Is there a relationship between the speed of the vehicle and the pressure of the vehicle on the grou

The upstairs duo are good, but lack comprehensiveness.

First of all, under ideal conditions, that is, the road surface is completely level, the car is stable and trembles, as mentioned by the two upstairs;

However, the pavement is not completely level, and the pavement is uneven. The faster you go, the more you can feel this. That is to say, a smooth driving vehicle, the pressure on the horizontal ground is different, the pressure of the protruding part is obviously higher, and the faster the speed, the greater the impact force, the greater the pressure, of course, the pressure of the concave part must be smaller.

As a result, the pressure on the pavement varies from place to place. For example, highways, especially airstrips, cannot use cement, the reason is that the cement has a joint, although this joint is small, it is enough to cause a major accident to high-speed objects. In fact, the road will have a certain service life, and its life is of course closely related to the road load, but the impact of speed is also crucial.

This means that the high speed will increase the load on the ground, which actually increases not only the friction on the ground (tangential), but also the positive pressure on the ground (normal).

Secondly, any vehicle, including all means of transportation, has a certain "chatter" in its driving, and this "chatter" exists in all directions, and with the increase of speed, the "chatter" is rapidly increasing. "Fluttering" not only forms a certain pressure on the ground, but as the two upstairs said, the car is very easy to be thrown. Here are two practical examples.

First, when the water in the water pipe flows, it has a certain "flutter", which is called "pulsation" in the industry, and the higher the flow rate of the water, the more obvious this pulsation phenomenon is, and its performance is that the water pipe is "shaking". This experiment can be easily verified. The second is the speed of the aircraft (in fact, it includes any means of transportation).

A new type of aircraft must be tested for its maximum speed (test flight), because when the speed of the aircraft exceeds a certain speed, the aircraft will "disintegrate" due to the "chatter" generated during flight. It's not a good experiment, of course, but you can ride a bike that's not very good, and when it's fast, you can see that the bike seems to be falling apart. Of course, you must pay attention to safety when doing this experiment, as long as you can experience it, you don't have to have a broken rack on the bike;

Finally, the road itself has a certain slope, and the pressure on the uphill slope is obviously greater than the pressure on the downhill, and the bend of the road will also have different pressures on the ground.

In short, the speed of the vehicle will have a certain effect on the pressure of the road surface, and the higher the speed, the influence will increase rapidly.

That's why speed limits are in place in many places, especially over important structures such as bridges (some of which are underground).

If friction is taken into account, it has an impact regardless of how the car is driven.

There is no when the pavement is absolutely level, but if the pavement is curved, there is.

The specific situation is analyzed by the relationship between the centripetal force and the velocity of the circular motion.

This has to do with the shape of the ground and is divided into three cases:

Type 1: Ground level.

Simplify the ground to a horizontal line.

At this point, the pressure of the vehicle on the ground is equal to its own gravitational force g!

The second type is that the ground is raised upwards (when going uphill to the top of the slope).

Simplify the ground into an upper semicircle.

Stress at this point is related to a variety of factors! Suppose the velocity of the car is v and the mass is m, the radius of the semicircle is rg is the gravitational constant, n is the ground support force on the car, and the magnitude of the force is equal to the pressure of the car on the ground.

The rook moves in a circular motion on top of a semicircular grip and is simplified to a circular motion at a constant speed.

Analysis of slag under force.

f (centripetal force.

The formula for calculating the centripetal force of mg-n: f (centripetal force) = m v v r pressure is: n = mg-m v v r is less than its own gravity.

The third type: the ground is concave downward (the car goes down to the bottom of the pit).

Simplify the ground into a lower semicircle.

Similar to the second but at this time.

f (centripetal force) = mg+n

The pressure is n=mg+mg-m v v r greater than its own gravity.

Note that the second and third cases of Duan Bichun can only be used when there is amplitude on the ground!

Whether the vehicle is driving or not, the pressure on the ground is its gravity.

The speed of the vehicle is too fast, especially the greater the impact force of the heavy vehicle on the bridge, and if the speed is too fast, the greater the vibration of the bridge, and the greater the damage to the beam under the large load of the heavy vehicle (also sometimes there will be resonance next to the nucleus). If it is a light car beam, the impact is less. Therefore, for the sake of safety, the vehicle is required to drive at a constant speed when crossing the bridge, and do not accelerate or brake on the bridge.

In particular, the over-duty vehicle crosses the bridge, and generally requires the vehicle speed to pass at a constant speed of 5 kilometers per hour.

The speed of the object wheel has nothing to do with the pressure of the car on the ground, and the vector direction of the two is curved and perpendicular.

The pressure of the car on the ground is only related to the weight of the body - -

To slow down for safety, too fast, the car will fly up, cover the letter to throw flat - the pressure is still the same, the gravitational acceleration is still g.

Drive too fast and throw the car away.