Simple Questions for Elementary School 10, Simple Questions for Elementary School

1.What do you know about electronic computers (computers???

2.Miss Qiu quietly left.

Grandpa Winter came on a snowflake.

Day 2Set up x apple trees.

x x = 840 trees.

I feel like the topic is wrong.

It should be that there are 560 trees in the orchard).

If so: set pear trees x trees, then apple trees.

x+x=224

About 4If there were originally x books on the upper floor, there would be a total of 4x books.

By analyzing the middle layer there are 4x 3 books.

x+10=4x/3

Solution: x = 30 copies.

So there are 120 books in total.

5.Because buy two get one free, that is to say, buy three yuan only with yuan.

2.Solution: If there are x pear trees, then there are apple trees.

x+x=224

So A: ......

4.If there are 4x books in total, there are x books on the upper floor.

There is a Y book in the middle floor.

4x-x-y=y=x+10

x=304x=120

A: ......

1.Through the three mathematical information of "Xiao Ming bought 3 popsicles and 2 cones, Xiao Jun bought 3 popsicles and 6 cones, Xiao Ming spent 4 yuan less than Xiao Jun", we get that in the case of the same number of popsicles, Xiao Ming spends 4 yuan less than Xiao Jun, which is actually 2 cones and 6 cones are 4 yuan less. Then "An egg cone is 1 yuan".

2.Through the three mathematical information of "Xiao Ming bought 3 popsicles and 2 cones, Xiao Liang bought 4 popsicles and 1 cone, Xiao Liang spent less yuan than Xiao Ming" and the previous "one cone is 1 yuan". We get "Xiao Liang buys one more popsicle than Xiao Ming and buys one less cone, and it should cost 1 yuan less to buy one less cone, but if you buy one more popsicle, it only costs less yuan, indicating that there is one yuan for popsicles" - quoting Li Yanxing's answer.

Set the popsicle as $ x and the cone as $ y.

3x+2y, Xiao Ming+4=3x+6y

4x+ytrabecular +

3x+6y Army.

3x+2y+4=3x+6y

4x+y+do the math x=,y=1

The popsicle is $1 and the cone is $1.

3x+2y Xiao Ming =

4x+y trabecular = 3

3x+6y Army.

Xiao Ming Hua Yuan. Trabecular costs 3 yuan.

Xiaojun Hua Yuan. The process is roughly like this, you take a look at it first.

Xiao Ming bought 3 popsicles and 2 cones, Xiao Liang bought 4 popsicles and 1 cone, Xiao Jun bought 3 popsicles and 6 cones, Xiao Ming spent 4 yuan less than Xiao Jun, and Xiao Liang spent less yuan than Xiao Ming. How much did they spend?

Set: The popsicle is $ x, the cone is $ y, and Xiao Ming spent a dollar.

Column equation system 3x+2y=a; 4x+y=；3x+6y=a+4 is solved to x=; y=1；a=

That is: popsicles are yuan, cones are 1 yuan, Xiaoming flowers are yuan, Xiaoliang flowers are 3 yuan, and Xiaojun flowers are yuan.

Xiao Jun buys 4 more cones than Xiao Ming, spending 4 yuan more, one yuan per cone, Xiao Liang buys one more popsicle than Xiao Ming and buys one less cone, and buying one less cone should cost 1 yuan less, but buying an extra popsicle only costs less yuan, indicating that the popsicle is one yuan.

Set each popsicle to be $ x and each cone to be $ y.

3x+6y)-(3x+2y)=4, the solution is y=1(3x+2y)-(4x+y)=, and the solution is x=

Therefore, Xiao Ming spends 3x+2y=yuan;

Trabecular costs 4x+y=3 yuan;

Xiaojun spends 3x+6y=yuan;

One cone is 1 yuan, and one yuan is a popsicle.

Xiao Ming spent yuan.

Trabeculars cost 3 yuan.

Xiaojun spent yuan.

Xiaojun spent yuan.

1 yuan for a cone.

Xiao Ming spent yuan.

Popsicle a meta.

Trabeculars cost 3 yuan.