Some math problems one will also do .

Initially, the number of PLA troops is X

x+10):(2x/3-10)=2:1

x=90 so 900,000 at the beginning, 1 million after the surrender of the 100,000 Kuomintang army.

It takes X hours to set up a slow train to get to station A.

As can be seen from the question, A walks for 8 hours, and B has to take 12 hours.

Therefore, the ratio of speed A to speed B is 12:8=3:2

So it's available. T A Beginning: T B Remainder = V B: V A.

12/x=2:3

x = 18 (hours).

1.Grasp the invariant to solve the problem.

The number of the Kuomintang and the total number of the Chinese People's Liberation Army remain unchanged!

The number of people in the People's Liberation Army has changed from 9 to 10, which means that this one represents 100,000 people.

Then the Chinese People's Liberation Army originally had 900,000 people, and now there are 1 million people.

2.The slow train traveled 12 hours, while the fast train traveled the same distance in only 8 hours. The speed ratio is inversely proportional to the time ratio, so v is fast: v slow = 3:2

12*3 2=18 (hours).

1.Let it start with 3x and the Kuomintang 2x

3x+100000/2x-100000=2/1

The original PLA has 3x people, 3x+10=2*(2x-10).

x=30, so there were 900,000 people.

12*(12/8)=18(h)

To solve a math problem, you should know the meaning of each step of the equation. In this question, if you put the question in the"76"Changed to"77"All other information remains the same, then the correct answer will become: Basket A has 60 kilograms of apples, and Basket B has 40 kilograms.

Can you still figure it out with your algorithm?

This question can be thought of like this:

1 4 of apples in basket A and 1 5 of apples in basket B were taken out, leaving a total of 76 kilograms.

Suppose you take out 1 4 of basket A and 1 4 of basket B, then there should be a total of two baskets left.

100 (1 1 4) = 75 (kilograms).

Comparing the hypothetical and actual data, it can be seen that if you take out 1 4 1 5 = 1 20 of the second basket, you will take out 76 75 = 1 (kg) more. This shows that 1 kilogram corresponds to 1 20 of the basket.

So, 1 1 20 = 20 (kg).

The basket originally contained 20 kilograms;

100 20 = 80 (kg).

The basket turned out to be 80 kilograms.

Think of it this way, too:

Suppose that the 1 of the second basket is slowed down by 5, and the 1 5 of the first basket is taken out, then the two baskets should be left in total.

100 (1 1 5) = 80 (kg).

It can be seen that if you take out 1 20 less of the basket, you will take 80 76 = 4 (kg) less.

4 (1 4 1 5) = 80 (kg).

100 80 = 20 (kg).

A and B knew that the two baskets were originally 80 kg and 20 kg respectively.

Of course, there are other solutions (e.g. equations).

There's a math problem, is this the right thing to do?

A and B have a total of 100 kilograms of apples in the two scum baskets, take out 1 4 apples from frame A, take out 1 5 apples from box B, and take out a total of 76 kilograms of apples in the two baskets. The original A: 1 4-1 5 = 1 20, and then 76 (1-1 20) = 80, the original B:

Is 100-80=20 correct?

This should be done wrong, and it should be done as filial piety.

It turned out to be a x kilogram, and it turned out to be a y kilogram. Column Equations:

x+y=100

1-1/4）x+（1-1/5）y=76

The change is here.

15x+15y=100×15=1500

15x+16y=20×76=1520

Subtract the two formulas to get y=20

x=100-20=80

You are not right to do this, because in this problem, the unit 1 corresponding to 1 4 and 1 5 is not equal and therefore cannot be subtracted. The arithmetic solution is a little more difficult. See the answer below

I think this is also the right math problem, after all, everyone is more accurate.

If it is a primary school, it is recommended to judge the answer in this way: consider the 1 4 of the first basket and the 1 size 5 of the second basket as a group, which is 24 kilograms, and the chong brigade has such 4 groups and the 1 5 of the second basket, and the four groups have 24 4 = 96 kilograms, and the remaining 100 96 = 4 kilograms are 1 5 of the second basket, so the second basket: 4 1 5 = 20 kilograms, and the first basket 100 20 = 80 kilograms.

If both A and B take 1 5 out of it, then the remaining apples should be 100-100*1 5=100-20=80

Therefore, the 80-76 = 4 taken out of the excess is 1 4-1 5 = 1 20 taken out by the multiply

A originally or or empty has 80

B originally had (100-80) = 20

So this calculation is correct.

Solution: If you take away 1 4, then B takes more than 1 4 1 5Thus it gets:

100 (1 1 4) = 75 (kilograms).

20 kg. 100 more than 20 = 80 kg.

Answer: A originally had 80 thousand vertical grams, and B had 20 kilograms.

If basket A has x kg of apples, then B basket 100 x kg.

1 4x+1 5 (100 x)=100 761 4x chain1 5x=24 20

1/20x=4x=80

The answer is correct. It turned out that the first basket was 80 kilograms, and the second basket of Jian Zheng was 20 grams.

If the disadvantage is set to be x, and B is y, then there are 3 Beibuling 4x+4 5y=76, x+y=100, and the two forms are combined, and x=20 and y=80 are obtained respectively.

This question corresponds:

A + B = 100 1 4 A + 1 5 B = 24 So A = 80 B = 20

If you recognize only the same dates, please point to the mountain and praise it, Xie Duan Zhen Xie.

There's a math problem, is that right? Personally, I think it's right to do this for math problems like hail books, and it's okay to feel like this kind of spillover source.

Well, the idea of solving the problem is completely correct, and it's not wrong, that's how it should be calculated.

That's the right thing to do, kudos to you!

A = 80kg, B = 20kg.

Column equation solution is required:

A B = 100

1 4 A + 1 Sell 5 B = 100-76

The result of solving the equation is: A midstream excavation = 80kg, B millant = 20kg

180 is.

The least common multiple of bai60 and 90. If you think that the poplar tree and the willow tree are opposite, it means that the distance between the poplar tree and the willow tree is equal to the starting point of each other, and this is the origin of 180.

As for why you add 1, imagine this: within 180 meters, the position of the poplar trees is: 0, 60, 120, 180 meters, a total of 4 trees.

The location of the willow trees is: 0, 90, 180 meters, a total of 3 trees. There are two trees that meet the "opposite position", at 0 and 180 meters.

However, 180 180 = 1, a difference of 1, so you have to add this 1 and count the missed starting point of 0 meters.

Because trees are planted on both sides of the road, add 1 at the end.

To put it simply, change the length of the road to 180 meters, and draw a diagram to understand.

Plant the third poplar every 180 meters, the second willow, every 180 meters to the relative one, plus one because the two ends of the tree to be planted, the last tree interval is outside the range of 3600 meters, not counted in the 3600 meters, draw a picture at a glance.

This question asks for bai, "how many places are relative."

du place", then only is zhi

dao3600 is the least common multiple of 60 and 90 version of 180, there will be a relative location of the occurrence, and this question planting trees are planted from beginning to end, formula 3600 180 only add 1, is the beginning and end of the tree, otherwise it is just the tail planting, and the first is not planted.

To draw a picture, in addition to the normal common multiple, there is also a relative one at both ends.

"Hello 584333938, glad to answer for you!"

Solution: As can be seen from the question, the radius is meters.

cubic meters minutes).

7 minutes) A: It takes a few minutes to complete the delivery.