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x = 3 or x 2
2(x-2)(x+3)=0
Solution: (x-2)(x+3)=0 (both sides are divided by 2 at the same time) So, just make .
x+3)=0 or: (x-2) 0.
The solution yields x = 3 or x 2
Bring it in, and get 0*(5)*2 0
0*5*2 0, in line with the original question, so x= 3 or x 2
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Summary: This time, a total of 1 question will be solved. Equation 1 is a problem
1 1 Equation Assignment: Find equations.
solution. Problem type: Equation Solution: Move the term containing x to the left of the equation, move the term without x to the right of the equation, and reduce the coefficient of the unknown number x to 1, that is, the solution of the equation is: x
Keeping 6 decimal places has 1 solution.
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Solution::4
3 (the product of the out-of-scale term is equal to the product of the in-scale term).
x=70
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This question: The situation of the question is a bit unclear, please distinguish the relationship between the front and back in parentheses.
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Is it missing two parentheses.
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The first question is not clear.
The second mention x = 31 * 5 = 155
1/3【1/4(1/5x-1)-6】=2
1/4(1/5x-1)-6】=6
1/5x-1)-6=24
1/5x-1=30
1/5x=31
x=155
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Solution: Remove parentheses:
Move Item:Merge Items of the Same Kind:
The coefficient is reduced to one: x = -8
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Such an equation can be obtained in the first place: 2x-6=x
Then move the item and get it: 2x-x=6
This yields: x=6
For a question like this, depending on the level of learning of the questioner, if you have not learned the shift term, adding or subtracting the same number from both sides of the equation will not change the value of the equation.
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Solution: The original equation can be deformed as: 2x-6=x
Shift: 2x-x=6
Solution: x=6
Look at the examples in the book and you'll do it.
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All are replaced with an exponent with a base of 3, with 3 to the 2x+4 power on the left and -2*x+2 to the power of 3 on the right.
So 2x+4=-2x-4
4x+8=0
So x=-2
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The equation can be reduced to (x+a+1) squared = 0 to get x=-a-1
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x +xy=12, ,xy+y =4, , get x +2xy+y =16, i.e. (x+y) =16, so x+y= 4, , get x y=3 (get x+y≠0 from , so you can make an appointment), substitute , get x=3, y=1, or x=-3, y=-1
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