Inductive load motor, the current and voltage angle is 0,

The power factor is between 0 1, China stipulates: the power factor of electrical equipment should reach the above, less than the time to put in the compensation capacitor, the power factor is greater than or equal to, the compensation capacitor will be withdrawn from operation. Your current power factor is already very high, basically close to 1, that is to say, your reactive power is very small, almost none, and some meters will not be able to measure it, which is normal.

Only a single motor will have a "two incomplete star" theory, right? For example, a low-power three-phase motor, in which two phases are connected to the neutral line and the live wire, and the other phase and the first two phases (one of the phases) are connected to the capacitor (leap change, steering change) to form a "three-phase motor single-phase capacitor operation". If this is the case, the capacitor already has a "compensating effect", and it is possible to increase the power factor appropriately.

I don't know what kind of motor the motor is, and the AC induction motor is impossible to have a power factor (I don't know where this comes from?). Is it a meter measurement? Then this watch must be broken);

How can a magnetic field be generated without reactive current?

Is a two-phase incomplete star wiring --- a single-phase motor?

If the two-phase incomplete star wiring, the wiring coefficient is, then the relay protection value should be noted, and the current of phase B is not accurate.

What is the relationship between the output voltage of a synchronous alternator and the size of the load for an inductive load.

For the alternator, the heavier the load, the lower the output voltage, which means that in the case of resistive load or inductive load, because at this time, as the load increases, the voltage drop of the generator armature also increases, and the output terminal voltage will be reduced accordingly, and the voltage will be low; Especially in the case of inductive loads, the armature current will also generate a demagnetized armature reactive magnetic field, which will reduce the total magnetic flux and drop the output voltage more; However, in the case of capacitive loads, the situation is different, the armature reaction magnetic flux is magnetized at this time, which will increase the main magnetic flux, in addition to canceling the armature resistance voltage drop, it may also increase the output voltage.

The phase angle is not the same under the two loads, corresponding to hysteresis and lead.

It is known that the leakage rate of the motor power family is 250kw, the rated voltage is 6kv, the transformation ratio of the electric zhaozi current transformer is 50 5, and the rated current is. What is the current of the zero search sequence.

According to your description, to calculate the zero sequence current, you need to know the phasor and vector diagram of the motor, as well as the method of calculating the current. Generally speaking, the current vector of a motor is composed of three phase current vectors, while the zero-sequence current vector is the sum of the vectors of the three phase current vectors, and the calculation method is as follows:1

Calculate the single-phase voltage: the rated voltage of the motor is 6kv, because the three are symmetrical, so the single-phase voltage is 6 3= calculate the single-phase rated current: the rated power of the motor is 250kw, the rated voltage is 6kv, and the power factor is taken, then the single-phase rated current is 250 (3 6.

3.Calculate the zero sequence current: From the question, it can be seen that the transformation ratio of the current transformer is 50 5, then the actual current is 1 10 of the rated current, that is.

Therefore, if the iron loss of the motor is ignored, and the three-phase currents are i 1, i 2, and i 3 respectively, then the zero sequence current i 0=(i 1+i 2+i 3) 3=(Qi coarse bi 3. It should be noted that in the actual operation of the motor, the actual zero sequence current will be different due to the different electromagnetic properties and working conditions of the motor. In the actual electrical design, it is necessary to calculate and analyze according to the actual situation to ensure the safe and stable operation of the motor.

The relationship between the terminal voltage and the induced electromotive force of the DC generator during normal operation is ().

a.The terminal voltage is greater than the induced wide collapse electromotive force.

b.The terminal voltage is less than the induced electromotive force.

c.The terminal voltage is equal to the inductive code balance momentum.

d.It is impossible to judge.

Correct Answer: The terminal delay is less than the induced electromotive force.

The load is gradually adjusted from the resistive inductive load to the resistive electric guest negative rent early load, and how the generator stool state should be adjusted, how the no-load potential of the generator, and the armature current will change.

Hello dear dear, I'm glad to answer for you The load is gradually adjusted by the resistance inductance xing load to the resistance electric customer xing load, try to ask how the generator should be adjusted by renting, how the generator no-load potential, armature current will change, according to the relevant questions for your characteristics to answer as follows: after the generator is loaded with the load (see synchronous generator armature reaction), the three-phase armature current works together to produce the armature magnetic potential fa, and the person will have an impact on the excitation potential f,, called the armature reaction, Usually the load is r-l load, the armature reaction result makes the air gap magnetic grip weaken early, so the terminal voltage will be reduced, the load is a capacitive load, the armature reaction result makes the air gap magnetically enhanced, so the terminal voltage will increase, the load size is different segment type, the armature reaction size is different, so the terminal voltage is different, in order to keep the terminal voltage constant, it is necessary to adjust the rotor excitation current from time to time to overcome the influence of the armature magnetic potential and keep the terminal voltage constant. When the stator of the tun machine three symmetrical tun pivot tun flow through the tun pivot winding, the rotating tun pivot magnetic potential Fa, F" will produce an armature reaction effect on the rotor magnetic potential r, so that the air gap magnetic flux (1 child changes, the induced electric potential E in the phase winding changes, so the generator terminal voltage is unstable.