There are 20 apples and pears in the box, and there are 4 more apples than pears, so how many apples

Add 4 pears, on the one hand, there are as many apples as pears, and on the other hand, there are 20+4 apples and pears.

So at this time, there are 12 apples and 12 pears, minus 4 pears, so there are 12 apples and 8 pears in the box.

I've learned the one-dimensional equation.

This problem is solved using a one-dimensional equation.

The specific solution process is shown below.

Suppose: If there are x pears, then there are (x+4) apples.

There are a total of 20 apple pears, so.

x+(x+4)=20

2x+4=20

2x=16x=8

So, there are 12 apples and 8 pears.

There are 20 apples in total, 4 more apples than pears, first find out how many pears there are: (20-4) 2=8 (pcs); 20-8 = 12 apples.

If there are x pears, then the apples are x+4

x+(x+4)=20

2x=20-4=16

x = 8. 12 apples, 8 pears.

Solution: Pear: (20-4) 2=8 (pcs).

Apples: 20-8=12 (pcs).

A: There are 12 apples and 8 pears.

Suppose x = number of apples y = number of pears.

x+y=20

x-4=y2x-4=20

x=12 y=8

Answer: 12 apples, 8 pears.

There are 54 boxes of apples, and there are 19 boxes of pears than apples, so the pears are 54 + 19 = 73 boxes.

A: There are 73 boxes of pears.

There are a total of 41 boxes of pears and apples, and there are four apples and eight pears on the outside. How many are there at least? How many pears are there at most? How many are there at least?

Suppose there are x guess bases for mocking apples and y pears. From the meaning of the title: 1

x + y = 41 (total of 41 boxes)24x + 8y = with the highest total number of apples and pears, there is a maximum of 10 apples and a maximum of 31 pears. This is because if there are 11 or more apples, then there cannot be more than 30 pears, otherwise the total number of apples and pears will be more than 164 (41 boxes * 4 fruits), which contradicts the title.

In the least cases, there are at least 2 apples and 39 pears. This is because if there is only 1 or fewer apples, then the number of pears cannot be less than 40, otherwise the total number of apples and pears will be less than 44, which contradicts the title.

Summary. You can assume that there are x boxes of pears and 15 boxes of apples less than pears, that is, x=34+15=49, so there are 49 boxes of pears, I hope it can help you.

There are 34 boxes of apples, 15 boxes less than pears, and how many boxes of pears there are.

Hello, there are 49 boxes of pears.

You've done a great job! Can you elaborate on that?

You can assume that there are x boxes of pears and 15 boxes of apples less than pears, that is, x=34+15=49, so there are 49 boxes of pears, I hope it can help you.

18 pcs. Subtract the number of pears from apples, 42 apples, 24 pears, and subtract the two numbers slowly, 42-24 = 18, so there are 18 more apples than pears. A mathematical method of subtracting one number or quantity from another using subtraction, one of the four rules of mathematics.

Summary. This is a math problem done in the second grade of elementary school, and there are 24 apples in a box, which is 12 fewer than a box of pears.

This is a math problem done in the second grade of elementary school, and there are 24 apples in a box, which is 12 fewer than a box of pears.

Then there are 24 + 12 = 36 pears in a box.

This kind of question mainly analyzes who is more than whom and who is less than whom.

Summary. Answer.

Apple + pear = 48

Apple-pear = 12

There are a total of 48 apples and pears, 12 more apples than pears, how many apples and pears are there?

Answer: Apple + pear = 48 Apple - pear = 12

So apples = (48 + 12) 2 = 30.

Pears 48-30 = 18 pcs.

Summary. According to your question, there are already five pears, then there are a maximum of 12 pears and a minimum of one apple. Apples have up to eight.

There are a total of 13 apples and pears, 5 pears are known, ask how many pears there are at most, and how many apples there are at most.

According to your question, there are already five pears, then there are a maximum of 12 pears and a minimum of one apple. Apples have up to eight.

How to calculate. With what method.

Because it's said that there are both pears and apples, so it can't be both pears, so there is at least one apple.

There are a total of 13 apples and pears, and it is known that there are 5 pears, and there are a few pears at most, and apples at most.

According to your question, there are already five pears, then there are a maximum of 12 pears and a minimum of one apple. Apples have up to eight.

I've already done that.

Because it is said that there are both pears and apples, so it can't be all pears, so there is at least one apple when there is one apple to be filial, so there are 12 of them. That is, a maximum of 12 pears.

Because it is said that there are pears and apples, so it can't be all pears, so there is at least one apple when the apple has a spare chong, so there are 12 pears. That is, a maximum of 12 pears.

Because there are already five, 12-5=7, and apples are all up to seven.

Because there are already five pears, 12-5 = 7, and apples are all seven at most.

Summary. The number of pears is x the number of apples = 3x + 2 according to the conditions given in the question: 38 apples and pears in total

3x + 2 + x = 384x = 36x = 9 apples = 3x + 2 = 3*9 + 2 = 27 + 2 = 29.

There are 38 apples and pears in the box, of which the number of apples is more than 3 times that of pears and 2 pears.

The number of pears is x the number of apples = 3x + 2 according to the conditions given in the title: 38 apples and pear peels: 3x + 2 + x = 384x = 36x = 9 The number of apples = 3x + 2 = 3*9 + 2 = 27 + 2 = 29.

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Is there an easier way to solve the question for elementary school students?

Hello classmates, this kind of problem is a bad book, we can only set it to an unknown quantity to solve, if we rent Jinghong is our guess, it is difficult to guess, according to the manuscript list the corresponding formula, and then step by step to solve it.

Okay thank you. Because he has two unknown quantities, and gives us the corresponding multiple of the regret year, so it can be listed correspondingly, Fang Roll Cheng, this is a one-time time, the equation is the most basic, the most basic big front Ming problem Oh <>

Are we helping children with their homework?

Yes, in the tutoring homework.

As a result, I won't <> myself

Then it is suggested that we can choose a primary school homework tutor for our children, who will give our children questions and lectures.

In this way, it is also more convenient, let's tutor the child to pinch correctly.

Okay thank you. As long as our children don't know any questions, they can ask the teacher.

Can the teacher ask another question?

Yes.