How to get the same element in two vectors

The simplest and most complex method.

Iterate through each element of one vector and find the same in the other.

Compare occasionally, as Fifaboy says, and iterate over again.

If you use it more frequently and pay attention to efficiency, make an index, such as installing alphabetic or numeric sorting, and use binary search method, which is very fast.

This depends on your vector class design and **, of course, the standard C++ library has it.

If it's a standard library, you can write it like this:

vector v1, v2;

if vi==v2 true

else false;

If you want to write a function yourself:

bool equlvectror(vector pv1, vector pv2)

Hope it helps!

1. For example, the following html**, to get the number of elements a under the p element:

#father a").length2, as shown in html, if you want to get the number of li, you can use: $("ul > li").length;

"ul > li").length;

1. siblings(), which can return all sibling elements of the element.

2. next(), you can get the next sibling element of the current element.

3. nextall(), which can get all the following sibling elements of the current element.

4. nextuntil(), which can get all the following sibling elements between the two elements.

5. prev(), you can get the previous sibling element of the current element.

6. prevall(), which can get all the previous sibling elements of the current element.

7. prevuntil(), which can get all the previous sibling elements between the two elements.

$(".Parent elementChild elements").length;This is the number of child elements.

It can also be changed to id or directly with the label name, if you want to manipulate each child element, it should involve the closure problem.

Implementation idea: Use the length attribute of jquery to get the number of elements in the object, $(selector)length。An example is as follows:

1. HTML structure: There are 4 list elements glen under UL with ID as test

tanejohn

2. jquery**: Click on the list to get the number of li $(function(){

#test").click(function() alert($("#test li").length);Obtain the number of LI elements in UL with the ID of test.

3. Effect demonstration:

If you know which object you want to fetch you can use instanceof to determine the same property and then add another vector to the original array.

Method 1 Use the built-in function array intersect array array intersect ( array $array 1 , array $array 2 [,array $ to calculate the intersection of the array, and return an array that contains all the values that appear in the array of all other parameters at the same time, and method 2 is to write it myself, I spent half an hour on the computer to do the following detection, I hope it will be useful to youcount($arr2))?count($arr2):

count($arr1);//echo $num;for($i=0;$i\".$arr1[$i].\"and the second of the array".

j+1).\"elements = >".$arr1[$i];?

? echo \"\";?

And the result obtained after the test is in line with the attachment haha gold coin[[i] This post was last published by fanglq04 on 2009-3-20 17:58 [ i]].

This is enough to make a two-layer loop comparison.

Visually this is ...... comparing the sizes of the two vectors to see if they are equal