Minghu Elementary School held a mathematics competition, and the number of students who passed in th

Without equation: ((23+30+15) 2)*5 170 people.

The second time the failure is less than 15, its 2 times is less than 30, the number of passing is still 2 times the number of 53 people who failed, plus the 15 people who failed to pass, it is 2 times more than 68 people, these 68 people are 2 times the second failure, the failure is 34 people, the total number is 170

Using the equation, let the second time fail x people, 4x-[2*(x+15)+23]=15 after solving x 34, the total number of people is x+4x 5x, and the total number of people is 170

Solution: If the number of people who fail in the preliminary round is x, the number of people who pass is 2x+23 (the number of people who pass in the preliminary round is 2 times more than 23 times the number of people who fail).

2x+23)+15=4(x-15) (the number of passers increased by 15 at the rematch, exactly four times the number of failers).

Solution x=49

Number of participants: 49 * 2 + 23 + 49 = 170 people.

A: A total of 170 people participated in the competition.

Hope to score, thank you.

If the number of failers in the preliminary round is x, then the number of passers can be set to 2x+23 according to the question

If the number of passers increases by 15 and is 4 times the number of failers in the semi-finals, then the equation can be listed.

2x+23+15=4（x-15）

Set the number of people who fail the preliminary round as x the number of people who fail the preliminary round: the number of passers 2x+23 The total number of participants is x+2x+23 When the semi-finals are set, the number of passers is 2x+23+15 The number of people who fail is:

2x+23+15) 4 So we get: x+2x+23=(2x+23+15)x(1+1 4) 3x+23= x=49 So a total of 170 people participate in the competition.

The number of participants in the contest was 60

8 (person) 8 8-4 = 60 (person).

The Law of Division:

From the high position of the dividend, first see how many digits there are in the divisor, then try to divide the first digits of the dividend with the divisor, and if it is smaller than the divisor, try to divide by one more digit;

Divide to the one whose dividend is divided, and write the quotient on that one;

The dividend expands (shrinks) n times, and the divisor does not change, and the quotient expands (shrinks) n times accordingly.

The divisor expands (shrinks) n times, and the dividend remains unchanged, and the quotient shrinks (expands) n times accordingly.

The dividend, divided by two divisors consecutively, is equal to the product of the two divisors. Sometimes simple operations can be performed depending on the nature of division. For example: 300 25 4 = 300 (25 4) divided by a number = the reciprocal of this number.

（68+4）÷（8+1）

72 9,8 (person).

8 8-4 = 60 (person).

A: The number of participants in the competition is 60

If the number of people who won the first and second prizes accounted for 3 4 of the total number of winners, the number of people who won the second and third prizes accounted for 5 6 of the total number of winners, and the number of people who won the second prize accounted for a fraction of the total number of people?

This question is also a "chicken and rabbit in the same cage" problem.

Let's assume that all female students participate in the competition, and they can get 7000 points, which is 7000-6300 points more, because male students are counted as female students, and everyone counts 70-60 points more. In this way, the number of male classmates can be calculated, and then the number of female classmates can be calculated.

Calculation pattern: (70*100-63*100) (70-60)=700 10

70 (person) 100-70 = 30 (person).

There are 70 boys and 30 girls.

Male + Female = 100 people.

60x Male + 70x Female = 63x100

100 63 7000 70 = 100 people.

100-70 = 30 people - girls.

100-30 = 70 people - boys.

A: There are 70 boys and 30 girls.

The number of people who failed in the preliminary round is 1 4 of the number of passers, that is, the ratio of the number of people who failed in the preliminary round to the number of people who passed is 1:4, that is, the number of people who pass is 4/4 of the total number of people (1+4), and it is 4 5 if you are not sleepy. The number of people who passed the semi-finals accounted for 6 7 of the total number of people.

X is used to represent the total number of invariant sixth grades, the number of people who pass the preliminary round is 4 5x, the number of people who pass the semi-finals is 6 7x, and the difference between the two is 22.

Solution: There are a total of x people in the sixth grade.

6/7x-4/5x=22

2/35x=22

x=385

6, that is, the ratio of the number of people who failed the preliminary round to the number of people who passed is 1, and the number of people who passed the semi-finals is 6: Zheng Lian has a total of x people in the sixth grade.

Solution: 4; 5x;7, the number of people who pass the repetition series competition accounts for 6 7x of the total number of people, and the difference between the two is 22, that is, the number of people who pass accounts for 4 of the total number of people (1 + 4), and the number of people who pass the preliminary round is 4, that is, 4 5x = 22

2/。In the same way, the number of people who fail in the preliminary round is 1 of the number of passers: 35x=22x=385A. X is used to denote the total number of invariant sixth graders; 7x—4/

5, the total number of people who pass the station is 4 5

Semi-finals: Failure accounts for 1:22 * (6 7: omitted, all the number of passing stations 6 7 total number; 7-4 5) = 385 (human scattered nucleus).

Answer: Caution in the preliminary round: Failure accounts for 1 of the total number of people

Guangming Primary School held a mathematics competition, and the number of students who passed in the preliminary round was 23 times more than twice the number of students who failed, and the number of students who passed in the second round increased by 15, which was exactly four times the number of people who failed. How many people participated in the celebration competition? Tachibana early (equation Lao Wu grip solution).

2x+23+15=(2x+23+x-2x+23+15)*4

The questions are incomplete, please

If the number of people who fail the preliminary round is x, the number of people who pass the preliminary round is 2x+23, that is, the number of participants in the semi-finals is 2x+23, and the number of people who fail in the semi-finals is x+15=4x, and the number of people who fail the preliminary round is x=5, that is, the number of people who fail the preliminary round is 5, and the number of people who pass the preliminary round is 2*5+23=33, and a total of 33 people participate in the competition.

Set the number of failers to x

The number of people who pass the preliminary round is 2x+23

So x+15=4x

x=5, so the total number of people is x+2x+23=38

Solution: Set the number of students who fail to x

then x+15=4x

x = 5 total number of people 5 + 5 * 2 + 23 = 38 "people".

Set the number of students who fail the preliminary round to x

Preliminary round: 2x+23 passers

The total number of participants is x+2x+23

In the semi-finals: the number of qualified students is 2x+23+15

The number of students who fail is: (2x+23+15) 4

Therefore, we get: x+2x+23=(2x+23+15)x(1+1 4)3x+23=

x=49, so a total of 170 people participated in the competition.

Solution: The number of people who fail in the preliminary round is x, 2x+23+15 4 (x 15).

2x+38＝4x－60

x 4949 + 49 * 2 + 23 147 + 23 170 (person).

The number of people who fail the preliminary round is x, x+2x+23=(x-15)*5, x=49, and the total number of students is 170

Solution: Set the number of students who fail to X people.

The total number of people in the preliminary round is 2x+23+x (people).

The number of qualified students in the semi-finals is 2x+23+15 (people); If the number of students who fail is x-15 (person), then 2x+23+15=4*(x-15).

x=49 The total number of people is: 2x+23+x=170 (people).

A: A total of 170 people participated in the competition.

Solution: The number of people who fail in the preliminary round is x

2x+23+15=4(x-15)

Solution x=49

Total number of people = 49x2 + 23 + 49 = 170

Answer...

Solution: Set the number of people who fail in the preliminary round as x

The equation is: x*2+23+15=(x-15)*42x+38=4x-60

2x=98x=49

According to the first condition, the number of passing students is 49 * 2 + 23 = 121 people 49 + 121 = 170 people.

A: A total of 170 people participated in the competition.

There are x people who fail in the preliminary round, and there are (2x+23) people who pass.

2x+23+15=4（x-15）

x=49, 2x+23=121, so the number of participants is 121+49=170.

If the number of people who fail the preliminary round is x, and the equation is 2x+23+15=4x, and the solution is x=19, then the number of passers is 57, and the total number of students is 76

Let the number of people who fail the first time be x

Then: 3x+4+5=6x

x = 3 and the number of people who pass for the first time is 3x + 4 = 13

The number of first-time participants is 3x+4+3=17

The number of people who pass for the second time is 13 + 5 = 18, the number of people who fail is 18 divided by 6 = 3, and the number of participants for the second time is 18 + 3 = 21

The total number of participants in the two times is 17 + 21 = 38

If the total number of people is regarded as a unit "1" (because the total number of people has not changed), the number of people who pass for the first time is 3 times more than 4 times the number of people who fail, and the number of people who pass for the second time is 6 times that of the number of people who fail, and it can be seen that the difference between the second time is 5 2 = 10 (people) compared with the first time

10-4 more = 6 people.

The first pass accounts for 3 4 of the total number of people, and the second time accounts for 6 7, so the total number of people: (5 2-4) (6 7-3 4) = 6 (3 28).

56 (person) The key to this question: find the fraction (3 28) corresponding to the partial quantity (6), and then you can find the quantity of the unit "1".

If there are x people who fail the first competition, the number of people who pass the first competition is (3x+4), and the total number of people is (3x+4)+x=4x+4 (people).

3x+4）+5=6x【4x+4—（3x+4+5）】3x+9=6x【4x+4—3x—9】

3x+9=6【x—5】

3x+9=6x—30

6x—3x=9+30

3x=39x=13

So the total number of participants in the math competition is 4x+4=4x13+4=56 (people).

Solution: For the first time, x people fail; It can be obtained according to the title.

Total number of people (3+1) x+4=(x-5) (6+1) gives x=13

Total number of people (3+1) 13+4=(13-5) (6+1)=56 (people).

If x people fail the first time, then 3x+4+5=6x solves, x=3 total number of people y=3x+4+x=16 people.