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The following algorithm is actually relatively simple, and I didn't find a more suitable method, for reference:
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The steps to simplify $49 frac times frac$ are as follows:
First, we can convert $49 frac$ to a fraction, i.e., $49 frac = frac + frac = frac$.
We then convert $49 frac times frac$ into the form of a fraction, which is $ frac times frac$.
Next, we can simplify the product of the denominator $11$ and $6$ to get $66$, i.e.,
frac \times \frac = \frac = \frac
Finally, if desired, we can convert $ frac$ to a form with fractions. This can be obtained by dividing $ frac$ by $66$ to get the quotient $8$ and the remainder $23$, i.e.:
frac = 8\frac
Therefore, $49 frac times frac = frac = 8 frac$.
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- 1225 and 25 99
Therefore, we can make detailed calculations through the simple calculation process of the upper and lower Zen faces, and the answer to the jujube Zen case of the absolute rock dust is -1125 and 25 99.
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(-49-1 Standby 99) x25
50x25)+25-25/99
1225 and 25 imitation of hunger model limb filial piety 99
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Negative 49 and 1 99 25. That's 49 99 25. =。Amount.
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How do you calculate 49 and 1 99 25 easily?
This problem can be used to perform a simple calculation of the multiplicative distributive law.
49 and dilemma 1 99 25
49-1/99)x25
49x25-1/99x25
1225 and 25 99
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Zha (50 Na Blind 1+1 99) 25
1250+25 25 99
- 1225 and 25 99
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A 49 and 1 99 25
Grip a 49 25 a 1 Huwu 99x25
A 1225 a 25 99
A 1225 and segment type 25 99
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There is no easy calculation of laughter.
49 100-49+1) or numbers 25 99-1225 and 25 99
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-1250+2500 Kukai 99-50 No Heru 99
1225 and 25 99
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49 and 1 99 25
98 99-50) 25
1250+25-25 Hidden rot 99
- 1225 and 25 99
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The simple example of 49+6x41+49x3 is included in the following figure.
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Simple calculation of the accompaniment before opening the eyes: 49 + 6x41 + 49x349 + 6x41 + 49x3
49x1+49x3+6x49-6x8
49x(1+3+6)-6x8
49x10-48
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You can decompose 73 and 1 17 into 72 + 18 17 and calculate it.
The multiplication rule is obtained: 73 and 1 17 1 9=(72+18 17)*1 9=72*1 9+18 17*1 9=8 and 2 17.
The multiplicative distributive law refers to the multiplication of the sum of two numbers and the number of early defeats, you can multiply the two additives with this number respectively, and then add the two products blindly, and the result remains the same.
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Negative and negative are positive, and the numerator and denominator are divided by 9 at the same time
The original formula is equal to 49 and 17 2
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49 and 1 11*1 6=(48+12 11)Sideside date*1 6=48*1 6+12 晌tease 11*1 6=8+2 11=8 and 2 2 11 11
Hello Lou Lou, I'm Shun Liang.
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