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3a9+c7e=287*2=574, so e=5, a=9, c=1So the difference = 399-175 = 224 From 0:00 on October 29 to 7:00 a.m. on November 5, it is a total of 7*24+7=7*25 (hour) This table is divided into points), so it takes 7*25 hours for every minute to go faster. The correct time should be 7 a.m. on November 5 minus 3 minutes * 70 3 hours per minute = 70 hours, that is, the correct time is 9 a.m. on November 2.
Let there be x in A and y in B, then there are (38-x-y) in C, and x+7=y-5=(38-x-y) 2, and the solution is x=3 and y=15, so B is 5 times that of A. The selling price is equal to the total price divided by the total weight (
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3a9+c7e=287 2=574 can be calculated a=9, c=1, e=5, i.e., 399 and 175The difference between these two numbers is 224 2.
If the number of cages in the three cages is exactly equal to x, then A + 7 + B - 5 + C = 4x = 38 + 2 = 40, x = 10A = 3, B = 15, C = 20It turned out that the rabbits in cage B were 5 times as many as those in cage A.
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Solution: The average of the two numbers is 287, then the sum of the two numbers is 574, 3a9 is the large number, and c7e is the decimal number, where 3a9-287 = 287-c7e, 9-7 = 2, then 7-e = 2, and e=5;8-7=1, then a-8=1, a=9;399-287=112, c7e=175, and the difference between the two numbers is 224
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Solution: 3a9+c7e=287 2=574
3 a 9 c 7 e
- Calculate from back to front: e=5 , a=9 , c=15 7 4
So these two numbers are 399 and 174 399-175 = 224
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Try the answer to the former Sakura question:
The sum of the three-digit number 3a9 and the three-digit number c7e is: 287 2=574;
i.e. 3a9+c7e=574;
On the single digit: the end of 9+e is 4, 9+5=14, you can get e=5, and advance 1 to the tenth place;
On the tenth: the end of a+7+1 is 7, 9+7+1=17, you get: a=9, advance 1 to the hundred;
On the hundred: 3+c+1=5,c=1;
Then the three-digit number 3a9 is the opening plexus 399; The three-digit number c7e is 175;
The difference between them is: 399-175=224
Therefore, the repentance macro is: 224
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Solution: The sum of the three-digit number 3a9 and the wide-line three-digit number c7e is: 287 2=574;
i.e. 3a9+c7e=574;
On the single digit: the end of 9+e is 4, 9+5=14, you can get e=5, and advance 1 to the tenth place;
On the tenth: the end of a+7+1 is 7, 9+7+1=17, you can get: a=9, and go up to the hundredth place to tease Qiaochen 1;
On the Hundred Mountains Zen position: 3+c+1=5, c=1;
Then the three-digit number 3A9 is 399; The three-digit number c7e is 175;
The difference between them is: 399-175=224
So the answer is: 224
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The sum of the three-digit number 3a9 and the three-digit number c7e is: 287 2=574;
i.e. 3a9+c7e=574;
The end of 9+E is 4, 9+5=14, and e=5 can be obtained, and the base of the ten is 1;
On the tenth: the end of a+7+1 is 7, 9+7+1=17, you get: a=9, advance 1 to the hundred;
On the hundred: 3+c+1=5,c=1;
Then the three-digit number 3A9 is 399; The three-digit number c7e is 175;
The difference between them is: 399-175=224
So the answer is Oak: 224
-
The sum of the three-digit number 3a9 and the three-digit number c7e is: 287 2=574;
i.e. 3a9+c7e=574;
On the single digit: the end of 9+e is 4, 9+5=14, you can get e=5, and advance 1 to the tenth place;
On the tenth: the end of a+7+1 is 7, 9+7+1=17, you get: a=9, advance 1 to the hundred;
On the hundred: 3+c+1=5,c=1;
Then the three-digit number 3A9 is 399; The three-digit number c7e is 175;
The difference between them is: 399-175=224
So the answer is: 224
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