On an airplane flying at a constant horizontal speed, objects A and B fall 1s apart, and before land

Answer: C is a flat throwing motion on the ground, but the horizontal displacement of the aircraft is equal to the horizontal displacement of the object in the same time.

It looks like a free-fall motion from an airplane.

Before landing, the ball is directly below the b-object.

c Air resistance is not calculated.

Due to inertia, both objects A and B continue to fly at their original speed before they hit the ground.

It's just that it's always under an airplane that is flying at a constant speed.

Since A falls 1s earlier than B, A will be directly below B. Hope.

That's right, isn't it just right above from the point of view of free fall You want you to release 2 balls before and after with no initial velocity, and the second one is just below the first one, choose c, I hope it can help you.

Whether air resistance is taken into account.

1,b Considering the air resistance, then the lateral velocity of A is less than that of B, after which the lateral deceleration of the two is equal.

2,c does not consider the air resistance, then the transverse velocity of a and b is equal, the vertical direction a is greater than b, and the distance is larger and larger.

The answer is only c, which is a flat throw, but the horizontal velocity a and b are the same.

The answer is C, but I'm not sure.

Answer: C The plane flies at a constant speed horizontally, then the thrown AB object has the same velocity in the horizontal direction, and before landing, the horizontal distance is the same, A is directly below the B object, and C is correct.

With inertia, it can be seen that the horizontal velocity of each object in the air is unchanged. So the relative position of the object in the horizontal direction is the same, the difference is only the distance in the vertical direction. So choose C

Regardless of air resistance, C is chosen. Because A and B have the same horizontal velocity, the horizontal position is the same, but it falls first, so it is below.

If air resistance is taken into account, then in the lower back, of course there is no answer to this that is, this situation is not taken into account.

If the horizontal initial velocity of A and B is the same, then their horizontal distance is always 100m, and the distance between A and B is the largest at the moment when object B hits the ground.

1.Calculate the time for object a to fall s=1 2at 2 a for 2 seconds for an object to fall! (Note the conversion unit).

The time of the object is 19 seconds!

3.Using s=1 2AT2 to calculate the vertical distance of object b's descent is 1805m, and the vertical distance difference is 195m

5.The maximum distance ab using the Pythagorean theorem is about 198m

The maximum distance is the moment when the object hits the ground.

Because both are accelerated motions, and the velocity of A is always greater than B. So the distance between the two will be bigger and bigger. When A lands on the ground and stops falling, the distance between the two objects is maximum!

This problem is very simple, when the first object falls to the ground, the distance between the two objects is the largest, it is a right triangle, one side is 100, and the distance of the other side can be calculated according to the one I gave above, and finding the chord is the longest distance.

It's very simple. You can imagine that the trajectory of the ball falling is an arc downward, right? The trajectory of the ball is divided into horizontal and vertical directions, the horizontal direction is the speed of flight, and the vertical direction is the free fall motion.

The horizontal direction of the ball is constant, so the ball is in a straight line.

In other words, you shouldn't have learned this in the third year of junior high school. This seems to be the knowledge of high school, that a free fall is a uniform acceleration in a straight motion, and the answer is d that the distance between the two balls will be farther and farther away. As for why it's getting farther and farther away, you think.

A falls first, and the acceleration is about 10 (meters per square second), which is the unit of acceleration, and then after one second, A's velocity is 10 meters per second, and then B starts to fall. After two seconds, A's velocity is 20 meters per second, B's velocity is 10 meters per second, A's velocity is always greater than B's, and in the same amount of time, A will always travel more distance than B.

The plane can be taken as a frame of reference, that is, the plane is not moving, which is equivalent to releasing two balls from a high place at rest, of course, it will only be up and down, and the flat throwing motion can be regarded as two movements, horizontal uniform motion and vertical free fall motion, and the horizontal velocity is equal to the flight speed of the aircraft, so their relationship is up and down.

D maintains a constant velocity horizontally, and the vertical direction is a free-fall motion and an accelerated motion, so D and A balls are directly below B balls, and the distance between the two balls gradually increases.

I did this ...... in the third year of junior high schoolYour teacher is amazing.

I was also in my third year of junior high school, and our teacher said that because there was no resistance, A threw it out and the plane stood still (stationary horizontally, but A fell), and when I threw B, A, B, the plane had the same speed, the same vertical line, and different heights, and then A smashed the ground, and then B, and the plane was difficult to say.

AB that falls from an airplane flying at a constant speed at a constant speed is the same as the time it takes to fall to the ground.

So the distance traveled is the same.

Because A falls first, A will come after object B.

Answer: C Analysis: When two objects fall downward, they will maintain their original horizontal velocity because of inertia, and the horizontal velocity of the two is the same, so they are arranged in a straight line in the vertical direction.

It must be c, because the air resistance is ignored. Don't ignore it, the answer is A.

c a and b have the same initial velocity as the aircraft, and there is no difference in displacement between the three in the horizontal direction before landing, so b should be directly above a.

a, the ball leaves the plane to do the flat throwing motion, the flat throwing motion in the horizontal direction to do a uniform linear motion, so the line of the two small balls is a straight line, and the horizontal plane is perpendicular so a correct

b. Flat throwing motion in the vertical direction to do free fall motion, according to h 12gt?12

g(t?1)

GT-12G, which increases over time so B is correct

c. Because the flat throwing motion does a uniform linear motion in the horizontal direction, a person sees the ball directly below him on the plane, and observes the ball doing free fall motion, so C is wrong

d. The person on the ground sees that the ball has a horizontal initial velocity and does a flat throwing motion so D is correct This question is wrong, so choose: C

Since the horizontal velocity of the two is equal, the horizontal distance is constant, δx=v0δt=100m, because the two are in free fall in the vertical direction, so A will always walk 1s more than B.

Therefore, the vertical distance increases with time, so when A just lands, the vertical distance between the two is the largest.

At this point, the maximum vertical distance is the vertical displacement of a in the last second.

Column formula: h=1 2gt, substituting h=2000m, g=10m s to get t=20s

The vertical displacement after 19s: h'=1 2gt, substituting t=19s, g=10m s to obtain h'=1805m

Therefore, the maximum vertical distance δhm = h-h' = 195m can be known from the Pythagorean theorem: δd = δx + δhm , and the solution is δd =

Due to inertia, B falls off in the last 1s, but due to inertia, when B flies forward with the plane, A is also flying forward at the same speed. So before A touches the ground, ab is always in the same vertical line, and A is always directly above B, and there is no horizontal distance.

When A touches the ground, B has to fly for 1s, so the distance between AB after landing is: 100mThe farthest distance between the two is when A just touches the ground.

Column: h=, get t=20s

h'='² t'=19s , solution h'=1805m so distance: δh=h-h'=（2000-1805）m=195m

The A-ball falls, and since A has the same horizontal velocity as the plane, the A-ball is always directly below the plane.

Similarly, when the B ball falls, B also has the same horizontal velocity as the airplane, so the B ball is also under the plane in the cardinal direction.

Thus the A ball destroys the ridge just below the B ball. Sleepiness.

Because the two velocities in the horizontal direction are the same, they are directly below, and in the vertical direction, there is an acceleration of g

a. The object does a flat throwing motion, which can be regarded as a uniform linear motion in the horizontal direction, and a free fall motion in the vertical direction, because the height is not known, the falling time is not known, so the spacing in the horizontal direction cannot be determined, so a is wrong;

B, objects are free from the plane flying at a constant speed, all do flat throwing motion, the horizontal direction is a uniform linear motion, the speed is equal to the speed of the aircraft, then before landing are directly below the aircraft, so they are arranged in a vertical straight line, so B is wrong;

c. The object is in free fall in the vertical direction, and although the falling time is the same, the vertical spacing is unequal, so C is wrong;

d. According to the law of free fall motion, the greater the falling height and the greater the speed, then it is known that their spacing is constantly increasing, so D is correct, so D is selected