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Anonymous users2024-02-06Circumference formula: rectangle circumference = (length + width) 2 c = 2 (a + b) square perimeter = side length 4 c = 4a
Circumference of the circle = pi Diameter c = d c = 2 r circumference of the semicircle = half of the circumference of the circle + diameter r + d
Area formula: rectangular area = length and width s=ab
Square area = side length side length s=a2
Parallelogram area = base height s=ah
Triangle area = base height 2 s=ah 2
Trapezoidal area = (top bottom + bottom bottom) height 2 s = (a+b)h 2 area of the circle = pi square of the radius s = r2
The side area of the cylinder = the circumference of the bottom surface and the height s=ch
Surface area formula: cuboid surface area = (length and width + length and height + width and height) 2s = (ab + ah + bh) 2
Cube surface area = side length Side length 6 s=6a2
Cylindrical side area = bottom perimeter height s=c h
Cylinder surface area = side area + bottom area 2 s = s side + 2 s bottom.
Volume formula: cuboid volume = length width height v=abh cube volume = edge length edge length edge length v=a3
Cylinder volume = base area height v=sh
Approximately the cuboid is placed horizontally: cylinder volume = half of the side area radius v=ch 2 r=2 r 2 r= r r).
Cone volume = base area height 3 v = sh 3 or 1 3sh relation: Fraction application problem: The amount of the unit "1" Fraction rate (percentage) = corresponding quantity.
Known quantity Corresponding fraction (percentage) = quantity in unit "1".
Quantity of comparison The amount of unit "1" = fraction (percentage).
Engineering Issues: Productivity Working hours = total amount of work.
Total amount of work worked hours = work efficiency.
Total work efficiency = working hours.
Encounter Problem: Speed and Encounter Time = Distance.
Distance Speed and = Time of Encounter.
Distance Encounter time = speed and.
Normalization Question: Single Quantity Quantity = Total.
Total Quantity Single Quantity = Quantity.
Total quantity = single quantity.
Scale bar: Distance on the chart: Actual distance = scale.
Distance on the graph = actual distance scale.
Actual distance = distance on the graph scale.
Average: Total Total Copies = Average.
y proportional relation -=k (definite) inverse proportional: xy=k (definite) x
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Anonymous users2024-02-05List of Common Formulas in Primary School Mathematics Perimeter Formula: Rectangle Perimeter = (Length + Width) 2 C = 2 (A+B).
Square circumference = side length 4 c=4a
Circumference of the circle = pi Diameter c = d c = 2 r circumference of the semicircle = half of the circumference of the circle + diameter r + d
Area formula: rectangular area = length and width s=ab
Square area = side length side length s=a2
Parallelogram area = base height s=ah
Triangle area = base height 2 s=ah 2
Trapezoidal area = (top bottom + bottom bottom) height 2 s = (a+b)h 2 area of the circle = pi square of the radius s = r2
The side area of the cylinder = the circumference of the bottom surface and the height s=ch
Surface area formula: cuboid surface area = (length and width + length and height + width and height) 2s = (ab + ah + bh) 2
Cube surface area = side length Side length 6 s=6a2
Cylindrical side area = bottom perimeter height s=c h
Cylinder surface area = side area + bottom area 2 s = s side + 2 s bottom.
Volume formula: cuboid volume = length width height v=abh cube volume = edge length edge length edge length v=a3
Cylinder volume = base area height v=sh
Approximately the cuboid is placed horizontally: cylinder volume = half of the side area radius v=ch 2 r=2 r 2 r= r r).
Cone volume = base area height 3 v = sh 3 or 1 3sh relation: Fraction application problem: The amount of the unit "1" Fraction rate (percentage) = corresponding quantity.
Known quantity Corresponding fraction (percentage) = quantity in unit "1".
Quantity of comparison The amount of unit "1" = fraction (percentage).
Engineering Issues: Productivity Working hours = total amount of work.
Total amount of work worked hours = work efficiency.
Total work efficiency = working hours.
Encounter Problem: Speed and Encounter Time = Distance.
Distance Speed and = Time of Encounter.
Distance Encounter time = speed and.
Normalization Question: Single Quantity Quantity = Total.
Total Quantity Single Quantity = Quantity.
Total quantity = single quantity.
Scale bar: Distance on the chart: Actual distance = scale.
Distance on the graph = actual distance scale.
Actual distance = distance on the graph scale.
Average: Total Total Copies = Average.
y proportional relation -=k (definite) inverse proportional: xy=k (definite) x
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Anonymous users2024-02-04A list of commonly used formulas in primary school mathematics.
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Anonymous users2024-02-03Solution: Let the rectangle be long x cm and y cm wide.
Triangle EDC area = 10 square centimeters = 1 2x*y*1 2=xy 4xy=40
Rectangle area = xy = 40 square centimeters.
A: The area of the rectangle is 40 square centimeters.
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Anonymous users2024-02-02Please see the world quietly search for suspicion below, and click on the pat to enlarge:
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Anonymous users2024-02-01If there are x books for the lower grades, there will be 2x books for the upper grades.
The middle grade is divided into 3x-120 books.
then x+2x+3x-120=840
Solve the equation to get x=160
160 books for the lower grades.
360 books for middle grades.
320 books for senior grades.
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Anonymous users2024-01-31Solution: Let the lower grades be x
2x+3x-120+x=840
6x-120=840
6x=720
x=120 Upper grade: 2x=2x120=240
Intermediate grades: 3x-120
3x120-120
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Anonymous users2024-01-30Let the lower grades be x, so the upper grades will be 2x, and the middle grades will be 3x-120
It's 840 in total, so 840 = x + 3x - 120 + 2x gives x = 160 So 2x = 160 * 2 = 320 in the upper grade 3x-120 = 480-120 = 360 in the middle grade
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Anonymous users2024-01-29If the lower grade section is divided into x books, then the upper grade section is divided into 2x books, and the middle grade section is divided into (3x-120) books, which can be seen from the title, x+2x+(3x-120)=840, and the value of x can be obtained by solving. Then find out how many books each of the three grade levels will get.
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Anonymous users2024-01-28400 2=200 cm Find the sum of length and width first.
1. Width 400 2 (3 1) = 50 cm.
Length 50 3 = 150 cm.
2. Length: Width.
3+1=4 parts 3/4 of the length and 1/4 of the width
Width 200 1/4 = 50 cm.
Length 200 = 150 cm.
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Anonymous users2024-01-27Let the length be x and the width be y
x+y=400 m
x y=3 is calculated: x = 300m y = 100m
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Anonymous users2024-01-26400 divided by 2 = 200 (meters).
Width: 200 divided by 4 = 50 (meters).
Length: 50 times 3 = 150 (meters).
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Anonymous users2024-01-25400 2=200 is the length plus width 200 4=50 is the width and the length is three times the width The length is 150
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