Iron, elemental, chemical compounds, chemical reactions, relationships with the human body, relation

Iron is an indispensable element of hemoglobin in human blood, and if there is a lack of iron, you will get iron deficiency anemia, but after all, iron is only a trace element in the human body, and it is not allowed to be excessive, and it is easy to get bone cancer if there is too much iron in the human body. In plants, iron is an enzyme that is required to participate in the process of photosynthesis and respiration. In addition, although iron is not a component of chlorophyll, it is indispensable in the synthesis of chlorophyll.

Because in the synthesis process of chlorophyll, the catalytic effect of iron redox protein and cis-aconitase is required to proceed smoothly.

(1) The relative molecular mass of ferrous sulfate is 56 + 32 + 16 4 = 152 (2) The mass ratio of iron, sulfur and oxygen in ferrous sulfate is 56:32:(16 4)=7:4:8

3) The mass fraction of iron element in ferrous sulfate is 56

4) Mass of elemental iron that can be supplemented per day = 152mg 3 (5), and the mass fraction of elemental iron in each ferrous sulfate tablet = 152mg 300mg

So the answer is: (1) 152; （2）7：4：8；（3）；(4) The mass of iron that can be supplemented every day = 152mg 3, and the mass fraction of iron in each ferrous sulfate tablet = 152mg 300mg

Elemental Fe can be converted to +2-valent Fe2++2 valence iron with a strong oxidant such as Cl2, which can be converted to +3-valent Fe3+, and in turn, Fe3+ can be added to reducing agent to obtain Fe2+, and Fe2+ can be obtained by adding reducing agent

Elemental Fe can be directly oxidized to Fe3+, and Fe3+ can be directly reduced to elemental Fe, that is, Fe in the three valence states can be converted into each other.

1) Known: 3Fe(S)+2O2

g）═fe3

o4s）△h1

2h2g）+o2

g）═2h2

o（g）△h2

According to Gaisce's law, it can be seen that - 2 gets:

3fe（s）+4h2

o（g）═fe3

o4s）+4h2

g）△hh=△h 1

2△；So the answer is:;

2) The amount of water to be transformed when equilibrium is reached in the container is xmol, 3Fe(S)+4H2

0（g）?fe3

o4s）+4h2

g) Initial amount (mol): 1 1 1 1

Conversion (mol): x Disperse lead x

Equilibrium (mol): 1-x 1+x then k = ch

cho)(1+x)

1?x)16, so x=1

then a container in h2

o has a balanced conversion rate of 1

100%=, so the answer is:;

a. The reaction is a reaction with the same volume of gas, so the pressure in the container is always simple and unchanged, and the equilibrium state cannot be judged by the pressure, so A is wrong;

b. The density of water vapor is different from the density of hydrogen, so when the density in the container is unchanged, it is in an equilibrium state, so B is correct;

c. Let the water in B convert xmol, then (1+x

xk=16, then x=, so the conversion rate of water in B is .

100%=, so it is greater than the conversion rate in A, so c is wrong;

d. The balance of the increased solids does not move, so the conversion rate of water remains unchanged, so D is wrong;

So the answer is: b;

4) Since the volume of the gas before and after the reaction is equal, the equilibrium does not move under condition c, and the volume fraction of hydrogen is the same as the equilibrium; Under condition A, the reaction is carried out in the forward direction to generate hydrogen, and the reaction releases heat to increase the temperature of the container, inhibiting the reaction to continue to generate hydrogen, so the integral number of hydrogen gas is low, and in the case of B, the reaction is reversed to generate Fe and water, which is an endothermic process, which reduces the temperature of the container and inhibits the reaction to continue to consume hydrogen, so the volume fraction of hydrogen is higher in the early mining period, so H2

The percentages are listed in descending order: b c a;

So the answer is: b c a;

4) According to the diagram analysis, the oxidation reaction occurs when methanol loses electrons at the negative electrode, and the electrode reaction that occurs when molten salt is used as electrolyte is: CH3

oh-6e-

3o2-co2

2h2o；So the answer is: CH3

oh-6e-

3o2-co2

2h2o．

According to the diagram, it can be seen that there are many substances that react with D, and from the information in the stem, it can be seen that there may be many types of these substances, so it is conjectured that D is an acid, and it is assumed to be hydrochloric acid

Verification shows that the setting meets the above requirements;

1) The chemical formula of substance D is HCl;

2) E is calcium oxide, which is mainly used as a desiccant;

3) The reaction between A and D is the process of iron and hydrochloric acid to produce ferrous chloride and hydrogen, and the reactants and products of the reaction are all a replanted element and a compound, so the reaction belongs to the displacement reaction;

4) The chemical equation for the reaction between b and d is: fe2

o36hcl=2fecl33h2o；

5) The chemical equation for f g is: CO2

CA (Oak Hunger OH) 2

caco3+h2

o；Therefore, the answer is: (1) HCL; (2) To make desiccant, etc.; (3) displacement reaction; （4）fe2

o36hcl=2fecl3

3h2o；（5）co2

ca（oh）2

caco3+h2o；

Elemental silvery-white.

Rust reddish-brown.

Iron hydroxide reddish-brown.

Ferrous sulphate light green.

Iron oxide red.

Ferric tetroxide black.

Iron sulphate yellow.

The dissolution of ferric ions is green.

The ferric ions are yellow in the middle of the night.

There are three types of positive bivalent (FeO), positive trivalent (Fe2O3), and positive hexavalent (Na2FeO4).

Elemental silvery-white.

Rust reddish-brown.

Iron hydroxide reddish-brown.

Ferrous sulphate light green.

Iron oxide red.

Ferric tetroxide black.

Iron sulphate yellow.

The dissolution of ferric ions is green.

The ferric ions are yellow in the middle of the night.

1.Iron rust (2Fe+O2+2H2O=2Fe(OH)2 4Fe(OH)2+O2+2H2O=4Fe(OH)3 2Fe(OH)3=Fe2O3+3H2O) changes from 0 valence to +3 valence.

2.The burning of iron wire in oxygen [3Fe + 2O2 (ignition) = Fe3O4] changes from 0 valence to +2 and +3 valence.

3.Blast furnace ironmaking [The principle of ironmaking is the reduction of iron oxides in iron ore to metallic iron with a reducing agent. Iron oxides (Fe2O3, Fe3O4, FeO) + reducing agents (C, Co, H2) Iron (Fe) changes from +2 and +3 valence to 0 valence.

4.The reaction of iron with dilute sulfuric acid (Fe+H2SO4=FeSO4+H2) changes from 0 valence to +2 valence.

Guo Dunyun: The three ferrites should refer to: metallic iron Fe, hematite Fe, magnetite ferric tetroxide FeO, ferric tetroxide Fe O is the compound of iron oxide FeO and ferric oxide Fe O (Fe O = Feo + Fe O), and the main chemical reaction in pig iron metallurgy is the reduction of Feo and Fe O

2FeO+C 2Fe+Co at high temperature, FeO+Co Fe+ Co;

2Fe O +3C 4Fe + 3Co at high temperature, Fe O +Co 2Feo + Co

Chemical changes in iron rust: jujube burning.

Iron rust is the result of the action of iron in the humid air, which produces a new substance, rust (Fe2O3).

Fe2 2OH Fe(OH)2 , Fe(OH2) are oxidized by air to form Fe(OH)3, 4Fe(OH)2 O2 2H2O 4Fe(OH)3, Fe(OH)3 is unstable, and the slow decomposition reaction occurs under sunlight to form Fe2O3:

2fe(oh)3＝fe2o3＋3h2o。

In general, the chemical reaction equation is: 4Fe + 3O2 + XH2O = 2Fe2O3·XH2O.

Formation of ferric tetroxide fe o in roasted orchid:

Iron is burned in oxygen to form ferric oxide 2o +3fe = ignition = fe o, and water vapor reacts with red-hot iron to form ferric oxide 4h o + 3fe = high temperature = fe o +4h.