There are 35 chickens and rabbits, and 94 chicken legs and rabbit legs.

x+y=35

2x+4y=94

x = 23 chickens.

y=12 rabbits.

Set: There are x chickens, because there are 35 chickens and rabbits, so there are rabbits.

35 x) only.

There are 2x chicken legs and 4 rabbit legs (35 x).

2x＋4（35－x）＝94

Solve x 23

So there are 23 chickens and 12 rabbits.

If there are x chickens, then there are 35 x rabbits. Let the equation be: 2x+(35-x)*4 94

x 23 There are 23 chickens, exempt 12 chickens.

Set: There are x chickens, because there are 35 chickens and rabbits, so there are rabbits.

35 x) only.

There are 2x chicken legs and 4 rabbit legs (35 x).

2x＋4（35－x）＝94

Solve x 23

So there are 23 chickens and 12 rabbits.

Dizzy. If there are x chickens, then there are 35 x rabbits. Let the equation be: 2x+(35-x)*4 94

x 23 There are 23 chickens, exempt 12 chickens.

Untie. Set rabbit x and chicken y.

x+y=35 ①

4x+2y=94②

Replace *2.

2x+2y=70③

Will - got.

x=12y=23

Assuming that it is a chicken, the source should be 35 * 2 = 70 At this time, the extra legs are all rabbits, and the other remaining legs are the extra legs of rabbits, each rabbit has two more legs, and the total number of rabbits is the number of rabbits.

Rabbit (94-70) 2=12

Chicken 35-12=23

This can also be the equation to solve the hail.

Let the chickens be x and the rabbits will be (35-x).

2x+4(35-x)=94

Organize the equations.

4x-2x ＝4*35-94

2x=46x＝23

Hypothesis: It's all rabbits.

Chicken: 46 (4 2) 23

Rabbit: 35 23 12

Looking at the above back, there is a list of equations, what are you doing, in fact, the oral calculation is out, and the idea is as follows:

Chicken has 2 legs, rabbit has 4 legs, that is to say, a rabbit has 2 more legs than a chicken, now we assume that rabbits are also two legs, then 35 chickens and rabbits should be 70 legs, but the title says that there are 94 in total, and the extra 94-70=24 legs are rabbits, and each rabbit has 2 more legs, then 24 2=12, which is the number of rabbits.

So 12 rabbits and 23 chickens.

Got it.

Let the chicken be a and the rabbit be b, so a+b=35, 2a+4b=94, you can solve the equation, and after the solution, you can get a=23, b=12, so the chickens are 23 and the rabbits are 12.

23 chickens and 12 ducks.

Suppose chickens x ducks are 35-x ducks.

then 2x+4*(35-x)=94

The solution is x=23 35-23=12

Let there be x chickens and y rabbits, and establish the equation:

x+y=35

2x+4y=94

Solve the equation to obtain: x=23 y=12

Rabbits have (264 100 2) (4 2) = 32 and chickens have 100 32 68 It can also be solved by setting a system of binary equations.

Let the chicken be x and the rabbit be y, then we can get the formula: x+y=35 and 2x+4y=94. Then just solve the equation. Note that the chicken has two legs so 2x, and the same goes for rabbits.

Twelve rabbits, 48 legs, twenty-three chickens, 46 legs, adding up to just 94 legs.

If there are x chickens, then there are 35-x rabbits.

then 2x+4*(35-x)=94

i.e. -2x+120=94

i.e. 2x=26

The solution is x=13

So there were 13 chickens and 24 rabbits.

264 divided by 2 equals 132, 132-100 = 32, 32 is a rabbit and 132 is a chicken.

Assuming that it is all chickens, then the rabbit has a sensitive appearance: pretending to be leaky.

94-35 2) (4-2), 24 2, 12 (only);

Chickens have: 35-12 = 23 (only).

Answer: There are 23 chickens and 12 rabbits