How to dilute 98 sulfuric acid into 50 sulfuric acid 5

It is assumed that 1000 g of 50% sulfuric acid is prepared.

The mass of sulfuric acid is required 1000 50% 500 grams.

Concentrated sulfuric acid is required.

The mass of 500 98% = grams.

Add another 1000 grams of water.

The gram of concentrated sulfur is not added to the gram water.

The quality of sulfuric acid before and after dilution is unchanged, for example, 100 grams of 98% sulfuric acid is 98 grams, and the mass of the solution is 50%, and the solution mass is 2 times that of 98 grams, so that 196 grams of water need to be added minus 100 grams, that is, 100 grams of 98% sulfuric acid are dropped into 96 grams of water.

Take 100g of sulfuric acid with a mass fraction of 98%, the mass of sulfuric acid should be 98g, dilute it into 50%, that is, the mass fraction of sulfuric acid is 50%, 98g divided by 50% is equal to 196g, so the dilution process is to add 96g of water to every 100g of concentrated sulfuric acid.

100 grams of 98% concentrated sulfuric acid is slowly added to 96 grams of water along the glass rod, stirring while adding, you can dilute to 50% sulfuric acid.

According to the concentration of concentrated sulfuric acid on the reagent bottle (98% I remember is the mass concentration, according to this idea to give you an algorithm), calculate the mass of concentrated sulfuric acid m sulfuric acid, and the mass of the remaining water sulfuric acid, then m water = m sulfuric acid, the mass of water to be added is m0 = m water - m. Remember, add sulfuric acid to the water, don't get it wrong. If you need to mix other types of concentration solutions such as the amount and concentration of the substance, you can also refer to the above ideas for calculation!

Dilute. Note: Concentrated sulfuric acid is added to the water, not the other way around!

If it is 100g, take 96ml of water with a graduated cylinder and add it to sulfuric acid.

Optimistic about the quality of sulfuric acid, do not move and add water, and the calculation will come out.

If the volume after dilution is x, the quality of sulfuric acid before and after dilution remains unchanged, and the dilution is 80%, then x* x= add water.

Dilution to 30% then x* x= add water.

98% concentrated sulfuric acid mass n

Required water quality = n*

Hello dear, need to add grams.

The specific process is shown in the figure below.

Well, thanks! Waiting.

Ok thanks!

You are welcome.

Summary. 98%a=70%(a+b), the law of conservation of mass The concentration is the quantity concentration of the substance, which also needs to be converted into a unit mass and should also be multiplied by the molar mass.

How to dilute sulfuric acid with a concentration of 98% to sulfuric acid with a concentration of 70%, calculate the specific method.

The law of conservation of mass of sulfuric acid is used for this question.

Don't you have a specific volume for this 98?

98%a=70%(a+b), the law of conservation of mass The concentration is the amount of the substance, the concentration of the burning, and it also needs to be converted into the concentration of the mass per unit grade, and it should also be multiplied by the segment picos to the molar mass.

Pro-3, do you still have any doubts?

Suppose 1 gram of 98% concentrated sulfuric acid is diluted into 1% dilute sulfuric acid, and the quality of water that needs to be added is x1g*98%=(1g+x)*1%.

x = 97g, that is, adding 97 grams of water to 1 gram of 98% dilute concentrated sulfuric acid can be released into 98 grams of 1% dilute sulfuric acid.

Take one part of 98% concentrated sulfuric acid, then 1*98%=

If it is diluted to 1%, the amount of water that needs to be added is x parts, and the equation is 98%=1%*(x+1) to obtain x=97;

That is, to dilute 98% concentrated sulfuric acid into 1% dilute sulfuric acid, 97 times the volume of water needs to be added.

Add water or metal to react with it.

To dilute 100 grams of 98% concentrated sulfuric acid to 20%, the quality of the water required is.

390 (grams).

Calculation formula for dilution solution:

The quality of the water added.

Concentrated solution quality.

Concentrated solution mass fraction.

Dilute solution mass fraction.

Concentrated solution quality.

Don't talk about molarity, which is a very non-standard statement, the correct expression is the amount concentration of a substance.

Start by giving you a quality score.

) and the conversion formula for the quantity concentration of the substance (c).

c = m, so dilute sulfuric acid.

The density is approximately 1000g l) of the amount of the substance as follows:

c = 1000g l 98g mol = Let's talk about the first question, 98% sulfuric acid, the density is g l, the amount concentration of the substance = 98% 1840g l 98g mol =

Before and after dilution, the amount of sulfuric acid is equal, and n = cv thus:

c1v1 = c2v2

v1 = 5 × 500ml

Solution v1 add: 5mol l? You can just reverse the above formula.

However, the density of 5mol l of sulfuric acid is relatively large, and it cannot be counted as 1000g l, and there will be a large error.

So you have to know the density to be calculated.

c = mω =cm/ρ

Density is a property of matter, which cannot be calculated, you can look up the table, or give the title.

If you have a graduated cylinder, you can dilute it according to the amount.

This problem is very simple, if you want to dilute 1 liter of 98% sulfuric acid to 80%, you need to add 225 ml of water; If you want to dilute 1 liter of 98% sulfuric acid to 30%, you need to add 2267 ml of water. If the sulfuric acid to be diluted is not 1 liter, a proportional calculation will do.

If the volume after dilution is x, the quality of sulfuric acid before and after dilution remains unchanged, and the dilution is 80%, then x* x= add water.

Dilution to 30% then x* x= add water.

Because the volume after mixing is less than the sum of the volumes of sulfuric acid and water before mixing, the density of sulfuric acid is also required here to calculate.