1, x 3 4 2 x 3 2x 3 How to solve the absolute value

1. |x-3|≥4

X-3 -4 or X-3 4

x -1 or x 7

2.|x-3|≤2x+3

x 3 x 3 2x+3 x -6

The intersection is x 3

3-x 2x+3 x 0 at x<3

The intersection is 0 x<3

So x 0

Question 1 When x is greater than three: x-3 4 solution gets x 7 when x is less than or equal to 3 -x+3 4 solution gets x less than or equal to minus one.

Question 2 When x is greater than three: x-3 2x+3 solution x is greater than 3 When x is less than or equal to 3 -x+3 2x+3 solution is x greater than or equal to 0 less than or equal to 3 In summary, x is greater than or equal to 0

1 simultaneous squared.

2 discussions, such as |x-3|42 is equivalent to x 3 42 or x 3 -42

x-3≤-4

x 7 and x -1

2.It's a bit complicated to assume that 2x+3 is greater than 0 or 2x+3 is less than 0, when the condition is -(2x+3) x-3 2x+3 The result is calculated by yourself, too lazy to calculate, take the formula apart and calculate, understand? If you don't understand, ask me again and I'll teach you.

In the same way, when the condition is 2x+3 x-3 -(2x+3), count it yourself. The last 2 answers are understood with or connected?

Hope you can

Categorical discussions. x is greater than or equal to 3 and x is less than 3

The general solution to absolute values is |x|<=a, we get -a==aIt's x>=a, or x<=-a, and that's what I'm making a positive

2x-1|=x+3(x+3 0,x -3) The square of the two wild books and the macro ridge.

4x^2-4x+1=x^2+6x+9

3x^2-10x-8=0

3x+2)(x-4)=0

x1=-2/3,x2=4

Because the age is scattered x-1 2x+3

So x-1 = gig(2x+3).

So x-1 = 2x+3 or x-1 = -2x-3, so x = -4 or x state feast 2 3

Let f(x)=|x-1|=x-1,x belongs to [0,+ Signs) f(x)=1-x,x belongs to (- 0).

So x-1>=2x+3 or 1-x>=2x+3 gives x<=-4 or x<=-2 Chazhouxiang3

Because the absolute value is equal to 2x-3, the square of both sides of the eggplant at the same time can get x -2x+1=4x -12x+9, and the same term is 3x -10x+8=0, (x-2)(3x-4)=0, and the solution is x=2 or x=4 3.

Categorical discussion, 1When 2x-1=3, 2x-1=3, 2x=3+1, 2x=4, x=2

2.When 2x-1=-3, 2x-1=-3, 2x=-3+1, 2x=-2, x=-1

Therefore, the solution of 2x-1 for the simple and absolute wear of lead = 3 is x=2 or x=-1

If the absolute value of x = 2 and the absolute value of y = 3, then the value of (x y) is how much the first manuscript is sold.

x=±2，y=±3

Hu roll x y respects = 5 (the same as the sizzle and the open star).

Variant = 1

i2x--1i=3

2x--1=3 or stool 2x--1=--32x=3+1 or jujube destruction and late change 2x=--3+12x=4 2x=--2

x1=2,x2=--1.

Summary. Absolute value 2x+3 + absolute value 1+2x is not equal to 3

Hello dear, it is a pleasure to serve you! I am Mr. Dong Xiaoming, and I am good at mathematics, physics and chemistry. I will provide you with the process and answer the rough case within 5 minutes, please wait for a while.

Dear, please take a picture of this question in the book and send it over, I'll take a look at the original question, so that I can see it more clearly.

Ask X to see, dear. Wait a minute, the answer is being written.

Look at the **, dear. Above is the process and result of the calculation. The red box is the specific value of x.

There are 4 types of cases. According to these four cases, simplify, remove the absolute value symbol, and then get the specific value of x.

x range in the form of a collection.

Look at the **, dear. Finally, there is the union of the three value ranges.

You look at the last one.

Knowledge expansion: The test point of this question is: according to the absolute value within the Nabobi arithmetic, change the value range of the boxer, remove the absolute value symbol, and find the value range of x. Then you can uncombine the range of values of x.