the equation true. Variables are also known as unknowns, and the value of the unknowns that satisfies equality is called the solution of the equation.

1. Shift term change: move some terms in the equation from one side of the equation to the other side with the previous symbols, and add, subtract, subtract, multiply and divide, divide by multiplication;

2. The basic properties of the equation:

1) Add (or subtract) the same number or the same algebraic formula on both sides of the equation at the same time.

The result is still the equation. It is expressed in letters as: if a=b, c is a number or an algebraic formula.

2) Multiply or divide both sides of the equation by the same non-0 number, and the result is still the equation. It is expressed in letters as: if a=b, c is a number or an algebraic formula (not 0).

Binary Linear Equations. General solution:

Elimination: Eliminate the number of unknowns in the equation system from more to less, and solve them one by one.

There are two ways to eliminate the element:

1. Substitute the elimination element.

Example: Solve the system of equations x+y=5 6x+13y=89

Solution: Bring in from x=5-y, get 6(5-y)+13y=89, and get y=59 7

Bring y=59 7 to get x=5-59 7, i.e. x=-24 7

x=-24/7，y=59/7

This solution is the substitution method of elimination.

2. Addition and subtraction.

Example: Solve a system of equations x+y=9 x-y=5

Solution: + gives 2x=14, i.e. x=7

Bring x=7 into to get 7+y=9, and solve y=2

x=7，y=2

This solution is the method of adding and subtracting the yuan.

The molecular part is changed to Xunfan element u= (x-t), t=x-u

lim ( x to 0 ) ue (x-u ) d (x-u ) x (3 2) commutation m= x tends to 0 + finishing.

lime m *lim (0 to m) 2u e (-u ) du m lim2m e (-m) 3m

Application skillsWhen we use the commutation method, we should follow the principle of being conducive to operation and standardization, and pay attention to the selection of the range of new variables after the commutation. As in the above examples, t>0 and sin [1,1].

You can first observe the equation, and you can find that the equation that requires the commutation method always contains the same formula, and then replace them with a letter to deduce the answer, and then if there is this letter in the answer, that is, bring the formula into it, and then it can be calculated.

The general form is ax +bx+c=0

It's okay to move to a forest.

The general form of this question is pure acres.

3x²+7x-1=0