Is the current of a 1 kW motor driven by a voltage of 380 the same as a current of 10 kW, and why?

No other factors are taken into account.

Current is equal to power divided by voltage.

Arithmetic knowledge: the larger the dividend, the greater its quotient.

So: the current of a 1 kilowatt motor cannot be the same as that of a 10 kilowatt motor.

The current of a 1 kW motor is 2A, and the current of 10 kW is 20A

Of course it's different. p=ui so i=p u

It should be said that there is a difference, I think the current you are talking about should be "no-load current", the motor with larger power does not have to be larger than the motor with small power, because the motor winding form of 1 kilowatt is relatively simple, and the quality of the core is not as good as that of the large motor, which is iron loss. In addition, the core cross-sectional area of the 1 kilowatt motor is small, the number of windings will be more, and the wire diameter will be thinner. A large number of turns and a thin wire diameter will increase the "DC resistance".

This is known as copper loss. The larger power of the motor wire diameter is thicker and the number of turns is less, the DC resistance will be smaller, the copper loss will be smaller, in addition, the 10 kilowatt motor is generally a "double winding", its electromagnetic conversion efficiency will be high. In this way, the no-load current of a large motor will be less than that of a small motor?

Not necessarily, because when the motor is large to a certain extent, the friction will increase, and the no-load current will also increase. It may be a bit vague for me to say this. But it is true, and in the end, your question --- the "no-load current" of a 1 kW motor and a 10 kW motor is definitely not the same.

The rated current is generally calculated by the following formula:

Rated current = rated power Rated voltage (i=p u), for three-phase 380v motor, p= cos, p is the rated power, u is the rated voltage, i is the rated current, cos is the power factor, i=p

So the rated current of the 1kW motor at 380V is i=p.

Hello. The rated current of the 380 volt 1 kW motor is ampere. (。

The calculation formula is as follows:

Current = Power (1000W) Voltage (380V) Power Factor.

What exactly is the current and the power factor.

The relationship is quite large, assuming that the power factor is taken.

Current = 1000 380 .

p = three-phase motor current = power voltage power factor (rated current takes three-phase motor current = 1000 amperes.)

Let's calculate, for a three-phase 380V motor, P= COS, P is the rated power, U is the rated voltage, I is the rated current, COS is the power factor, and I=P COS = 1000.

For a three-phase 380V motor, it can be estimated at 1 ampere per kilowatt.

The voltage of 220 volts is a single-phase power supply, and the power of 1,000 watts (1000 220 = the calculated current is 4.55, but the actual voltage is about six. 380 volts is the current of the three-phase point, and the working current of each phase is 1.93 ampere, and the power consumption is about 2 amperes.

Given a relationship between wattage, current and voltage, you can calculate the current of any appliance at will. Current = Wattage voltage. For example:

1000 watts of 220 volt ampere. The same goes for 380 volts, 1000 watts 380 volt amperes. A current is commonly known as a current, and the current unit does not matter", on"Ann , with letters"a Indicated.

Small current, expressed in milliamps, letters.

1 kilowatt current of 220V power supply pure resistance equipment, generally estimated according to 1 kilowatt five ampere current, for power equipment due to the influence of reactive power, the current will be much larger, can be estimated according to 8 10A per kilowatt (the motor current with small power is large).

Single-phase resistive load 1kw current, inductive load 8 currents.

The rated current of the motor with a voltage of 380V and 15kW is the rated current, which is generally calculated by the following formula:

Rated current = rated power Rated voltage (i=p u) p - rated power of the motor.

u-Motor line voltage.

Rated current refers to the current when the electrical equipment operates at the rated voltage and according to the rated power. It can also be defined as the current at which electrical equipment can work continuously for a long time under rated environmental conditions (ambient temperature, sunlight, altitude, installation conditions, etc.). The current of the appliance should not exceed its rated current when it is working normally.

From the formula of three-phase motor: p=

So the rated current of the power i=p ,cos is. The voltage is 380V.

Simple calculation: 3000 3 = 1000 (380 2) = roughly between 6 and 6.6 amps.

If the motor adaptation voltage is 380 volts two-phase electric operation, 3000 380= The operating current is about nine amperes.

The calculated answer is:

In a purely resistive circuit, according to Ohm's law, U=IR is substituted into P=UI, and P=I2R=(U2) R can also be obtained

For a resistive load in a single-phase power supply, the current is calculated by dividing the power by the voltage. Such as incandescent lamps, electric heaters, rice cookers, etc. In a 220V single-phase power supply, the operating current is 1000W resistive load.

For inductive loads in a single-phase power supply, the current is calculated by dividing the power by (voltage x power factor).

Single-phase 220V: I=1000 220=, Three-phase 380V: I=1000 380

A motor is 10kw, the voltage is 380v, how much is the current per phase.

Hello dear, happy to answer your <>

According to the power and voltage of the motor, the size of the current for each phase can be calculated. The formula is: current per phase = motor power blind limb 3 x voltage x power factor) where 3 represents the root number 3, that is, the power factor is generally taken.

Substituting the data into the formula: current per phase = 10,000 x 380 x Foolish Scales Amperes. Therefore, the motor has amperes per phase.

A motor is 10kw, the voltage is 380v, how much is the current per phase.

According to the relationship between power (p) and voltage (v), the current per phase can be calculated using the following formula: i = p 3 * v) Substituting the given power (10 kw) and voltage (380 v) into the formula: i = 10 kw 3 * 380 v) So, the current per phase is about amperes.

Please note that this is a theoretical calculation and the actual situation may vary, as hidden factors such as the power factor and efficiency of the motor also need to be considered. 