High score questions, please master! 25

Then we have to figure out whether these things you are talking about are not at the same time, or are they not single. If not, then it depends on where you are? Who are you going to contact? It's too complicated, so let's walk, it's the most convenient and safe!

Light a fire, or walk, or call an alien with your mind, or kill yourself.

Find a wine bottle, write a note and put it in, throw it out the window, you can watch "Lonely Island", it fits your mood very well.

Ask someone to help you talk! The person must be reliable.

Not contacted. After solving the problem by yourself, you can come out and contact it.

Choose a, consider means thoughtful, because the preposition followed by the space is of, so this space should be filled in with the adjective to describe you, and considerable means important, obviously to describe the latter thing, so choose considerate

Choose A, thoughtful, considerate, and considerate.

This kind of question is to test the discrimination of similar words, and you need to have a large enough vocabulary.

b. considerable

It is important to arrange a morning meeting between your boss and us.

Choose a thoughtful meaning adjconsiderate; considerate; Thoughtful Thoughtful for others.

b is significant, c is considered, d is well thought out, and is respected.

Set the team's speed to x. The speed of the communicator is 600 (2x60+24) = 150 31 (m s).

60x3x[（150/31）-x]=600（150/31）-（10/3）=x

x Team velocity is meter seconds.

When the team rests, the length of the team is 600, and the speed of the communicator can be calculated to be 600 144 = 25 6, and the pursuit of the team at the beginning is the pursuit problem, so the speed of the team is 25 6-600 180 = 5 6, when the team moves forward at a uniform speed, and returns to the end of the team is the encounter problem, so the time is 600 (25 6 + 5 6) = 120s, that is, 2 minutes.

Answer to question 1: When 6 is the base edge, the area is the square root of 3 times 7. When 4 is the base edge, the area is 8 times the square root of 2.

Answer to the second question; When 6 is the base edge, the area is 3 times the square root of 55. When 8 is the base edge, the area is 8 times the square root of 5.

The solution is as follows: the square root of the triangle area equal to s(s-a)(s-b)(s-c), where s=(a+b+c) 2,a; b;c;is the length of the three sides of the triangle.

The answer to the third question can be solved by solving the right triangle and the above method.

1。When the length of both sides is 4, the length of one side is 6. s is 6*(4 2-3 2)*1 2=3, root number 7

When the length of both sides is 6, the length of one side is 4. s is 4 * (6 2-2 2) * 1 2 = 8 root number 2

2。The second is the same...

Article 3 Waiting

Article 3 has two situations. a.That is, if 4 is hypotenuse, then the two right-angled sides are 3 and 4 respectively, 2-3 2 is the root number 7, and s is the root number 7 multiplied by 3 times half equals...

b。That is, if 3 and 4 are right-angled edges, then the hypotenuse is 5, and the area is 6.

1.(2x+y-z) (2x-y-z) = (2x-z) -y (square difference).

2.(-x-y)×(x+y)=-(x+y)×(x+y)=-(x+y)²

3.(x-2y-7) (x+2y-7) = (x-7) -4y (square difference).

4.(2x-y+4) (2x+y-4)=4x-(y-4) (square difference).

A steamer sails between two piers, it takes 4 hours to sail downstream, 5 hours to sail against the current, and the current speed is known to be 2 kilometers per hour, so find the speed of the ship in still water and the distance between the two piers. If the distance between the two piers is required to be x kilometers, the speed of the ship is (x 4), the speed against the water is (x 5), and the equation (x 4-x 5=4) can be listed, and the distance between the two wharves is (x=80).

Distance divided by time Along the water x 4 against the water x 5 Equation x 4-2=x 5+2 The distance between the two piers is 80 km.

If you don't connect, it's 14, and if you don't, it's 13. 1 root of 6 meters can be divided into 2 roots of rice and 3 roots of rice. That is, the material of 10 roots, and the rest are all meters of materials, which require a total of meters, which is the material to be connected. If you don't pick it up, it's it. The remaining 3 and 1 rice.

The total length of the 15 panels using the frame is meters;

1. If you only consider the length and do not consider the splicing of the frame, you need 780 6 = 130.

2. If each edge must be a complete frame, there can be no joints, and a total of at least 30 frames with meters need to be made.

There are four ways to divide the raw material of each complete frame:

A: 3 long side wastes rice.

B: 2 long sides, 3 short sides, no waste.

C: 1 long side, 5 short side, waste of meters.

d: 7 short side, waste of rice.

Preliminary comparison, plan A has 3 roots, plan B has 9 roots, and plan C has 1 root, a total of 13 roots are needed.