A math problem, kneeling down and begging the master to solve it!!!!!!!!! Urgent!!!!!!!!! Equation

Red 100 White 150

Equations can be passed.

Take it 1:1, and there will be 50 whites left at the end, indicating that there are 50 more whites than red.

Take it according to 1:3, and there is 50 red left at the end, which means that there are 50 more red than 1 3 of white, that is, 150 less white than 3 times that of red.

100 red balls and 150 white balls

Set the red ball x and the white ball y

Take it 1:1, and there will be 50 whites left at the end, indicating that there are 50 more whites than red.

i.e. y=x+50

Take it according to 1:3, and there are 50 reds left at the end, which means that there are 50 more reds than 1 3 in white.

i.e. x-50=y 3

The two equations are solved in conjunction with x=100

y=150

Let the number of times the first way is x, and the second is y

x+x+50=y+3y+50 x=2y

In addition, the total number of white balls calculated by the first method is x+50, and the total number of white balls calculated by the second method is 3y

So x+50=3y

Thus x=100, y=50

So 100 red balls and 150 white balls.

Feel free to ask.

Red Ball x White Ball Y

According to the title.

x+50=y

y/3+50=x

The solution is x=100 y=150

Solution: If there are x white balls, then there are (x-50) red balls. Columnable equations:

1 3) x+50=x-50 – red balls on both sides of the equation. The solution is x=150 - the number of white balls. There are (x-50) red balls, that is, 150-50 = 100 (pcs) Answer:

There are 150 white balls and 100 red balls.

1) If the red ball is x, then the white ball is x+49 (assuming the red ball is taken first and then the white ball is taken).

Take three white balls at a time, how many times do you take them and they are gone? x+49 times, then the red ball is also taken so many times, and only one at a time. So, x-(x+49) 3=50 gives x= haha.

2) Let the red balls be x, then the white balls are x+50 (assuming they are taken at the same time) x-(x+50) 3)=50 to get x=50

Both answers were wrong.

Set x red balls.

There are 50+x white balls.

x-（50+x）÷3=50

Solution x=100

So 100 red balls and 150 white balls.

Let the red ball be x and the white ball be y, then there is 50+x=y; y/3+50=x ；Solve the above equation to get x=100, y=150.

Red 100 White 150

Please give points, thank you.

That person is so fast... Sweat.

Solution: Qiaowang set up the submarine to descend when the filial piety shed is Ling Jian x seconds.

50+2*15-5x=-80

x = 12 A: 12 seconds down.

The highest cost: 200 (1+50%)=400 3 133 yuan, the lowest cost: 200 (1+100%)=100 yuan, 133 (1+20%)=yuan160 RMB, 100 (1+20%)=120 RMB.

When you go to buy toys, you can make a counteroffer in the range of 120 yuan to 160 yuan.

1.Solution: The average speed of Mr. Shilin when he set out from Zhoushan was x km hx=160

A: The distance between Zhoushan and Jiaxing is 720 kilometers.

2.Solution: Derived from the question.

503=a×(720-48-36)+100+80+5636a=318

A = A: The highway mileage fee for the car is yuan kilometers.

Set the distance of the expressway between the two places is x kilometers, x (x solution, x = 360 kilometers (2) Mr. Lin from Zhoushan to Jiaxing, the high-speed toll y = yuan, the highway mileage is x = 360-48-36 = 276 kilometers, the bridge toll b = 100 + 80 = 180 yuan, so, y = ax + b + 5 a = yuan km

1.Let the distance be x...

ax=318 Bring in the x calculated in the first question, which is the answer to the second question.

1.Let x h get x = 160 160 multiplied by the answer 720 km.

2.(720-48-36)a+100+80+5=503, a=yuankm.

Arithmetic: 1-1 5=4 5 for boys

The ratio of the remaining boys to girls is 3:2, so the remaining girls are 4 5 * 2 3 = 8 15 of all boys

128 people - 13 girls who went to the welfare home, it was 115 people.

These 115 are the total number of boys (1+8 15).

115 (1+8 15)=115*15 23=75 people.

Girls: 128-75=53.

If there are x boys, 128 x girls.

4/5)x:(128-x-13)=3:2(8/5)x=3*(115-x)

23/5)x=345

x=75 so 75 for men and 53 for women.

There are x number of boys. then there are (128-x) female students.

x-1/5x):(128-x-13)=3:2(4/5x):(115-x)=3:2

8/5x=345-3x

x=75 so there are 75 boys and 53 girls.

Solution: If there are x boys, then there are 128-x girls.

According to the question: (4 5) x: (128-x-13) = 3:2 (4 5) x: (115-x) = 3:2

x=75 (person).

Then there are 128-47 = 53 girls.

A: There are 75 boys.

There were 53 female students.

First, there are x and y people for boys and girls, and the equations are listed.

x＋y＝128

4x/5):(y-13)=3:2

3×(y－13)＝2×(4x/5)

15y-8x=195

It can be solved in conjunction with X y 128.

Let the number of boys be x and the number of girls be y

x+y=128

y=13+2 3(4 5x) Because 13 girls go to clean, the remaining girls are 2 3 with 4 5x left

The column formula is as follows: x+13+2 3(4 5x)=128x+8 15x=128-13

23/15x=115

x=115÷23/15

x=75y=128-75

y=53

Let the number of boys be x and the number of girls be y, then: x+y=128

4/5 x:(y-13)=3:2

y=128-x is substituted into the calculation......

If there are x boys, there are 128-x girls.

4x/5)/(128-x-13)=3/2

x = 75 for 75 boys and 53 for girls.

Solution: Let the boy have x and the girl have y

x+y=128

x-1/5x/y-13=3/2

Solution: x=75

y=53

by a c x ton, 15 yuan per ton then a d (20-x) ton, 12 yuan per ton b c (15-x) ton, 10 yuan per ton b d [35-(20-x)] ton.

or [30-(15-x)] tons, i.e. (15+x) tons. 9 yuan per ton.

So, the total amount of money.

m=15x+12*(20-x)+10*(15-x)+9*(15+x)=2*x+240+150+135

2*x+525

Therefore, when x is zero, the total shipping fee is the lowest, which is 525 yuan. Right?

Solution: Let A be transported to C x tons then A-D: (20-x) tons B-C: (15-x) tons B-D: 35-(20-x) = x+15

Total shipping cost y=15x+12(20-x)+10(15-x)+9(x+15)y=2x+525 x>=0 20-x>=0 15-x>=0 x+15>=0 15=>x>=0

When x=0, y=525 is minimum, then a-c:0 a-d=20, b-c:15, b-d:15

a-cx. a-d20-x.

b-c15-x b-d15+x

The x can be between 0 and 15.

Total shipping = 15x + 12 (20-x) + 10 (15-x) + 9 (15 + x) = 525 + 2x

The greater the x, the greater the freight, the least freight, the smallest x.

x=0, freight=525

Set A to ship to C city x tons of total freight Y yuan.

y=15x+（20-x）12+（15-x）10+【35-（20-x）】9

2x+525

Because k=2>0

y increases as x increases.

So x = when y is minimal.

y 525 yuan.

0 tons from A to C and 12 tons from D.

15 tons from B to C and 15 tons from D.

Solution: Set the average of bai large watermelons per ** is.

X yuan, Du small watermelon is Y yuan per each ** on average. Then: DAO has a square internal program group according to the topic.

50x+25y=660

30x+45y=540

Solve this system of equations to get: x=, y=

That is: each large watermelon dollar, each small watermelon dollar.

The weight of a large watermelon is kilograms), and the weight of a small watermelon is kilograms) So: the boss's estimate is not very accurate.

Solution: 20 big bai

Watermelons cost 660-540 = 120 yuan more than 20 small watermelons, and each large watermelon dao is 120 more than small watermelons 20 = 6 yuan.

Let the average of each large watermelon be x yuan.

50x+25(x-6)=660

50x+25x-150 =660

75x=660+150

x = each small watermelon = yuan.

Column Equation System Answer:

Solution: Let the average of each large watermelon be X yuan and the small watermelon be Y yuan.

50x+25y=660

50-20)x+(25+20)x=540 solution to x= y=

Check your boss's estimate yourself.

Let a large watermelon weigh x kilograms.

Small watermelons are y kilograms.

Solve x,y.

then a small watermelon yuan.

A large watermelon dollar.

x=y=2

Set the average of each large watermelon x yuan, small watermelon y yuan. Then: 50x+25y=660, (50-20)x+(25+20)y=540.

That's it! After solving x and y, and then dividing by it, you can estimate the size of each watermelon, and you will know whether the boss is correct or not!

Set the weight of the large watermelon x kg, and the weight of the small watermelon y kg;

get x=; y=2.Large watermelons are each yuan, and small watermelons are each yuan.

Well, I'll answer in detail when I have time.